@cbiofficer said:bhai konsa ques h geo ka
A cyclic quadrilateral , PQRS is inscribes in a circle A tangent RT is drawn to it, /QRS=140; /SRT =??
In a tri ABC tan A + tanB + tanC = 6 and
tan A.tanB = 3 then triangle is-
(A) Acute angled (B) Obtuse angled
(C) Right angled (D) Equilateral
plz explain
@mrudalmodi C ??
@mrudalmodi said:If a sphere of radius r is divided into fouridentical parts, then the total surface areaof the four parts is(A) 4pie r^2(B) 2pie r^2(C) 8pie r^2(D) 3pie r^2
@Brooklyn said: Maximum value of : (x+2)/2x^2+4x+8
bhai option de do
else kafi bada ho jayega question
@JS-M said:A cyclic quadrilateral , PQRS is inscribes in a circle A tangent RT is drawn to it, /QRS=140; /SRT =??
bhai isme kuch missing lg rha h muje
@gudda1122 said:if 1/(x+1) + 2/(y+2) + 1009/(z+1009) =1 then d value of x/(x+1) + y/(y+2) +z/(z+1009)options r 0,2,3,4kindly please tell me which value you took and why?
x=-3,y=2,z=0
ans:2
ans:2
@mrudalmodi said:In a tri ABC tan A + tanB + tanC = 6 andtan A.tanB = 3 then triangle is-(A) Acute angled (B) Obtuse angled(C) Right angled (D) Equilateralplz explain
Obtuse.......
@gudda1122
@JS-M said:approach plz
yar was given without options:
i solved using differentiation .....do u wann c dat?
@JS-M said:approach plz
i think he has done this
x can't be less than (-2) because than answer will be negative
and at x=1 you will get 3/14
so maximum value will be at x=0
waise iska method bhi aata h but bahut bada hota h
@gudda1122 is it 2/3 of radius.
As total distance from the center will be 5/3
and the shortest distance will be 5/3r-r=2/3r
@Brooklyn said: @gudda1122yar was given without options:i solved using differentiation .....do u wann c dat?
by batana differentiation kaise use kiya???
after diffrentiation:
equal to zero n solve :)
