CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
3484
@sanju2012 said:
@micky0007
let radius of circle be a,b,c in increasing order then;
pie a^2 = pie( b^2-a^2)
2 a^2 = b^2;------(1)
pie ( c^2 -b^2) = pie ( b^2 - a^2)
a^2 + c^2 = 2 b^2;------(2)
sub (1) in(2); also c=8 given
a^2 + 64 = 4 a^2
a=8/rt3; sub in (1)
b=(rt2 * 8)/rt3;
c=8;
88/rt3)rt2*8)/rt3= 1:rt2:rt3
thank you boss
3485
@sanju2012 said:
@micky0007
let radius of circle be a,b,c in increasing order then;
pie a^2 = pie( b^2-a^2)
2 a^2 = b^2;------(1)
pie ( c^2 -b^2) = pie ( b^2 - a^2)
a^2 + c^2 = 2 b^2;------(2)
sub (1) in(2); also c=8 given
a^2 + 64 = 4 a^2
a=8/rt3; sub in (1)
b=(rt2 * 8)/rt3;
c=8;
8;(8/rt3);(rt2*8)/rt3= 1:rt2:rt3
ditto........
3486
@JS-M said:
1.2 m.......z d answer
x/(4.8+x) = .9/3.6
x= 1.6 (sry)
how how???? im getting 1.6m...are u getting tan(theta)=3/4??
3487
@sandeepv882 said:
gud evng bhai....movie dekhte hai ab.....
kon si wali dost??
3488
@anurag1701 said: Q.A solid is hemispherical at the bottom and conical above.If the surface areas of two parts are equal,then ratio of radius and ht of its conical part a.1:3 b.1:1 c.3^2:1 d.1:3^2 ??
yaar mera toh ajeeb sa hi answer aa rha h

1: (3)^1/2
3489

in problems related to finding diameter no need to solve....


in options one will be double the other..the doubled value is diameter..


3490
@gudda1122 said: A semi circular sheeet of metal of diamtr 28cm is bent into an open conical cup.The depth of d cup is approx-11 12 13
yaar koi yeh wala solve karna

+yeh batana what does surface area means??//

is it total surface area or curved surface area????????
3491
@anurag1701 said: Q.A solid is hemispherical at the bottom and conical above.If the surface areas of two parts are equal,then ratio of radius and ht of its conical part a.1:3 b.1:1 c.3^2:1 d.1:3^2 ??
none of these.. I m getting 1: 3^0.5
3492
@gudda1122
@Vineeth555 U both r correct..Optn is 1:(3)^1/2...My bad

method plzz ??
3493
@alkoszzz said:
how how???? im getting 1.6m...are u getting tan(theta)=3/4??
yr 1.6 m hi to likha hai maine......
3494
@anurag1701 1:1
3495

simple.. I took Total Surface area and radius became 0..
then on equating CSA and surface area of hemi sphere, we get,
slant height of cone in terms of radius
PS: too lazy to copy paste pie.. thats why i m nt including any equations

3496
@anurag1701 said:
@gudda1122
@Vineeth555 U both r correct..Optn is 13)^1/2...My badmethod plzz ??
TSA of sphere=3*pi*r^2-----------1
TSA of cone=pi*r*(r+x)--------------2
r will common for both
x=slant height
x^2=h^2+r^2

equate both the equations
(r/x)=(1/2)-------3

now just square equ 3 put value of x you will get the answer
3497
@sanju2012 said:
@anurag1701 1:1
@sanju2012 its 1:3^0.5
3498

@anurag1701 2*pie*r^2 = pie * r *l .........where l=rt (h^2 + r^2)
2*r = rt(h^2+r^2);

square on bs

4r^2-r^2=h^2

rt3r=h

r/h=1/rt3

3499
@gudda1122 said:
yaar koi yeh wala solve karna
+yeh batana what does surface area means??//
is it total surface area or curved surface area????????
yr jab tak questn me TOTAL word use na ho......to avoid TSA.....basically its for open figures.
ya phir kabhi paint waint karna ho to
3500
@gudda1122 said:
TSA of sphere=3*pi*r^2-----------1
TSA of cone=pi*r*(r+x)--------------2
r will common for both
x=slant height
x^2=h^2+r^2
equate both the equations
(r/x)=(1/2)-------3
now just square equ 3 put value of x you will get the answer
total surface liya h tumne
main curved liya tha ans same aaya
3501
@sumitrewri said:
total surface liya h tumne main curved liya tha ans same aaya
haan yr same hi ayega.......dono ka base same hai na
3502
The volume of a cube, whose diagonal measures 4 ˆš3 cm is ?
3503
@JS-M said: The volume of a cube, whose diagonal measures 4 ˆš3 cm is ?
64???/