Today, NO Gym !! (Cardio Day) ... (Kal watt lagegi.. lower body)
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@fisherking said:New age ways to psyche people
naaah asking for and discussing a mock bfroe actli writing one shows insecurity..IMHO...anyway..atb.
@shashanksvnit05 said:naaah asking for and discussing a mock bfroe actli writing that shows insecurity..IMHO...anyway..atb.
"Insecurity" is a bit harsh I think.. "Impatience" is the right word, I think 😃 .. :mg:
"Impatience" would be trying to login even bfore ur slot I think 😃 not asking others "hows it" .
@fisherking said:Anupam jee ke sirf score dekho...Unke aur Vanni jee ke comments self deprecation ka epitome hain....Anupam jee ekdum form main aa rahe hain
maine kya kar diya ab? :o
@anupam001 @fisherking .. Help me with this QA question:
Two guys start from A and B,which is 50 kms from A, and with speeds in the ratio 2:3. At how many distinct points will they meet and where will they meet for the 23rd time ?
@YouMadFellow said:@anupam001 @fisherking .. Help me with this QA question:Two guys start from A and B,which is 50 kms from A, and with speeds in the ratio 2:3. At how many distinct points will they meet and where will they meet for the 23rd time ?
3 distinct points
They will meet at A for the 23rd time. (this is assuming person with 2x speed starts from A and 3x starts from B initially)
They will meet at A for the 23rd time. (this is assuming person with 2x speed starts from A and 3x starts from B initially)
@Ibanez said:3 distinct points They will meet at A for the 23rd time. (this is assuming person with 2x speed starts from A and 3x starts from B initially)
How ? Approach ?
@YouMadFellow said:How ? Approach ?
Well, for the first part there's a direct concept. It will be max(2,3) =3 . If you wanna verfiy
take a track of length 5m and let the speeds be 2m/s and 3m/s. Do a quick dry run and you'll find only 3 distrinct points. Concept: No of distinct points= Max(ratio of speeds) so 3.
2nd part.
They together cover (2n-1)*d distance at their nth meet where d is the length of the track. to elaborate,
Distance covered together after the first meet =d
From now on after every meet they would cover a distance 2d together
so discovered after nth meet = (2n-1)d
n=23, total dis covered by both = 45d. Out of which A would have covered 2/5 *45d =18d So they meet at A.
take a track of length 5m and let the speeds be 2m/s and 3m/s. Do a quick dry run and you'll find only 3 distrinct points. Concept: No of distinct points= Max(ratio of speeds) so 3.
2nd part.
They together cover (2n-1)*d distance at their nth meet where d is the length of the track. to elaborate,
Distance covered together after the first meet =d
From now on after every meet they would cover a distance 2d together
so discovered after nth meet = (2n-1)d
n=23, total dis covered by both = 45d. Out of which A would have covered 2/5 *45d =18d So they meet at A.
@Ibanez said:Well, for the first part there's a direct concept. It will be max(2,3) =3 . If you wanna verfiy take a track of length 5m and let the speeds be 2m/s and 3m/s. Do a quick dry run and you'll find only 3 distrinct points. Concept: No of distinct points= Max(ratio of speeds) so 3.2nd part.They together cover (2n-1)*d distance at their nth meet where d is the length of the track. to elaborate,Distance covered together after the first meet =d From now on after every meet they would cover a distance 2d together so discovered after nth meet = (2n-1)dn=23, total dis covered by both = 45d. Out of which A would have covered 2/5 *45d =18d So they meet at A.
mujhe max waala funda nahi pata tha..i usually make pattern for these qs like first meeting point will be at d=20..similarly calculating second and 3rd meet we will find that it will start repeating...ab max waala concept hi use karunga :P
@anupam001 said:mujhe max waala funda nahi pata tha..i usually make pattern for these qs like first meeting point will be at d=20..similarly calculating second and 3rd meet we will find that it will start repeating...ab max waala concept hi use karunga
Aimcat1311 ke first ques ne sikhaya tha yeh funda.same ques tha 2:3 , all of marked 5 distinct points. Then dry run kia ghar aake toh yeh funda nikla tha
@Ibanez
@Ibanez said:Well, for the first part there's a direct concept. It will be max(2,3) =3 . If you wanna verfiytake a track of length 5m and let the speeds be 2m/s and 3m/s. Do a quick dry run and you'll find only 3 distrinct points. Concept: No of distinct points= Max(ratio of speeds) so 3.2nd part.They together cover (2n-1)*d distance at their nth meet where d is the length of the track. to elaborate,Distance covered together after the first meet =dFrom now on after every meet they would cover a distance 2d togetherso discovered after nth meet = (2n-1)dn=23, total dis covered by both = 45d. Out of which A would have covered 2/5 *45d =18d So they meet at A.
i followed a different but similar approach..........after every 4th meet they will meet at first point...hence for 23rd meet, I found the 3rd meeting point which turned out to to be A
@anupam001 said:mujhe max waala funda nahi pata tha..i usually make pattern for these qs like first meeting point will be at d=20..similarly calculating second and 3rd meet we will find that it will start repeating...ab max waala concept hi use karunga
If speed ratio is 4:6 isme bhi 3 hoga and not 6. simplest form mei lana hai ratio ko pehle.
@Ibanez said:Well, for the first part there's a direct concept. It will be max(2,3) =3 . If you wanna verfiy take a track of length 5m and let the speeds be 2m/s and 3m/s. Do a quick dry run and you'll find only 3 distrinct points. Concept: No of distinct points= Max(ratio of speeds) so 3.2nd part.They together cover (2n-1)*d distance at their nth meet where d is the length of the track. to elaborate,Distance covered together after the first meet =d From now on after every meet they would cover a distance 2d together so discovered after nth meet = (2n-1)dn=23, total dis covered by both = 45d. Out of which A would have covered 2/5 *45d =18d So they meet at A.
Yah, first part was an aimcat question.. I remember it.
Second part, I got confused with one question here , so asked
Ok, so between each meeting point, they always travel 2*D distance ... always ? sure ?
What about the meeting sequence here ,
three distinct points -> 0m (A), C(20m from A), D(40 from A)... now what is the sequence of meeting ?
Next question: 8 m track AB, 3:5 ratio , 23rd meeting ?
@YouMadFellow said:@anupam001 @fisherking .. Help me with this QA question:Two guys start from A and B,which is 50 kms from A, and with speeds in the ratio 2:3. At how many distinct points will they meet and where will they meet for the 23rd time ?
mujhe bhi formula nai pata tha..assuming their speeds to be 2m/s and 3m/s..meeting points find kiye..
@aimingCAT12 said:mujhe bhi formula nai pata tha..assuming their speeds to be 2m/s and 3m/s..meeting points find kiye..
Haan, but isme sequence of meeting points dekho.. aur maine jo latest post pe question diya hai.. use bhi dekho ...
Each of the students Zoya, Kate, Frida and Latika appeared in an exam consisting of 4 subjects namely Optics, Life Sciences, Public Service and Finance. The following table indicates the marks obtained by them in the different subjects
Further, it is known that
1. No student obtained the same marks in any two subjects.
2. No two students obtained the same marks in any subject.
3. The aggregate of the marks in the four subjects, obtained by each student was different.
4. The aggregate of the marks obtained by the four students was different across the four subjects
q2)In which of the following subjects the aggregate marks obtained by all the four mentioned students can never be the maximum?
q1)The aggregate marks secured by Zoya, when Kate gets 7 marks in finance, is
q2)In which of the following subjects the aggregate marks obtained by all the four mentioned students can never be the maximum?
I. Life Sciences
II. Public Services
III. Finance
Q3) What is the aggregate of the marks obtained by the four students in Optics ?
@YouMadFellow said:Ok, so between each meeting point, they always travel 2*D distance ... always ? sure ?
Not if ratio of speeds is more than 1.5
@Angadbir said:Not if ratio of speeds is more than 1.5
In that case, what would we do ? Brute force method ? or some pattern ?
@YouMadFellow said:Yah, first part was an aimcat question.. I remember it.Second part, I got confused with one question here , so askedOk, so between each meeting point, they always travel 2*D distance ... always ? sure ?What about the meeting sequence here ,three distinct points -> 0m (A), C(20m from A), D(40 from A)... now what is the sequence of meeting ?Next question: 8 m track AB, 3:5 ratio , 23rd meeting ?
No not always. if the speed ratios are 1:10 then they won't cover a dist of 2d every meeting. because the first person won't reach the end of the track by the time he gets overlapped 😃 we'll have to do manually then.