CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
1005
@cbiofficer said:
x y kya h isme
x= speed of boat+water
y=speed of boat - water
1006
@sumit1234567890 40
1007
@mickym said:
Bro iska shrtcut ye hai
Assume 1/b-s = X
& 1/ b+s = Y
Now solve the eqns for X n Y
1008
@mickym said: @Brooklyn
Bro u posted a ques
MAx & min
Sin^3A+ Cos^3A
MAx= 1
Min= 1/rt2
Plz chk
explain???
1009
@rameshvvv kiska ans hai ye??
1010
@truly.gone said:
@Simpatic0
@mrudalmodi
@VK_Shukla
@sumit1234567890
@cbiofficer bhai log ek query hain......JSM and samprass abhi bhi zinda hain kya??? yaa bhagwan ko pyaare ho gaye ????
kal tk zinda the bhai..aaj ka kuch keh nai skta
1011
@truly.gone lagta hai secret study ho raha hai unki
1012

At a point on a horizontal line through the base of a monument, the angle of elevation of the top of the monument is found to be such that its tangent is 1/5.on walking 138meter towards the monument the secant of the angle of elevation is found to be rt193/12. height of the monument?

1013

hi friends..pls help me solve this problem..


A Triangle ABC is drawn to circumscribe a circle of radius 4cm such that segments BD and DC into which BC is divided by point of contact D are of lengths 8cm and 6cm respectively.find sides AB and AC.
Thanks in advance.
1014
@sumit1234567890 x3-6x2+18x+18 its answer is 40
right????
1015
@sscjindabad said:
Bhai how did u find the factors i e 1,3, 5, 15,17, 51,....255???
bro, factorize 255... including 1 and 255..
1016
@mickym said:
48510
explain bhai....
1017
@sandeepv882 40??
1018
@mickym said:
1/3 pi ( 28 * 28 * 60 - 7 * 7 * 15)
bhai from where did u get 60 and 15 in the equation????
1019
@rahul09061989 i don't know the ans ..i askes vikas to solve this..if u got it pls explain...
1020
@rahul09061989 said:
@sandeepv882 40??
ha bhai 40 hi answer hai ........explain plz
1022
@truly.gone said:
42
bhai explain plz......aaj pta nhi kya ho rha hai questions hi solve nhi ho rhe hai
1023
@truly.gone bhai i m getting 30 ?? can u pls explain??
1024
@sumit1234567890 said:
@VK_Shukla x=2-(2^1/3)+(2^2/3)......find value of x^3-6x^2+18x+18=?
ye solve karna yaar
x-2=-2^1/3+2^2/3
(x-2)^3=(-2^1/3+2^2/3)^3
x^3-8-6x(x-2)=-2+4-6(-2^1/3+2^2/3)
x^3-8-6x^2+12x=2-6(x-2)
x^3-6x^2+18x-8=14
x^3-6x^2+18x+18=40
1025
@VK_Shukla thanks yaar..