CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
901
@sumit1234567890 d.
902
@snkr87 4
903
@snkr87 said: The sum of a pair of positive integers is 336 and their HCF is 21.. The no.of such possible pair is..?
opt 2/3/4/5
4
904
@snkr87 said: The sum of a pair of positive integers is 336 and their HCF is 21.. The no.of such possible pair is..?
opt 2/3/4/5
2 ??
905
@snkr87 said: The sum of a pair of positive integers is 336 and their HCF is 21.. The no.of such possible pair is..?
opt 2/3/4/5
ans is 4
906
@sumit1234567890 16
907
@sumit1234567890 said:
When two numbers are separately divided
by 33, the remainders are 21 and 28
respectively. If the sum of the two numbers
is divided by 33, the remainder will be
(a) 10 (b) 12
(c) 14 (d) 16
16
908
@rahul09061989 said:
@snkr87 4
xplain it bro

909
@sumit1234567890 said:
When two numbers are separately divided
by 33, the remainders are 21 and 28
respectively. If the sum of the two numbers
is divided by 33, the remainder will be
(a) 10 (b) 12
(c) 14 (d) 16
16
910
@snkr87 said: The sum of a pair of positive integers is 336 and their HCF is 21.. The no.of such possible pair is..?
opt 2/3/4/5
1,15
3,13
5,11
7,9
911

16 is the correct ans..

912
@mickym said:
16
pls giv xplan..

913
@007pagal said:
2 ??

4 it is
914
@mickym said:
400 %
explain karo??
915
@007pagal said:
1:rt2 ??
explain karo yaar!!
916
@snkr87 said:
ans is 4
@snkr87 hw 4..mera to 5 aa raha hai???
917
@snkr87 said:
pls giv xplan..
N1= 33x1+ 21
N2 = 33 x2 + 28

N1+N2 = 33(x1+x2) + 49

so rem = 49-33= 16
918
@anurag1701 5 nai hai kya?
919

@cbiofficer said:
bhai i can not get dis..


920

@snkr87 suppose nos are 21x and 21y

dn x+y=16

nw ve hv to make combinations in such a way so dat hcf of x and y remains 1

dese will b

1,15 3,13 5,11 7,9