Hi, Puys CAT 2011 is finally over :: :: Lets start the Preparation for CAT 2012…please use this thread for all kind of LR-DI discussion,posting questions,submitting answers etc. Here are few links for previous years DI-LR thread …
Hi, Puys
CAT 2011 is finally over 

Lets start the Preparation for CAT 2012..please use this thread for all kind of LR-DI discussion,posting questions,submitting answers etc.
Here are few links for previous years DI-LR thread
Useful Links:-
http://www.pagalguy.com/discussions/cat-2011-lr-di-thread-25059843
http://www.pagalguy.com/discussions/cat-2010-lr-di-thread-25048796
Offcial (CAT 2009 LR-DI Thread)LR-DI thread for CAT2009(CAT 2009 LR-DI thread)
(THE OFFCICAL CAT2008: DI - lOGICAL REASOING)Official LRDI thread for CAT 2008 (THE OFFCICAL CAT2008: DI - lOGICAL REASOING)
(Vedic mathematics)Vedic Mathematics (Vedic mathematics)
( DI and VA/RC Question a Day by Arun Sharma's Mindworkzz)DI question a day ( DI and VA/RC Question a Day by Arun Sharma's Mindworkzz)
Let me Start with some questions :-
2 Persons A and B , are going down from 1st Floor to Ground Floor on an Esclator moving downward. A takes sometime to take 1 step as B takes to take 3 steps. A takes 50 steps & B takes 75 steps to reach ground Floor.
what is the number of steps in the escalator, while it is stationary ?
100 , 150 , 200 , 300
There are 80 balls which look identical. All the balls are of same weight except one which is heavier. In how many minimum weighing with a bean balance can you find the heavier ball?
4,5,6,7
A, B, C, D, and E are five different integers such that A B C D E = 45. Then the value of A + B + C + D + E is
13,11,9,5 

Let me Start with some questions :-
2 Persons A and B , are going down from 1st Floor to Ground Floor on an Esclator moving downward. A takes sometime to take 1 step as B takes to take 3 steps. A takes 50 steps & B takes 75 steps to reach ground Floor.
what is the number of steps in the escalator, while it is stationary ?
100 , 150 , 200 , 300
There are 80 balls which look identical. All the balls are of same weight except one which is heavier. In how many minimum weighing with a bean balance can you find the heavier ball?
4,5,6,7
A, B, C, D, and E are five different integers such that A B C D E = 45. Then the value of A + B + C + D + E is
13,11,9,5
No idea about first
2nd . ans may be minimum 6 weight
there are total 80 balls
first divide 80 into two parts 40 40. check the heaviest part and then divide
second these 40 into 20 20 check the heaviest part and then divide
Third these 20 into 10 10 check the heaviest part and then divide
Fourth these 10 into 5 5 check the heaviest part and then divide
Fifth now divide these 5 into 2 2 1
check with 2 2 if these are equal means the remaining is the heavy ball
otherwise check with one more step.
so the total minimum steps required 6 .
For third que.
make the factors of 45 which are 3*3*5=45
there may be two cases
first 5*9*1*1*1=45
5+9+1+1+1=17
Second 5*3*3*1*1=45
5+3+3+1+1=13
17 is not in the option so the ans is 13
No idea about first
2nd . ans may be minimum 6 weight
there are total 80 balls
first divide 80 into two parts 40 40. check the heaviest part and then divide
second these 40 into 20 20 check the heaviest part and then divide
Third these 20 into 10 10 check the heaviest part and then divide
Fourth these 10 into 5 5 check the heaviest part and then divide
Fifth now divide these 5 into 2 2 1
check with 2 2 if these are equal means the remaining is the heavy ball
otherwise check with one more step.
so the total minimum steps required 6 .
For third que.
make the factors of 45 which are 3*3*5=45
there may be two cases
first 5*9*1*1*1=45
5+9+1+1+1=17
Second 5*3*3*1*1=45
5+3+3+1+1=13
17 is not in the option so the ans is 13
Buddy you almost got it. The question says distinct integers, so the numbers should be 1,-1,3,-3,5. So the sum comes out as 5
As for the beam balance questions, a better breakup could be 27,27,26
If one of the 27 lots is heavy, then 27 can be further broken up as 9,9,9
then 3,3,3 then 1,1,1 so total of 4 weighings
Now if the 26 lot is heavy then it can be broken up as 13,13 then further as 6,6,1....3,3....1,1,1... so total weighings come out to be 5
So my take on this one would be 5
Let me Start with some questions :-
2 Persons A and B , are going down from 1st Floor to Ground Floor on an Esclator moving downward. A takes sometime to take 1 step as B takes to take 3 steps. A takes 50 steps & B takes 75 steps to reach ground Floor.
what is the number of steps in the escalator, while it is stationary ?
100 , 150 , 200 , 300
My take on this would be 100 steps
Twelve students, mentioned below, from 4 different schools - ABS, XYS, PQS and MKS participated in the 3 inter-school competitions Acting, Dancing and Singing.
Each school was represented by only one student in each competition. There were no ties and the points awarded for 1st, 2nd, 3rd and 4th ranks were 3, 2, 1 and 0 respectively.
- Ajay and Prakash were from ABS and, both have scored points.
- Sunil, Akash and Amit could not score any points. None of them is from MKS.
- The overall points earned by the schools are in A.P.
- Akash is the only student from XYS who could not come 1st, and he participated in Dancing. - Dheeraj and Pradeep came third in Singing and Dancing respectively.
- Vijay and Neeraj both came first in their respective competitions.
- XYS got the maximum points, while PQS earned 4 points.
- Sandeep and Ajit from the same school have scored points, while Amit from the same school could not score any points in Singing.
- Ajit, Neeraj and Anil took part in Acting.
Who came second in Dancing?
a.)Sandeep b.)pradeep c.)ajit d.)prakash
Which school got the least total points?
a.)MKS b.)PQS c.)ABS d.)MKS or PQS
In which competition did Vijay participate?
a.)Acting b.)Singing c.) Dancing d.)Acting or singing![]()
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Twelve students, mentioned below, from 4 different schools ABS, XYS, PQS and MKS participated in the 3 inter-school competitions Acting, Dancing and Singing.
Each school was represented by only one student in each competition. There were no ties and the points awarded for 1st, 2nd, 3rd and 4th ranks were 3, 2, 1 and 0 respectively.
Ajay and Prakash were from ABS and, both have scored points.
Sunil, Akash and Amit could not score any points. None of them is from MKS.
The overall points earned by the schools are in A.P.
Akash is the only student from XYS who could not come 1st, and he participated in Dancing. Dheeraj and Pradeep came third in Singing and Dancing respectively.
Vijay and Neeraj both came first in their respective competitions.
XYS got the maximum points, while PQS earned 4 points.
Sandeep and Ajit from the same school have scored points, while Amit from the same school could not score any points in Singing.
Ajit, Neeraj and Anil took part in Acting.
Who came second in Dancing?
a.)Sandeep b.)pradeep c.)ajit d.)prakash
Which school got the least total points?
a.)MKS b.)PQS c.)ABS d.)MKS or PQS
In which competition did Vijay participate?
a.)Acting b.)Singing c.) Dancing d.)Acting or singing
My take
d)
a)
d)
Time for some unfinished business..:)
Xat is on the corner..Will post questions based on it.
Time for some unfinished business..:)
My take is
9 - Silence
10 - Rosebud
11 - 3
As the first statement says Ms.Tilti and previous person have the same number of characters and the subsequent word is one less than word of Ms.Titli...
--------- x letters-----x letters----(x-1)letters
---------unknown------Ms.Tilti----Either Mr.Bineet or Mr.Easwer(coz it says the next word after Ms.Titli is a men....
Since now Ms.Tilti and previous person should have the same number of characters and as well as one more than subsequent word,it got to be a seven letter word..(Silence or rosebud)...
Now Ms.Tilti's word will be either in 2,3,4 position..
If Ms.Tilti's word is in 4th position then 3rd word will be a 7 letter word and 5th position word will be 6 letter word and 2nd word will be 8 letter word...
But this possibility is not possible because as per the 5th statement it says Baadshah can't be second word...
And as per 6th statement,Ms.Sheela has to be 2nd and Ms.Elsie is 5th
So now it is like
Barley--------Silence/Rosebud-------Silence/Rosebud------Burden------------Baadshah
Mr.Bineet----------Ms.Sheela-----------Ms.Tilti------------Mr.Eashwar------Ms.Elsie
-----------------------------------------8 across------------------------------
Now as it shows Silence word is for only across,so it can be either 15 across or 21 across...
And also Baadshah word is also filled in across as per the last statement...
As 4 down cant be the word found by Eashwar,Bineet word will be 4 down..
4th word was answered by a man=>Sheela answered 2nd word
2nd and 3rd are 7 letter words each
Silence cant be third =>it was answered 2nd
Hence Sheela's answer was Silence
So it is now as
Barley--------Silence------Rosebud------Burden------------Baadshah
Mr.Bineet----------Ms.Sheela-----------Ms.Tilti------------Mr.Eashwar------Ms.Elsie
---4 down----15 across or 21 across----8 across-------------15 down-------15 across or 21 across
9-2
10-3
11-3.
30. The day on which Irfan takes rest is
(1) Saturday
(2) Sunday
(3) Friday
(4) Thursday
(5) Cannot be determined
31. If Irfan practiced two of the three aspects of the game on a certain day, it can be a
(1) Tuesday
(2) Saturday
(3) Thursday
(4) Monday
(5) Sunday
32. Irfan practices which aspect on a Sunday?
(1) Batting
(2) Bowling
(3) Fielding
(4) More than one of the above
(5) Cannot be determined
Irfan is an all-rounder in cricket and is good at all the three aspects of the game batting, bowling and fielding. For this season, he has assigned himself a weekly training schedule, such that each of the three aspects are practiced for exactly three sessions, in a period of seven days. Also, the gap between any two consecutive practice sessions of any of the three aspects, must not be more than two days. He rests completely on exactly one day of the week and only on Wednesdays does he practice all the three batting, bowling and fielding. During a certain period of six consecutive days, he practiced fielding on the first day, batting on the second day, bowling on the third day, fielding on the fourth day, bowling on the fifth day and batting on the sixth day. The above mentioned is only a partial list for some of the days, during which he could have practiced more than one of batting, bowling and fielding on the same day.
30. The day on which Irfan takes rest is
(1) Saturday
(2) Sunday
(3) Friday
(4) Thursday
(5) Cannot be determined
31. If Irfan practiced two of the three aspects of the game on a certain day, it can be a
(1) Tuesday
(2) Saturday
(3) Thursday
(4) Monday
(5) Sunday
32. Irfan practices which aspect on a Sunday?
(1) Batting
(2) Bowling
(3) Fielding
(4) More than one of the above
(5) Cannot be determined
i am getting
31) Friday
32) Saturday
33) Batting
Irfan is an all-rounder in cricket and is good at all the three aspects of the game batting, bowling and fielding. For this season, he has assigned himself a weekly training schedule, such that each of the three aspects are practiced for exactly three sessions, in a period of seven days. Also, the gap between any two consecutive practice sessions of any of the three aspects, must not be more than two days. He rests completely on exactly one day of the week and only on Wednesdays does he practice all the three batting, bowling and fielding. During a certain period of six consecutive days, he practiced fielding on the first day, batting on the second day, bowling on the third day, fielding on the fourth day, bowling on the fifth day and batting on the sixth day. The above mentioned is only a partial list for some of the days, during which he could have practiced more than one of batting, bowling and fielding on the same day.
30. The day on which Irfan takes rest is
(1) Saturday
(2) Sunday
(3) Friday
(4) Thursday
(5) Cannot be determined
31. If Irfan practiced two of the three aspects of the game on a certain day, it can be a
(1) Tuesday
(2) Saturday
(3) Thursday
(4) Monday
(5) Sunday
32. Irfan practices which aspect on a Sunday?
(1) Batting
(2) Bowling
(3) Fielding
(4) More than one of the above
(5) Cannot be determined
The sequence:
Mon -> Bowlling
Tue -> Fielding
Wed -> Bowling, Batting, Fielding
Thur -> Batting
Fri -> Rest
Sat -> Fielding, Bowling
Sun -> Batting
30. 3-Friday
31. 2-Saturday
32. 1-Batting
Irfan is an all-rounder in cricket and is good at all the three aspects of the game batting, bowling and fielding.........
30. The day on which Irfan takes rest is
(3) Friday
31. If Irfan practiced two of the three aspects of the game on a certain day, it can be a
(2) Saturday
32. Irfan practices which aspect on a Sunday?
(1) Batting
My take in bold
SET-3
A quack- Dr. Fools Paradise- fools his customers by claiming to predict future using a unique method. He has
three parrots kept in three different cages. Each cage has three cards with a single non-zero digit inscribed on
every card. No two cards have the same number & no cage contains two cards with digits totalling ten. Further,
the total of three cards in the first cage is greater by two than the total in the second cage & by four than that of
third cage. When a customer asks for his prediction, the quack lets out three parrots which randomly picks one
card out of their respective cages. Before the prediction is made, the quack totals the digits on the three picked
cards & charges the customer the same number of rupees as the total of the cards. One day a customer paid
seven rupees for his prediction.
1. What is the lowest payment possible?
(1) Rs. 5 (2) Rs. 7 (3) Rs. 6 (4) Rs. 8
2. What is the maximum possible amount that anyone can pay?
(1) Rs. 22 (2) Rs. 23 (3) Rs. 24 (4) Rs. 25
3. Which of the following payments can never be made by any customer?
(1) Rs. 19 (2) Rs. 16 (3) Rs17 (4) Rs. 23
SET-3
A quack- Dr. Fools Paradise- fools his customers by claiming to predict future using a unique method. He has
three parrots kept in three different cages. Each cage has three cards with a single non-zero digit inscribed on
every card. No two cards have the same number & no cage contains two cards with digits totalling ten. Further,
the total of three cards in the first cage is greater by two than the total in the second cage & by four than that of
third cage. When a customer asks for his prediction, the quack lets out three parrots which randomly picks one
card out of their respective cages. Before the prediction is made, the quack totals the digits on the three picked
cards & charges the customer the same number of rupees as the total of the cards. One day a customer paid
seven rupees for his prediction.
1. What is the lowest payment possible?
(1) Rs. 5 (2) Rs. 7 (3) Rs. 6 (4) Rs. 8
2. What is the maximum possible amount that anyone can pay?
(1) Rs. 22 (2) Rs. 23 (3) Rs. 24 (4) Rs. 25
3. Which of the following payments can never be made by any customer?
(1) Rs. 19 (2) Rs. 16 (3) Rs17 (4) Rs. 23
Since no sum equals ten and there are 9 cards..so we have the numbers 1 to 9 present.
Given,
a + (a+2) + (a+4) = 9*10/2 = 45
=> 3a = 39
=> a = 13
So the sum of the cards are 13,15,17
Now we know from the problem that the numbers below cannot come together..
(1,9), (2,
So the possible combination we can take to get the sums as 13,15,17
Cage 1 has 3,5,9 cards = 17
Cage 2 has 2,6,7 cards = 15
Cage 3 has 1,4,8 cards = 13
1. Minimum will be when cards selected are (1+2+3) = 6
2. Maximum will be when cards selected are (9+7+
3. 1) 19 - 9+6+4
2) 16 - 5+7+4
3) 17 - 9+7+1
4) 23 - 9+6+8
I think options given in question 3 is incorrect. Please confirm.
Originally Posted by A2012
Twelve students, mentioned below, from 4 different schools - ABS, XYS, PQS and MKS participated in the 3 inter-school competitions Acting, Dancing and Singing.
Each school was represented by only one student in each competition. There were no ties and the points awarded for 1st, 2nd, 3rd and 4th ranks were 3, 2, 1 and 0 respectively.
- Ajay and Prakash were from ABS and, both have scored points.
- Sunil, Akash and Amit could not score any points. None of them is from MKS.
- The overall points earned by the schools are in A.P.
- Akash is the only student from XYS who could not come 1st, and he participated in Dancing. - Dheeraj and Pradeep came third in Singing and Dancing respectively.
- Vijay and Neeraj both came first in their respective competitions.
- XYS got the maximum points, while PQS earned 4 points.
- Sandeep and Ajit from the same school have scored points, while Amit from the same school could not score any points in Singing.
- Ajit, Neeraj and Anil took part in Acting.
Who came second in Dancing?
a.)Sandeep b.)pradeep c.)ajit d.)prakash
Which school got the least total points?
a.)MKS b.)PQS c.)ABS d.)MKS or PQS
In which competition did Vijay participate?
a.)Acting b.)Singing c.) Dancing d.)Acting or singing
my take
1)a
2)a
3)b
Twelve students, mentioned below, from 4 different schools ABS, XYS, PQS and MKS participated in the 3 inter-school competitions Acting, Dancing and Singing.
Each school was represented by only one student in each competition. There were no ties and the points awarded for 1st, 2nd, 3rd and 4th ranks were 3, 2, 1 and 0 respectively.
Ajay and Prakash were from ABS and, both have scored points.
Sunil, Akash and Amit could not score any points. None of them is from MKS.
The overall points earned by the schools are in A.P.
Akash is the only student from XYS who could not come 1st, and he participated in Dancing. Dheeraj and Pradeep came third in Singing and Dancing respectively.
Vijay and Neeraj both came first in their respective competitions.
XYS got the maximum points, while PQS earned 4 points.
Sandeep and Ajit from the same school have scored points, while Amit from the same school could not score any points in Singing.
Ajit, Neeraj and Anil took part in Acting.
Who came second in Dancing?
a.)Sandeep b.)pradeep c.)ajit d.)prakash
Which school got the least total points?
a.)MKS b.)PQS c.)ABS d.)MKS or PQS
In which competition did Vijay participate?
a.)Acting b.)Singing c.) Dancing d.)Acting or singing
My take
1)a
2)a
3)b
Since no sum equals ten and there are 9 cards..so we have the numbers 1 to 9 present.
Given,
a + (a+2) + (a+4) = 9*10/2 = 45
=> 3a = 39
=> a = 13
So the sum of the cards are 13,15,17
Now we know from the problem that the numbers below cannot come together..
(1,9), (2,, (3,7), (4,6)
So the possible combination we can take to get the sums as 13,15,17
Cage 1 has 3,5,9 cards = 17
Cage 2 has 2,6,7 cards = 15
Cage 3 has 1,4,8 cards = 13
1. Minimum will be when cards selected are (1+2+3) = 6
2. Maximum will be when cards selected are (9+7+= 24
3. 1) 19 - 9+6+4
2) 16 - 5+7+4
3) 17 - 9+7+1
4) 23 - 9+6+8
I think options given in question 3 is incorrect. Please confirm.
My take
1) 3
2) 3
3) 4
Quack can predict 7.
So 1 ,2 and 4 should be in different cages.
combination
cage 1:- 2 6 9
cage 2:- 3 4 8
cage 3:- 1 5 7
for third question
23 is possible only when sum is 9+8+6.But this is not possible as 9 and 6 are in same cage










