@cbiofficer said: ABCD is parallelogram P Q R S are mid pints on AB BC CD AD respect...find PQ+QR+RS+SP
AC+BD
speed 20kmph
speed increases by 4kmph aftr evry 15min
find distance covered in 6hours
bhai ab tum b do kuch ques
@cbiofficer said: speed of A to B=33.3 kmphspeed of B to C = 50kmphspeed of C to A = 55 kmphfind average speed?
how r thes ratios even possible??
a/b* b/c * c/a =1
whhich is not in this case
@mickym said:how r thes ratios even possible??a/b* b/c * c/a =1whhich is not in this case
iska ans btau kya
@cbiofficer said: speed 20kmphspeed increases by 4kmph aftr evry 15minfind distance covered in 6hours
9th class ka formula hai
S= ut+1/2 at^2
ans 408
@ansh099 said: cbiofficer 2(x*y)/x+y.......eq1 .... (x=33.3 y = 50) we obtain avg speed of first two then result of this will again go in above formula ..where x will be the resultant and y be = 55
wrng..ans is data insufficient
@mickym said: sin # - cos # = 7/13find sin # + cos #if 0@mickym said: tan 2# tan 4# = 1 find tan3#how to solve these??!
@ansh099 said: cbiofficer 2(x*y)/x+y.......eq1 .... (x=33.3 y = 50) we obtain avg speed of first two then result of this will again go in above formula ..where x will be the resultant and y be = 55
bro here it nt givn dat distance is same..2xy/x+y is in d case of same distance