@sameer90sharma said: does anyone have 'uttam nagar' as their centre for tommorow ??
@gudda1122 ji ka hai
btw GM to all puys __/\__
Kaha hai sab log???
good morning bhai log....
@sampras said: Q. In a tri ABC ang BAC = ABC = 80 deg and D is any point on BC such that ang ADB = 30 deg then AB/DC = ?
bhai ye question explain karke batado....samajh nahi aaya.... sin formulas use karke bhi....koi explaination bata do
@sampras said: Q. In a tri ABC ang BAC = ABC = 80 deg and D is any point on BC such that ang ADB = 30 deg then AB/DC = ?
bhai ye question explain karke batado....samajh nahi aaya.... sin formulas use karke bhi....koi explaination bata do
@sumit1234567890
@alkoszzz said:bhai ye question explain karke batado....samajh nahi aaya.... sin formulas use karke bhi....koi explaination bata do
apply sine rule in both triangle ABD and traiangle ADC , to get ratio of AB/DC which you would get as (sin20 * sin30 ) / (sin80 * sin 10) which can be simplified to be 1
@alkoszzz said: @harsh1839 yaar yahi solve nahi ho ra....maine kabhi nahi kiya....sin * cosec lana hai kya???
convert sin20 to 2sin10cos10 , sin30 we already know cos 10 is same as sin 80 so everythng gets cancelled
@sumit1234567890 c i have reached here (sin20 * sin30 ) / (sin80 * sin 10) but i dnt know wat to do next??
ty both of u 😁
@alkoszzz said:bhai ye question explain karke batado....samajh nahi aaya.... sin formulas use karke bhi....koi explaination bata do
what are the options???
@alkoszzz said: @viksg mera answer to ab/dc=2/1 aa ra hai
answer is 1 , check ur calculation after what i have told u to simplify
@alkoszzz Equal Annual Instalment under CI , x= Pr/100*[1-(100/100+r)^n]
or is it (100p)/(100t+(rt(t-1))/2)
or is it (100p)/(100t+(rt(t-1))/2)