@cbiofficer said: i asked him how could he go out if it started raining/no erorfind error
I asked him how could he go out if it rains.
@sampras said: Q. In a tri ABC ang BAC = ABC = 80 deg and D is any point on BC such that ang ADC = 30 deg then AB/DC = ?
bhai nai hua..btana iska
@sumit1234567890 said:bhai ye phele bhi diya tha nai aaya tha..ans explain kar do iska plz//
use sine laws will get AB=DC...Ans 1:1 ....
approach : ang DAB= 70 ... ang ADC =150 ....so ang ACB=20deg
@sampras said:use sine laws will get AB=DC...Ans 1:1 ....approach : ang DAB= 70 ... ang ADC =150 ....so ang ACB=20deg
bro bt u said dat ADC=30
Q. If x/(b-c)(b+c-2a) = y/(c-a)(c+a-2b) = z/(a-b)(a+b-2c) then the value of x+y+z :
@sampras said: Q. In a tri ABC ang BAC = ABC = 80 deg and D is any point on BC such that ang ADB = 30 deg then AB/DC = ?
Edited pls see ang ADB in place of ang ADC earlier ...
@sampras said: Q. If x/(b-c)(b+c-2a) = y/(c-a)(c+a-2b) = z/(a-b)(a+b-2c) then the value of x+y+z :
bhai most of d tym iska ans 0 hota h...wild guess
@sampras said: Q. If x/(b-c)(b+c-2a) = y/(c-a)(c+a-2b) = z/(a-b)(a+b-2c) then the value of x+y+z :
00
x^2-3x+1=0
find value of x^3+1/x^3
@cbiofficer said:bhai most of d tym iska ans 0 hota h...wild guess
ha ha ha bro even night is getting wild .... CORRECT Officer
@harshgupta88 said: x^2-3x+1=0 find value of x^3+1/x^3
x(x-3+1/x) = 0
=> x+1/x =3... so x^3+1/x^3 = (x+1/x)^3 -3(x+1/x) = 27-9 = 18 ... Ans
@harshgupta88 said:solution de do pls...mai isme bada kamjor hu
bhai equ ko x s divide krdo
den u get x + 1/x = 3
den cubing both side u wil get d ans
@harshgupta88 said: x^2-3x+1=0 find value of x^3+1/x^3
yaar pen paper nahi hai paas mein ... bed pe lete lete... type karke solve kiya hai... chk if correct..