@007pagal said:
repeated so many times here.... a=1, b=-1 and c=-1.... after rearranging...
(a-1)^2+(b+1)^2+(c+1)^2=0 .... so ans...1
@sampras said:repeated so many times here.... a=1, b=-1 and c=-1.... after rearranging...(a-1)^2+(b+1)^2+(c+1)^2=0 .... so ans...1
sahi kaha
chalo ab back to questions
kuch aur post karo yaar
ALL folks keep on posting questions :)
A jar contained a mixture of two liquids A and B in the ratio 4:1. When 10 litres of the mixture was taken out and 10 litres of liquid of B was poured into the jar. this ratio became 2:3 The quantity of liquid A contained in the jar initially was
a 4 lt
b 8l t
c 16 lt
d 40 lt
a 4 lt
b 8l t
c 16 lt
d 40 lt
Dear all, small recap of trigonometry... as I see most of the times direct qns are asked either on finding Circum radius or inradius...
There are quite a few formulas dealing with triangles. Here are some. R is the circumradius, r is the inradius, h is a height, p is the perimeter (a+b+c), s is the semi-perimeter (a+b+c)/2, and sqr() is the square root function.
Area=ah/2 [h=height perpendicular to a]
Area=sqr(s(s-a)(s-b)(s-c)) [Hero's Formula]
Area=sqr((a+b+c)(-a+b+c)(a-b+c)(a+b-c))/4
Area=sqr(p(p-2a)(p-2b)(p-2c))/4
Area=2R^2sinA sinB sinC
Area=abc/4R
Area=rs
Area=(bc sinA)/2
Area=(a^2 sinB sinC)/(2sinA)
CotA=(a^2+b^2+c^2)/4area
c^2=a^2+b^2-2ab cosC [Law of Cosines]
a/sinA=b/sinB=c/sinC=2R [Law of Sines]
(a-b)/(a+b)=tan((A-B)/2)/tan((A+B)/2) [Law of Tangents]
@gudda1122 said: A jar contained a mixture of two liquids A and B in the ratio 4:1. When 10 litres of the mixture was taken out and 10 litres of liquid of B was poured into the jar. this ratio became 2:3 The quantity of liquid A contained in the jar initially wasa 4 ltb 8l tc 16 ltd 40 lt
C.16 lt
sorry pus editing the qn here is the modified one.......
if (cos^4 alpha/cos^2 beta) + ( sin^4 alpha / sin^2 beta) = 1
then (cos^4 beta+cos^2 alpha ) + ( sin^4 beta + sin^2 alpha ) = ?
a=3+2rt2
then find
(a^6+a^4+a^2+1)/a^3
@pathakrahul said: if (cos^4 alpha/cos^2 beta) + ( sin^4 alpha + sin^2 beta) = 1then (cos^4 beta+cos^2 alpha ) +( sin^4 beta + sin^2 alpha ) = ?
yaar upar + ki jagah / hai kya ? kindly check the question...
16ltr
16ltr
€Ž57^25-1 Digit @Unit place will be..?
sec@ + tan@ =2 then sec@ ?
a) 5/2 b)5/4 c) 7/4 d) 7/2
a) 5/2 b)5/4 c) 7/4 d) 7/2
In a fleet of a certain car-renting agency the ratio of the number of sedans to the number of hatchbacks was 9:8. If after the addition of 3 sedans and 1 hatchback, this ratio rose to 6:5, how many more sedans than hatchbacks does the agency have now?
(A) 2
(B) 3
(C) 5
(D) 7
(E) 9
(A) 2
(B) 3
(C) 5
(D) 7
(E) 9
@gudda1122 said: A jar contained a mixture of two liquids A and B in the ratio 4:1. When 10 litres of the mixture was taken out and 10 litres of liquid of B was poured into the jar. this ratio became 2:3 The quantity of liquid A contained in the jar initially wasa 4 ltb 8l tc 16 ltd 40 lt
Let the quantities of A & B in the original mixture be 4x and x litres.
Then we have...4x/x+10 = 2/3 .... x=2 so ans ... 4x=8
Removal and Replacement theory :
If a vessel contains “x” litres of milk and if “y” litres be withdrawn and
replaced by water, then if “y” litres of the mixture be withdrawn and
replaced by water, and the operation repeated 'n' times in all, then :
(Milk left in vessel after nth operation)/ (Initial quantity of Milk in Vessel)
= [(x-y)/x]^n = [1-y/x]^n
If y be real the min. Value of -> 4 y^2 + 4 y + 9 ?
kaha gaye sab??????/
@gudda1122 said: €Ž57^25-1 Digit @Unit place will be..?
6