CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
2335
@JS-M said:
In ∆ABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ∆DOF to the area of ∆DOE?
(a) 8 : 9 (b) 9 : 8 (c) 3 : 4 (d) 4 : 3
My take 9:8
2336
@rahulshaitan said:
bhai hua kya tha?
bhai was actually stuck in downloading admit card for ACIO.... they wanted uploading the photo n signature of less than 20kb.... I had 22 kb with me which i had managed for SBI application ... but here they are asking 20kb n below.... JS-m bhai and others guided me .... tried ... but today went to studio finally and got it done...
2337
@JS-M said:
In ∆ABC, D is the midpoint of BC. E is a point on AC such that AE : EC = 2 : 1 and F is a point on AB such that AF : FB = 3 : 1. Line segments AD and FE intersect at point O. What is the ratio of the area of ∆DOF to the area of ∆DOE?
(a) 8 : 9 (b) 9 : 8 (c) 3 : 4 (d) 4 : 3
4:3
2338
A and B are centres of the two circles whose radius are 5 cm and 2 cm respectively. The
direct common tangents to the circles meet AB extended at P. The P divides AB in the ratio?
a. externally in the ratio 5:2
b. internally in the ratio 2:5
c. internally in the ratio 5:2
d. externally in the ratio 7:2


yaar yeh question samjh nhi aaya
2339
@rahulshaitan said:
matlab mere notes kuch to kaam aa he rahe hai
kuchh ???? you willl come to know tomorrow when puys wake up after slumber...those are really useful and more than that like shopperstop... one stop shopping...good show
2340
@mickym said: @rahulshaitan
Hey shaitan bhai chk my method for ur MAXIMA wala ques

1/(sin^2 y + 3 sin y cos y + 5 cos^2 y)= 1/ (sin^2 y + 4cos^2 y - 4sin y cos y + 7sin y cos y+ cos^2 y)= 1/ (sin y €“ 2cos y)^2 + cos^2 y +7 Sin y cos yFor this to be max. denominator should be minimum.so sin y = 2 cos y

Tany = 2

Or sin y = 2/rt5

Cos y = 1/rt5on putting these1/( 1/5 + 7*2/5)

= 1/3

Ans

bhai ye bhi theek lag raha mujhe confusion yahi hai ki hum square wale portion ko kab kab zero put kar sakte hai kyunki alag alag tarike se sqaure wale bracket me different values aayegi and answer different aayega.

sampras bhai ka bhi aisa he tarika tha but he is getting different answer so yi samajh nahi aa raha ki sqaure wale portion ko kin condtitions me zero put karte hai.
2341
@sampras said:
bhai was actually stuck in downloading admit card for ACIO.... they wanted uploading the photo n signature of less than 20kb.... I had 22 kb with me which i had managed for SBI application ... but here they are asking 20kb n below.... JS-m bhai and others guided me .... tried ... but today went to studio finally and got it done...
bhai photo editor se bhi ho jata hai so agar aur kabhi dikkat ho to use that software.
2342
@gudda1122 said:
A and B are centres of the two circles whose radius are 5 cm and 2 cm respectively. The
direct common tangents to the circles meet AB extended at P. The P divides AB in the ratio?
a. externally in the ratio 5:2
b. internally in the ratio 2:5
c. internally in the ratio 5:2
d. externally in the ratio 7:2
yaar yeh question samjh nhi aaya
externally in the ratio of 5:2...........
2343
@rahulshaitan said:
bhai ye bhi theek lag raha mujhe confusion yahi hai ki hum square wale portion ko kab kab zero put kar sakte hai kyunki alag alag tarike se sqaure wale bracket me different values aayegi and answer different aayega.sampras bhai ka bhi aisa he tarika tha but he is getting different answer so yi samajh nahi aa raha ki sqaure wale portion ko kin condtitions me zero put karte hai.
Bhai i think we shud always keep in mind the range of these functions
So accordingly we may chose the value
value shud lie within range
2344
@mickym said:
My take 9:8
yr approach share karna ...........
2345
@gudda1122 said:
A and B are centres of the two circles whose radius are 5 cm and 2 cm respectively. The
direct common tangents to the circles meet AB extended at P. The P divides AB in the ratio?
a. externally in the ratio 5:2
b. internally in the ratio 2:5
c. internally in the ratio 5:2
d. externally in the ratio 7:2
yaar yeh question samjh nhi aaya
ext in 5:2
2346
@JS-M said:
externally in the ratio of 5:2...........
sahi h bhai
approach and question kya bol rha h yeh batana
2347
@gudda1122 said:
sahi h bhai
approach and question kya bol rha h yeh batana
Similar triangles concept laga do
5:2 aa jayega
2348
@JS-M said:
yr approach share karna ...........
Bro I used MASS POINT GEOMETRY RULE
2349
@gudda1122 said:
sahi h bhai
approach and question kya bol rha h yeh batana
yr let M and N r point of contact of direct tangent for circle A & B.
Now triangle PBN ~ triangle PAM
so 2/5 = PB/PA...............
so P z d point outside the line ....so dividing it externally
2350
@mickym said:
Bro I used MASS POINT GEOMETRY RULE
..........wo kya hota hai.....thoda brief karoge??
2351
.A circular wire of radius 15 cm is cut and bent so as to lie along the circumference of a
loop of radius 120 cm. what is the measure of the angle subtended by it at the centre of the
loop?

lo yaar ek direct question
2352

11/7 radians

2353
lo yaar ek direct question

when a heap of pebbles is arranged into groups of 32 each 10 pebbles are left over .when
they are arranged in heaps of 40 each ,18 pebbles are left over and when in groups of 72 each
,50 are left over .the least no. Of pebbles in the heap is
options..
1450
1440
1418
1412

2354

@JS-M said:
..........wo kya hota hai.....thoda brief karoge??
Bro chk it out
very nice concept for speedy calculations