@JS-M said:ohksssssssss.............bas maja aana chahiye
Game is Russian roulette 
@mickym said:Game is Russian roulette
...........raat ko khai nind me goli woli chal gayi to tier-2 nahi de payege@JS-M said:...........raat ko khai nind me goli woli chal gayi to tier-2 nahi de payege
lo ques karo issi bat pe The surface of a right circular cone is painted black. The cone has height 4 and its base has radius 3. It is cut into two parts by a plane parallel to the base, so that the volume of the top part (the small cone) divided by the volume of the bottom part (the frustrum) equals the painted area of the top part divided by the painted are of the bottom part. The height of the small cone is
@gsn said: @mickymyes....pls tell me how to solve it
Bro draw ABD equi trian such that it faces away frm C
I hope u can undrstnd the diag
Now draw DZ perpendiculr to AB this is altitude of equi trian ABD
u will get DZ = 15
join CD let it intrsct AB at O
let ZO= x , thn AO = 5rt3-x
also apply similar trian concept in thes triangles AOC & DOZ to find x
X will come 3rt3
apply pythagrs in
in ths triangles
to dind DO & CO
CD= DO + CO
@mickym said:lo ques karo issi bat peThe surface of a right circular cone is painted black. The cone has height 4 and its base has radius 3. It is cut into two parts by a plane parallel to the base, so that the volume of the top part (the small cone) divided by the volume of the bottom part (the frustrum) equals the painted area of the top part divided by the painted are of the bottom part. The height of the small cone is
yr h1 = 4-8/3 =4/3.................actually calculatn bahut ho gya tha, messed up ho raha hai....yr concept to shayad se simple hai, but calulation kafi tough....
yr ek baat batao.......CAT diya tha tumne ?? , kitna score kiya yr....,if u don't mind
@JS-M said:yr h1 = 4-8/3 =4/3.................actually calculatn bahut ho gya tha, messed up ho raha hai....yr concept to shayad se simple hai, but calulation kafi tough....yr ek baat batao.......CAT diya tha tumne ?? , kitna score kiya yr....,if u don't mind
diya nhn dena hai bro.........2012
@JS-M said:k.....to iska answer to bata do jate jate...
arre aapko aise hi bina bataye thode hi na chod ke chale jayenge bro
iska ans hai 5/2
aur ye lo SSC wala ques
A straight line // to base BC intersects AB & AC of trian ABC at D & E resp.
If the Area of train ABE be 36 sq cm then area of trian ACD
@mickym said:arre aapko aise hi bina bataye thode hi na chod ke chale jayenge broiska ans hai 5/2aur ye lo SSC wala quesA straight line // to base BC intersects AB & AC of trian ABC at D & E resp.If the Area of train ABE be 36 sq cm then area of trian ACD
yr dono equal hai ...........36sq com
one more 4 u
ABC is a triangle with sides AB = 4, BC = 5, and CA = 6. D and E are the foot of the altitudes from the vertices A and B to the respective opposite sides. What is the values of the ratio CD/CE?
@mickym said: one more 4 uABC is a triangle with sides AB = 4, BC = 5, and CA = 6. D and E are the foot of the altitudes from the vertices A and B to the respective opposite sides. What is the values of the ratio CD/CE?
5/6??
