@[518068:raku1989] My Bad...
-1000
142
So a= 142+142+1 =285 
@[533596:Kevin88]
What is the remainder when 128^1000 is divided by 153
this time no options for you!!
@[518068:raku1989] Is it 67
Srry Calculation Mistake :9k1+7=17k2+1 ==> Rem : 52...
Hell if i have no options... i am bound to make some stupid calculation mistake !!!
@[533596:Kevin88] solution?
@[582772:brandnewrap] : 52 is the sol for the q posted by raku !!
Bro.. quote the Q No: too ..
..Damn.. i love this smiley!!
@[533596:Kevin88] By solution, i meant how you arrived at the answer 52.
@brandnewrap said: @Kevin88 By solution, i meant how you arrived at the answer 52.
153 = 9*17
So by 17 we ill get a remainder of 1 and
by 9 we ll get a remainder of 7.
So we can have 9k1+7=17k2+1
@[582772:brandnewrap] So sorry bro... My fuse is all blown !!! 
128^1000 /153 ==>
153 = 17*9
Hence find out the remainders when (128^1000)/17 & (128^1000)/9
For (128^1000)/17 ===> Remainder is 1.
For (128^1000)/9 ===> Remainder is 7
Hence 9k+7=17s+1
s = (9k+6)/17
When k=5 ==> s=3
So final remainder is 17(3)+1 = 9(5) +7 = 52
@[518068:raku1989] @[526706:pradyothcjohn] & everyone lurking out ther !!
Good Night & Hope to see you all tomorrow !!!
Good night everyone 😁 This is good,this thread..this way i see a few qns,at the very least 😛 😁
CAT 2005 question
whats the remainder when (p+2) is divided by 11!
options 10, 0, 7, 1
ans is 1.
Can someone explain ?
@[514195:seetharam7]
p = 1! + (2*2!)+(3*3!)+(4*4!)+.....+(10*10!)
= (2!- 1!) + (3!-2!) + (4!-3!) +..........(11!-10!)
= 11! - 1!
p+2 = 11!+1
(p+2)/11 will give remainder of 1.
for the 4x+7y=3 question
here is how i did it
x=(3-7y)/4
so, for x and y to be integers, i took 2 cases
case 1
y=1,5,9...
x=-1,-8,-15....-995
no of solutions = 143
case 2
y=-3,-7,-11....
x=6,13,20...993
no of solutions = 142
total = 285 
@[533596:Kevin88] is it a formula ?? n*n! = (n+1)!-n! ??
@[514195:seetharam7] You can derive it : N*N!= (N+1-1)N!= (N+1)N! - N!= (N+1)! - N!
oh my , i am missing out on so much of good things out here , busy with coimbatore stuff, Will be active from tuesday onwards:)! decided to deffer the ITIS offer
@[533596:Kevin88] Thanks
@[533596:Kevin88] @[526706:pradyothcjohn] @[518068:raku1989] @[495113:joethaliath] @[582772:brandnewrap] Guys, almost all the questions we discuss are quant based. That too, mostly remainders. We are confining ourselves. How about we discuss around 2 chapters a day ? Every person can post short cuts for that chapters. So at the end of the day, we will have all the short cuts together a chapter. What do you guys say ?
@[514195:seetharam7] Gud suggestion, however if we try 2 chapters a day.. it wud result in confining ourselves to only a few Q's per chapter.. how abt we discuss 2 chapters per week; tht wud mean abt 1 chapter for say abt 2-3 days depending on the feedback from the team.
If any one has a particular weak section , we cud discuss more Q's based on the response & activeness of the team.
If each member of the team can post abt 5 different Q's relating to the respective chapter at the very least , we cud have a discussion of nearly 30-50 Q's.
However this need not be compulsory, team members can post difficult Q's & any Q's they have a doubt in or which they encounter during self prep which in turn cud strengthen the core concepts of the entire team too..
@[518068:raku1989] @[397955:rohan_bhasker] @[495113:joethaliath] @[526706:pradyothcjohn] @[544751:pugna] @[149515:dead_alive] @[319787:vinmohcetvmklm] @[582772:brandnewrap] @[585700:KatMann] @[584893:sriraman89] : Any Suggestions ??