x = cos^4 + 1-cos^2 = 1-cos^2+cos^4=1-cos^2(1-cos^2)=1-cos^2*sin^2
x=1-sqr(sin2y)/4; x will be max when sin2y=0=>xmax = 1;
x will be min when sin2y=1;xmin=1-1/4 = 3/4
So,range is [3/4,1]
BBi ppl , gud nyt!! mai chala sone 
@Brooklyn said: BBi ppl , gud nyt!! mai chala sonejagane walle jate raho "mg:

@lalit5800 said: @JS-M ....BRO IF SIN2Y=-1 HOGA THEN SQURE OF -1 TO 1 HO JAYEGA NA.......THRFR SIN2Y=0
Sorry bhai logo for this abrupt post....But I haven't studied trigonometry...if someone can just elaborate ki kaha se padh lu....and kya kya padh lu :)
Thanks in advance 😃
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