CGL 2012 Tier 2 Preparations and Results

@007pagal said:
wrng
@mickym said:
gud Nite
Bhai hume toh koi gudnyt ka reply nahi karta nahi hi gud morning ka...Lagta hain female profile bananni padegi....kya keheto ho sampras n truly bhai...
@snkr87 said: the diff b/w Exter.angl & Inter.angl at a vertex of a reg.polygon is 150 deg. Then the no.of sides of polygon..?
opt 10/15/24/30
24
@snkr87 said: the diff b/w Exter.angl & Inter.angl at a vertex of a reg.polygon is 150 deg. Then the no.of sides of polygon..?
opt 10/15/24/30
24
@visitsameer said:
After the elections, a firm conducted exit polls. Exactly 2% of the male voters said they had voted for candidate A, while exactly 59% of the female voters said they had voted for candidate A. If in total, exactly 17% of the people said they had voted for the Candidate. What is the minimum number of people who were surveyed?
OPTIONS
1) 17
2) 19
3) 323
4) 1700
5) 1900
the answer is 1900....male to female ratio comes out to be 14:5
How did u find the ration yaar....14:5???
@cbiofficer said:
24
broth i tried with d formulae inter.ang=180-exter.angl and n=360/exter angl
bt nt getting answr..correct me if i m wrng...

@sscjindabad said:
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@snkr87 said:
broth i tried with d formulae inter.ang=180-exter.angl and n=360/exter angl
bt nt getting answr..correct me if i m wrng...
bro chk ques 1ce again..d it wud b internal - external
@snkr87 said:
broth i tried with d formulae inter.ang=180-exter.angl and n=360/exter angl
bt nt getting answr..correct me if i m wrng...
take exter angle = 15
@cbiofficer said:
wrng
396??
@007pagal said:
@cbiofficer said:
bro chk ques 1ce again..d it wud b internal - external
s..qn might be wrngly printed...dis qn frm CHSL 2011 paper..

@mickym said:
take exter angle = 15
s got it bro..
@Brooklyn
Bro u posted a ques
MAx & min
Sin^3A+ Cos^3A

MAx= 1

Min= 1/rt2
Plz chk


@visitsameer said: the answer is a....1/2 solved thru options......
explain...Mine is coming as 1...
@mickym said: @Brooklyn
Bro u posted a ques
MAx & min
Sin^3A+ Cos^3A
MAx= 1
Min= 1/rt2
Plz chk
method
@gudboy said:
divide both the side by cos^2x, 2 sec^2x-1 =3 sinx/cosx, 2(1+tan^2x) - 1 =3 tan^2x 2 + 2tan^2x -1 = 3 tan^2x. solve the quad ............
Bhai how did u get 3 tan^x in the RHS as by dividing yields 3 tan x only...

X+1/X=2 and X is real no

x^17+1/X^19 is....? opt 1/0/2/-2
@mickym said: @Brooklyn
Bro u posted a ques
MAx & min
Sin^3A+ Cos^3A
MAx= 1
Min= 1/rt2
Plz chk
correct
@Brooklyn said:
method
Bro i hav just put random values of A

Say at A= 90 or either 0 the exp will be 1

At sin A= Cos A= 1/rt2, A= 45

The exp = 1/rt2 MIN
Now whther u go above 45 or below it the value is gonna increase