whta is the method that is bng used for solving 29 question.. by time..
Remainder of lcm. of 3^2003-1 and 3^2003+1... as in how come it is (3^2-1)/2
In one of the Grammar caselets , the first sentence has a fullstop missing and they have passed it off as a correct sentence . 
They have just crapped out in the solution.
The right approach is to find the remainder by 20 ( if we find remainder by 10 , we cant be sure of the last digit when we divide by 2 subsequently , as 8 can give last digit of 4 or 9 ) for the product of those 2 nos. and then divide that remainder by 2.
Remainder was 8 , and hence answer is 4.
i have consistently score 80%ile in all five aimcats ...Suppose i dont improve what should i expect in CAT ...... do Give a %ile.
I dont understand why do people vote with fake scores even in aimcat polls
There are total 4 students with score>120 according to TIME but in pg there are 5.
QA - 43.9 8(Screwed up QA big time) :banghead:
VA - 99.25
OA - 90.09
was d 1st mock test dat 2 w/o any preparation.. need to gear up for QA frm here onwrds ..
Can sum1 pls explain the solution for the log problem. Q.No 7 in section I.
QA/DI - 82.07 %ile :(
VA/LR - 97.76 %ile
OA - 95.39 %ile
AIR - 798
QA/DI -85.43%ile - 30
va/lr - 89.37 %ile - 37
OA - 90.83%ile - 67
Don't know how to react....
QA/DI -85.43%ile - 30
va/lr - 89.37 %ile - 37
OA - 90.83%ile - 67
Don't know how to react....
Que : To find Last Digit (LD) of LCM [3^2003-1 and 3^2003+1]
Soln : LD ( LCM [ 3^3 - 1 and 3^3 + 1]) ...... taking last digit of 2003 in the power, i.e., 3
LD ( LCM [ 26 and 28])
LD ( 13*7*4 ) = LD (264) = 4 Answer
They have just crapped out in the solution.
The right approach is to find the remainder by 20 ( if we find remainder by 10 , we cant be sure of the last digit when we divide by 2 subsequently , as 8 can give last digit of 4 or 9 ) for the product of those 2 nos. and then divide that remainder by 2.
Remainder was 8 , and hence answer is 4.
akiii Saysu took last digits of 2003? y ?
the breakup of score for 1316 is
QA/DI-91.62
VA/LR-99.25
OA-98.53
AIR-255
Is there anyway i can get the aimcat 1316 with the solution so i can see which all questions i did wrong.
Though this is not from AIMCAT 1316 it's a good question to solve. I'll be happy if u try this and let mw know the answer.
XYZ company Produces various products P,Q,R,S,T,U,V. Out of entire no. of products it produces P=20%, Q=18%, R=19%, S=12% ,T=10% ,U=13% ,V=8% .
It sells certain no. products out of produced ones. It sells P=24%, Q=12%, R=16%, S=14%, T=9%, U=15%, V=10 %
Atmost what percentage of products manufactured by the company were sold i that year?
1. 90% 2. 65% 3.83.33% 4.None of these
can anyone plz mail me Qs and solutions of aimcat 1316?
my email id is my PG user name @gmail.com
thnx in advance
Though this is not from AIMCAT 1316 it's a good question to solve. I'll be happy if u try this and let mw know the answer.
XYZ company Produces various products P,Q,R,S,T,U,V. Out of entire no. of products it produces P=20%, Q=18%, R=19%, S=12% ,T=10% ,U=13% ,V=8% .
It sells certain no. products out of produced ones. It sells P=24%, Q=12%, R=16%, S=14%, T=9%, U=15%, V=10 %
Atmost what percentage of products manufactured by the company were sold i that year?
1. 90% 2. 65% 3.83.33% 4.None of these
Ques: 7^777 / 28
Soln : 7^7 / 28 ............ taking last digit of power i.e., 7
By cyclicity of 7^n / 28 .... it comes like 7..21..7..21..7..21........n
So, the cyclicity of 7^n / 28 is 2.
Hence, for 7^7 / 28, remainder is 7 .......
akiii Saysstill dint get u dude.. please explain in a simpler way..i am not able to understand the cyclicity.. ..7...21 .. 7.. 21.. what is that actly?