CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
5242
@watsnew24 said: hey anybody here who gave todays examhow was it....... tough or comparitively easy....????
vry easy..bt maths ws lil bit tough
5243

Ojas public school

sec 17 rohini
5244
@cbiofficer said:
bhai mera rohini pda h..mai apko bta rha tha kaise pahochoge aap apne centre
bhai abhi dekh kar aaya Center
:) Ghar k pass hi hai
5245
@cbiofficer said:
bhai mera rohini pda h..mai apko bta rha tha kaise pahochoge aap apne centre
bhai abhi dekh kar aaya Center
:) Ghar k pass hi hai
5246
@cbiofficer said: Ojas public school
sec 17 rohini
bhai mera bhi same hai......
5247

guys


between our first name and surname can we leave one letter gap???

i didnt during tier1
5248
@sanju2012 said: guys
between our first name and surname can we leave one letter gap???
i didnt during tier1
yeah its required also.... keep full column empty
5249
@gudda1122 said:
bhai abhi dekh kar aaya Center
Ghar k pass hi hai
bhai secluded place h kaafi
5250

all the centre are secluded...


my centre's name no one knew...it was an adventure finding it..

not on google map too
5251

anybody has the center Govt. Boys Sr. Sec School Vikaspuri?????

5252

mujhe pata he bhaiyon ye last minute me relax hona mangta...lekin cant resist to ask my doubts...ye theen question mere dimag kha rahe he....mummyyyyyyyyy bachao..

1.pathakrahul bhai posted this

how to convert 22degree 20minute 40 seconds into radians

2.wt is d value of (1+sec 20 + cot70 ) (1-sec20 +tan 70)

options -1,2,1,0

3. If xsin^3 A + y cos^3 A=sin A cos A not equal to 0
and x sin A-y cos A=0
find x^2+y^2

options
sinA-cosA
sinA+cosA
1
0

........
PS: If these were answered before pls take d pain to post page no.

5253

sampras ne pg-266, reply # 5309 mein detail mein likha hi hai, usko short mein dimag mein bithayein to wo hai ->

remain Calm, Cool and Confident during the exams

Believe in your preparation
..and assure that you use your knowledge in all the places where it can be applied by working out all the easier questions first

If by chance you start feeling panicked, close your eyes for a few seconds, remember these words in bold and exhale all your tension away..


5254
@VENRAG said: mujhe pata he bhaiyon ye last minute me relax hona mangta...lekin cant resist to ask my doubts...ye theen question mere dimag kha rahe he....mummyyyyyyyyy bachao..1.pathakrahul bhai posted thishow to convert 22degree 20minute 40 seconds into radians
Bhai here are the soln n approach

1.use 60 deg = 1' and 60" = 1' and pi rad = 180 deg
so converting all to degrees :
22+20/60 + 40/3600 = 2011/90
now 180 deg = pi radians
so (2011/90) deg = (2011/90)*pi/180 .... radians
5255
@VENRAG said: mujhe pata he bhaiyon ye last minute me relax hona mangta...lekin cant resist to ask my doubts...ye theen question mere dimag kha rahe he....mummyyyyyyyyy bachao..2.wt is d value of (1+sec 20 + cot70 ) (1-sec20 +tan 70)options -1,2,1,0
chk second one the second multiplicand should have cot70
5256
@VENRAG said: mujhe pata he bhaiyon ye last minute me relax hona mangta...lekin cant resist to ask my doubts...ye theen question mere dimag kha rahe he....mummyyyyyyyyy bachao..3. If xsin^3 A + y cos^3 A=sin A cos A not equal to 0 and x sin A-y cos A=0 find x^2+y^2options sinA-cosA sinA+cosA 1 0........ PS: If these were answered before pls take d pain to post page no.
Sol3. tanA= y/x .... sinA = y/rt(x^2+y^2) and cosA= x/rt(x^2+y^2)

the given eqn reduces to ....
x sinA tanA + y cosA cotA = 1..... use above values and solve algebtraically

will get rt(x^2+y^2) = 1.... so x^2+y^2=1........... Ans
5257
@sampras , @gudda1122 n other Puys:

Good nyt ppl....cu tomm evng here after xam... Best of luck to all :)
__/\___

Jai mata di lets rock 😉
5258
@Brooklyn said:
@sampras , @gudda1122 n other Puys:
Good nyt ppl....cu tomm evng here after xam... Best of luck to all
__/\___
Jai mata di lets rock
very good night bhai phod ke aana...I have much expectations from you...
jai mata di ____/\___
5259
@sampras said:
very good night bhai phod ke aana...have much expectations from you...
@Brooklyn said:
@sampras , @gudda1122 n other Puys:
Good nyt ppl....cu tomm evng here after xam... Best of luck to all
__/\___
Jai mata di lets rock
Gud ngt bhai
Try to give your best
baki dekh lenge yaar
_____/\_____

"kahe do is aasama se Agar dekhni hai hamari udhaan toh khud ko thoda aur Upar kar le"
5260
@gudda1122 said:
Gud ngt bhai
Try to give your best
baki dekh lenge yaar
_____/\_____
"kahe do is aasama se Agar dekhni hai hamari udhaan toh khud ko thoda aur Upar kar le"
kya baat hai sardaar... IRSHAAD.. ___/\___ .... Ek aur bhai mere taraf se bhi before I sign off for the day...

Parindo Ko Nahi Di Jaati Talim Udaano Ki,
Wo khud Hi Tay Karte Hai Manjil Aasmaano Ki,
Rakhte Hain Jo Hausla, Aasman Ko Chhune ka,
Unko Nahi Hoti Parwah Gir Jaane Ki...................

...........see you all tomorrow...Good Night Shabba Khair
5261
@sampras said:
Sol3. tanA= y/x .... sinA = y/rt(x^2+y^2) and cosA= x/rt(x^2+y^2)
the given eqn reduces to ....
x sinA tanA + y cosA cotA = 1..... use above values and solve algebtraically
will get rt(x^2+y^2) = 1.... so x^2+y^2=1........... Ans
@sampras said:
chk second one the second multiplicand should have cot70
@sampras said:
Bhai here are the soln n approach
1.use 60 deg = 1' and 60" = 1' and pi rad = 180 deg
so converting all to degrees :
22+20/60 + 40/3600 = 2011/90
now 180 deg = pi radians
so (2011/90) deg = (2011/90)*pi/180 .... radians
jeethe raho mere bhai................khoob khushi hui solutions aapse sunke...wt a day to end before th D day....

all the best..zarror phod ke aana..aap kabhil ho aur aappe hamare umeed bhi..


.......ALL THE PUYS ..........goooooooooooooooooooood night

all the best..phir milenge...

LOVE

venrag