@VENRAG said:a bike costs 5000. a client purchased it by paying Rs 2060 cash and promised to return the rest amount in 3 yearsat 4 p.c. p.a. compounded annually .what should be the installment 1059 1061 1074 989
A is the answer?
rt90 = +3rt10 or both + and - 3rt10
@VENRAG said:sol bro...thnx
Yaar this is one of the rare type of question for which i have mugged up formula...
Let x be the installments paid
Then
((x)/(1+r/100)^n)+((x)/(1+r/100)^n-1)+........+x/(1+r/100)=Amount Payable
Here 'r' is rate of interest and 'n' is time in years
Problem is Calculations become really cumbersome....
a-b=3,b-c=5,c-a=1 than value of
(a^3+b^3+c^3-3abc)/a+b+c
@sumitrewri said:what is rt90 puch raha hu
is both + - 3rt10
bt if q varibale can only b +ve or -ve den it will change accoridngly
let say q had log(x) blah blah
n u found x=rt 90
here x will 3rt10 as log of -ve no doesnt exist
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[image was removed because it was too large]
@sumitrewri said:a-b=3,b-c=5,c-a=1 than value of(a^3+b^3+c^3-3abc)/a+b+c
Their is some problem in question
a-b=3------eq1
b-c=5-------eq2
c-a=1-------eq3
if we add 1 nd 2
a-c=8
but eqn 3 says
a-c=-1
Ambiguous???
@anubhav2011 said:
a^2 + b^2 + c^2 = 2(a – b – c) – 3
=> a^2 + b^2 + c^2-2a+2b+2c+3=0
=> (a^2-2a+1)+(b^2+2b+1)+(c^2+2c+1)=0
Now the term in bracket can be converted to whole squares as follows
(a-1)^2+(b+1)^2+(c+1)^2=0
Now since we have square term in the expression so for the expression
to be 0 all the term should be seperately equal to 0
i.e. a-1=0,b+1=0,c+1=0
=> a=1,b= -1,c=-1
so a-b+c=1 and hence the ans
Feeling alot of pressure bhai logo..Jst 2 days for xam. 
@watsnew24 said:Simple intrest waale ka answer B hai kyaI am getting approx answer
yes b is correct but approx nhi exact aayega bhai......