yaar abhi apne doubt rakh lo baad mein ek saath clear karte h
main question dalta hu solve karte h saath saath
are u ready
@watsnew24 said:0cube on both side& derive the equation by taking x^6 common
bhai thoda method aur explain karna
@sumitrewri said: yaar abhi apne doubt rakh lo baad mein ek saath clear karte hmain question dalta hu solve karte h saath saathare u ready
yup pretty much aane do
@gudda1122 said:root questionb???//not sureany one please method batana
factorize taking x^6 common also calculate x^6+1/x^6 ...
@gudda1122 said:bhai thoda method aur explain karnayup pretty much aane do
bhai cube kar lo x^3 + 1/x^3 = 0 ho jayega
uske baad given equation ko factorize karo to (x^12+1) & (x^6+1) ayega
x^6 + 1 = x^3(x^3 + 1/x^3) ho jayega
so whole thing will become zero
uske baad given equation ko factorize karo to (x^12+1) & (x^6+1) ayega
x^6 + 1 = x^3(x^3 + 1/x^3) ho jayega
so whole thing will become zero
@sumitrewri said:
1) 0
the exp is (X^15 +X^3) ( x^3+1/X^3)
now x^3+1/X^3 = 0
on cubing u will get this
@mickym said:1) 0the exp is (X^15 +X^3) ( x^3+1/X^3)now x^3+1/X^3 = 0on cubing u will get this
bhai d uppar wale q ka kah raha hu
@sampras said:factorize taking x^6 common also calculate x^6+1/x^6 ...
even calculating (x^3+1/x^3) will do ... coming as zero...
see :
x^18+x^12+x^6+1 = x^12(x^6+1) +1(x^6+1)....
(x^12+1)(x^6+1) .... (x^12+1)*x^3*(x^3+1/x^3) = 0
@sumitrewri said: any short cut for t
ab/a+b
a/x-b/x = (x-b-x-a)/(rt(x-a)(x-b)
=> x^2=(x-a)(x-b)
=> x= ab/a+b
@sumitrewri said:
its 960 ...initial let boys 5y and 3y... new admission 5x and 7x
eqns... (5x+5y)+(7x+3y) = 1200 and (5x+5y)/(3y+7x) = 7/5 .... solve
....kaha se start karu
, yr kal se try kar raha hu smiley bada nahi ho raha @mickym said:ab/a+ba/x-b/x = (x-b-x-a)/(rt(x-a)(x-b)=> x^2=(x-a)(x-b)=> x= ab/a+b
@sumitrewri said:
Bhai 960
Let boys 5x Gals 3x
new boyz 5y galz 7y
8x+12y=1200.........1st
also (5x+5y)/(3x+7y) = 7/5
=> x= 6y
hence put this in 1st
y=20
x= 120
total 8*120= 960
@JS-M said: ....kaha se start karu, yr kal se try kar raha hu smiley bada nahi ho raha
bhai go straight way adding taking root wala fractions on one side..
@gudda1122 said:work wale question ka answer option A?????bhai answer bhi batate jao
bhai main tumhare saath saath solve kar raha hu