SSC CGL 2019-20 Tier 1 Syllabus, Exam Pattern and Preparation Tips

Staff Selection Commission (SSC) SSC - CGL
17296

## MAXIMA MINIMA ##


KAAM CHALAU POST ____/\___

 when sum of any quantities is constant, there product is maximum when they are equal.

example. if 3x+5y=15. 

find maximum value of x^2*y^3. 

here 3x+5y=15 => 3x/2 + 3x/2 + 5y/3 + 5y/3 + 5y/3 = 15.--------------1as I said, when sum of any quantities is constant, there product is maximum when they are equal. :beers

here sum is constant. so when 3x/2 = 5y/3. we get maximum value of x^2*y^3. taking 3x/2 = 5y/3 putting it in 1, => 5(3x/2) = 15. =>x=2. and y = 9/5. answer is 2^2*(9/5)^3. :beers

generalizing it, how to find maximum value of x^m*y^n where ax+by=P. a,b,x,y>0 x^m*y^n is maximum when ax/m = by/ n = p/m+n 4. when the product of any quantity is constant, sum of the all the quantity is minimum, when they are equal. xy^3 = 64.


find minimum value of x+12y. we need to adjust x+12y,accordingly. x+12y = x+ (12y/3)*3now, x*(12y/3)^3= 64 *64 ( coz xy^3 = 64)-----------1 the product is constant. so the sum of the quantities will be minimum when quantities are equal. take x= 12y/3 putting it in 1, we get x= 8 =>12y/3 = 8, y = 2. minimum value of x+12y = 8+24 = 32.


generalizing it, how to find minimum value of ax+by where x^m*y^n=P a,b,x,y>0 ax+by is minimum when ax/m = by/n 

🍻 

17297

##chotuuuu post  tips ###

##yaad karlo post ##

  :beers

In a solid figure no. of faces + vertices = no. of edges+2

 i.e. F+V=E+2

 If a larger cube painted by a color is broken into n smaller cubes, then no. of cubes having
3 faces painted = 8
2 faces painted = 12(n-2)
1 face painted = 6(n-2)^2
0 faces painted = (n-2)^3 


 There are n non-overlapping identical triangles, then at max how many bounded regions these intersecting triangle can form.

3n^2 - 3n + 1 

:beers 🇲🇬 

17298

Khuskhabari.. Cgl tier 1 result to be declared this week 

17299

The distance b/w P&Q is 100m and the speeds of A and B 20m/s and 30m/s respectively.Initially A and B are at P.The distance B/w Q & the point of 3rd meeting?



answer is 60 . pls explain

17300

Hello Puys,

Here is the PaGaLGuY's Current Affairs Monthly Bullet for October 2016 .https://www.pagalguy.com/news/current-affairs-monthly-bullet-for-competitive-exams-october-2016-46561528

 

17301

             So Here is your drill for the rest of your Life.



                               1.01^365 = 37.8


                               0.99^365 = 0.03.



 It compares where you end up if you improve by 1% every day for a year instead of going worse by 1% every day for a year. 


                              As Simple as That !!!

17302

Number system k liye koi achhi si site batado

17303

solve:

 find the radian measure corresponding to   5° 37' 30" 

A. pi/8 rad        B. pi/12 rad             C  pi/18            D. pi/32 rad

17304

solve:

 The simplified value of  (secθ−cosθ)^2+(cosecθ−sinθ)^2−(cotθ−tanθ)^2

  1. 1/2
  2. 0
  3. 2
  4. 1
17305

##remainder post ##

 Euler's Totient
Eulers totient, (n), of a a number n is the number of positive integers less than or equal to n that are coprime to n.

If n = (p1)^a*(p2)^b*(p3)^c*......, where p1, p2, p3, .... are prime numbers then
(n) = n(1 - 1/p1)(1 - 1/p2)(1 - 1/p3).....

For ex:-
147 = 3*7^2
(147) = 147(1 - 1/3)(1 - 1/7) = 84

Eulers's Theorem
If {(a^(n)) - 1} is divisible by n, where (n) is Euler's totient of n and n is coprime to a.
That means a^(n) = 1 (mod n)

For ex:-
We have to find the remainder when 5^180 is divided by 209.

Now, 209 = 11*19
=> (209) = 209*(1 - 1/11)(1 - 1/19) = 180

=> Since 5 and 209 are coprime, we can say that
5^180 = 1 (mod 209) 


@pavansai564  ye waala dekho 

most rremainder problems can be solved through this !!!

🍻 


17306

Values of a and b for 8x^2-ax^2+54x+b  be a perfect cube are ....a>0 and b< 0 .....iska short cut bata do koi _/\_

17307

Can anybody tell the coupon code of TESTBOOK for SSC T2 test series ?


TIA!

17308

##try try try ##

CHai waala post 🍵 

 42 cubes of side 1cm are glued together to form a solid cuboid.if the perimeter of base of the cuboid is 18cm,

 then find the number of possible heights (height being integer)  

17309

kd maths mock is not loading properly. Is it only me or any one else is also facing same problem?

17310

solve:

http://imgur.com/MwG6R5z

17311

Do you get the feeling that maths tier 2 is going to be of same level as of pre , like what ssc tube has said?

  • no
  • yes

0 voters

17312

http://imgur.com/RJvCXsF

17313

http://imgur.com/pGTjt8N


17314

http://imgur.com/F11uOdA

17315

All that is human must REVERT if it does not advance

ans nahi pata 

  • withdraw
  • no improvement
  • retire
  • retrograde

0 voters