What is the maximum value of 1/(sin^2 y + 3 sin y cos y + 5 cos^2 y) ????
@cbiofficer said: on selling a pen at 5%loss and a book at 15% gain. karim gains rs 7 . if he sells the pen at 5 % gain and the book at 10% gainthen he gains rs 13..find the actual price..
pen = 100 rs
book = 80 rs
book = 80 rs
x^n+y^n always divisible by?(n odd natural no)
@sh.arora10 said:. An empty fuel tank of a car was filled with A type of petrol. When the tank was one-third empty, it was filled with B type of petrol. Again, when the tank was one-third empty, it was filled with A type of petrol. Again, when the tank was one-third empty it was filled with B type of petrol. At this time what was the percentage of B type of petrol in the tank?1) 51 %2) 48 %3) 49 %4) 50 %n plz explain hw to solve dis....
is the answr 48.1%
here the tank becomes 1/3 3 times so I took total capacity of the tank as 270.
1st addition -
A = 180 B = 90
2nd addition
1/3 consumed again so amount before addition -
A=2/3*180 = 120 and B = 2/3 *90 =60
now remaining is filled with A so quantity becomes -
A=120+90 = 210 and B =60
3rd addition -
A= 2/3*210= 140 and B = 2/3*60=40
now B is added so final quantity will be -
A = 140 and B = 40 + 90 = 130
now find the percentage.
here the tank becomes 1/3 3 times so I took total capacity of the tank as 270.
1st addition -
A = 180 B = 90
2nd addition
1/3 consumed again so amount before addition -
A=2/3*180 = 120 and B = 2/3 *90 =60
now remaining is filled with A so quantity becomes -
A=120+90 = 210 and B =60
3rd addition -
A= 2/3*210= 140 and B = 2/3*60=40
now B is added so final quantity will be -
A = 140 and B = 40 + 90 = 130
now find the percentage.
@rahulshaitan said: What is the maximum value of 1/(sin^2 y + 3 sin y cos y + 5 cos^2 y) ????
is it 50/257?
@rahulshaitan said: What is the maximum value of 1/(sin^2 y + 3 sin y cos y + 5 cos^2 y) ????
bhai my take ... 6(10-3rt5)/55
take the denominator as x then for 1/x to be maximum x has to be minimum
x can be simplified as ... (siny-rt5cosy)^2+ (2rt5+3) cosy siny
for min sq term has to be zero so... siny-rt5cosy = 0 .... tany = rt5
hence siny = rt5/rt6 and cosy = 1/rt6...
subs these values in x we get the answer as ...... 6(10-3rt5)/55
@sampras said:bhai my take ... rt6(2rt5-3)/11rt5take the denominator as x then for 1/x to be maximum x has to be minimumx can be simplified as ... (siny-rt5cosy)^2+ (2rt5+3) cosy sinyfor min sq term has to be zero so... siny-rt5cosy = 0 .... tany = rt5hence siny = rt5/rt6 and cosy = 1/rt6...subs these values in x we get the answer as ...... rt6(2rt5-3)/11rt5
nopes.
@rahulshaitan said:is the answr 48.1%here the tank becomes 1/3 3 times so I took total capacity of the tank as 270.1st addition - A = 180 B = 902nd addition 1/3 consumed again so amount before addition - A=2/3*180 = 120 and B = 2/3 *90 =60 now remaining is filled with A so quantity becomes -A=120+90 = 210 and B =603rd addition -A= 2/3*210= 140 and B = 2/3*60=40now B is added so final quantity will be - A = 140 and B = 40 + 90 = 130now find the percentage.
thnx :)
gt it 
A. When they move to another flower to feed, some of the pollen can rub off onto this new plant €™s stigma.
B. They are not trying to pollinate the plant.
C. Usually they are at the plant to get food, the sticky pollen or sweet nectar made at the base of the petals.
D. When animals such as bees, butterflies, moths, flies, and hummingbirds pollinate plants, it €™s accidental.
E. When feeding, the animals accidentally rub against the stamens and get pollen stuck all over themselves.
(a) EABDC (b) DBCEA (c) DCABE (d) EADBC
@sandeepv882 said: x^n+y^n always divisible by?(n odd natural no)
x+y property :D
@rahulshaitan said: What is the maximum value of 1/(sin^2 y + 3 sin y cos y + 5 cos^2 y) ????
3 by any chance????

@JS-M said:A. When they move to another flower to feed, some of the pollen can rub off onto this new plant €™s stigma.B. They are not trying to pollinate the plant.C. Usually they are at the plant to get food, the sticky pollen or sweet nectar made at the base of the petals.D. When animals such as bees, butterflies, moths, flies, and hummingbirds pollinate plants, it €™s accidental.E. When feeding, the animals accidentally rub against the stamens and get pollen stuck all over themselves.(a) EABDC (b) DBCEA (c) DCABE (d) EADBC
option D, it seems
@JS-M said:A. When they move to another flower to feed, some of the pollen can rub off onto this new plant €™s stigma.B. They are not trying to pollinate the plant.C. Usually they are at the plant to get food, the sticky pollen or sweet nectar made at the base of the petals.D. When animals such as bees, butterflies, moths, flies, and hummingbirds pollinate plants, it €™s accidental.E. When feeding, the animals accidentally rub against the stamens and get pollen stuck all over themselves.(a) EABDC (b) DBCEA (c) DCABE (d) EADBC
A
@JS-M said:A. When they move to another flower to feed, some of the pollen can rub off onto this new plant €™s stigma.B. They are not trying to pollinate the plant.C. Usually they are at the plant to get food, the sticky pollen or sweet nectar made at the base of the petals.D. When animals such as bees, butterflies, moths, flies, and hummingbirds pollinate plants, it €™s accidental.E. When feeding, the animals accidentally rub against the stamens and get pollen stuck all over themselves.(a) EABDC (b) DBCEA (c) DCABE (d) EADBC
b
@rahulshaitan said:nopes.
calculation mistake ... its coming as ... 6(10-3rt5)/55 ... is it correct... ????
@JS-M said:A. When they move to another flower to feed, some of the pollen can rub off onto this new plant €™s stigma.B. They are not trying to pollinate the plant.C. Usually they are at the plant to get food, the sticky pollen or sweet nectar made at the base of the petals.D. When animals such as bees, butterflies, moths, flies, and hummingbirds pollinate plants, it €™s accidental.E. When feeding, the animals accidentally rub against the stamens and get pollen stuck all over themselves.(a) EABDC (b) DBCEA (c) DCABE (d) EADBC
B