@JS-M said:
ooppss.. it should be Neither the HM nor the Asst. Masters were present. 
@JS-M said: if x, y, z are real numbers such that x + y + z = 5 and xy + yz + zx = 3, what is the largest value x can take(a)5/3 (b)13/3 (c)19 (d) none of these
bhai iska methd share krna
@visitsameer said: When the Subjects joined by 'or/nor are of different numbers, the Verb must be Plural, and the Plural Subject must be placed next to the Verb.
duly corrected.. a sumptuous lunch can be such a distraction, bro 
@truly.gone said:bhai simply put value x 13/3 and y,z 1/3 ....dusre kisi values se equation match nehi ho raha
bhai ek option d bhi hai.........
@truly.gone said:bhai isiliye answer correct hain ya nehi puch liya tha
bro even if answer is correct here than too we cant take hit & try in cases of none of these too risky.......
@truly.gone said:bhai isiliye answer correct hain ya nehi puch liya tha
@visitsameer said:answer is d......square root of 19.....
@truely.gone see told ya......
@visitsameer bhai explain bhi kr do
@truly.gone said:bhai simply put value x 13/3 and y,z 1/3 ....dusre kisi values se equation match nehi ho raha
@watsnew24 said:bhai ek option d bhi hai.........
@truly.gone said:bhai isiliye answer correct hain ya nehi puch liya tha
@watsnew24 said:bro even if answer is correct here than too we cant take hit & try in cases of none of these too risky.......
@visitsameer said:answer is d......square root of 19.....
(x^2+y^2+z^2) =19
now for max x
y=z
2y+x=5..............(1)
2y^2+x^2 =19.........(2)
solve for x
@JS-M said: if x, y, z are real numbers such that x + y + z = 5 and xy + yz + zx = 3, what is the largest value x can take(a)5/3 (b)13/3 (c)19 (d) none of these
from 1, we can take a value for x+z = 5-y and substitute it in 2..
xz + y(5-y) = 3
now (x-z)^2 = (x+z)^2 - 4xz
replace the values for xz and x+z
RHS = (5-y)^2 - 4 ( 3-y(5-y))
= 25+y^2-10y - 12 +4y(5-y)
= 13+y^2+10y -4y^2
= -3y^2 +10y +13..
we know that the square of a number is always greater than or equal to zero
so (x-y)^2 > or = zero
ie 3y^2- 10y-13 3y^2 -13y+3y-39
xz + y(5-y) = 3
now (x-z)^2 = (x+z)^2 - 4xz
replace the values for xz and x+z
RHS = (5-y)^2 - 4 ( 3-y(5-y))
= 25+y^2-10y - 12 +4y(5-y)
= 13+y^2+10y -4y^2
= -3y^2 +10y +13..
we know that the square of a number is always greater than or equal to zero
so (x-y)^2 > or = zero
ie 3y^2- 10y-13 3y^2 -13y+3y-39
a big cube is formed by rearranging d 160 coloured and 56 non-coloured similar cubes in such a way dat d exposure of d coloured cubes to d outside is minimum.the percentage of exposed area tht is coloured is...
A.25.9%
b.44.44%
c.35%
d.none of these
A.25.9%
b.44.44%
c.35%
d.none of these
@JS-M said: a big cube is formed by rearranging d 160 coloured and 56 non-coloured similar cubes in such a way dat d exposure of d coloured cubes to d outside is minimum.the percentage of exposed area tht is coloured is...A.25.9%b.44.44%c.35%d.none of these
is it 44.44%? solution is a bit lengthy.. answer is wrong means, I can save the trouble
@JS-M said: a big cube is formed by rearranging d 160 coloured and 56 non-coloured similar cubes in such a way dat d exposure of d coloured cubes to d outside is minimum.the percentage of exposed area tht is coloured is...A.25.9%b.44.44%c.35%d.none of these
Is it d( i got answer as 48.148
I will post my solution. Since we have to find the minimum area, let the uncolored cubes be placed in the corners and edges (as three sides and two sides resp. are exposed in corner and edge cubes). so 8 corner cubes and 12X4 edge cubes = 8 + 48 =56
since there are a total of 216 cubes, it can be assumed that we have a 6X6X6 cube
Now, the exposed cubes will be colored. In each face, 4X4 units of exposed area will be there. that means, 16 units in each of the six faces, amounting to 96 units.
Percentage of exposed area is 96 / 216 = 44.444% (approx)
@viksg said: Find the error..(A) He left for Mumbai on Sunday/ (B) arriving there/ (C) on Monday./(D)No error.
arrived
@sumit1234567890 said: a right circular cylinder of height 16cm is covered by a rectangular tin foil of size 16*22 cm . find the volume of the cylinder.
616
@sumit1234567890 said: the ratio of area of a sector of a circle to the area of a circle is 1:4 if the area of circle is 154cm^2 the perimeter of the sector is .. ???
7pi/2+14
puys pls solve n giv explan..
X= r sinA cosC ,Y=r sinA sinC ,Z=r cosA find the value of X^2+Y^2+Z^2=...?
opt (1-r^2)/r^2/1+r^2/1
@sandy73 said: Excluding stoppages, the speed of a bus is 54kmph and including stoppages it is 45kmph. For how many minutes does the bus stop per hour?a) 9 b) 10 c) 12 d) 20
10