ShoutBox (Part 1)

@viewpt said:
Q: in how many ways one can wear 3 rings on 5 finger?
Different rings or same rings? Different rings: 5*6*7 . 5 fingers to choose from, then once the 1st ring goes in, you have 6 positions to choose from, 4 of the remaining fingered and the two positions behind and in front of the 1st ring and so on.
:gm:
@ankita14 said:
ye kya hai
@miseera said:
@brixcel FB Deactivated
No More Time Waste
:gm:
@anupam001 said:
Smiley trying :lookround:
@ankita14 said:
Smiley trying
mai to jan 9 ko kar raha hun na iska trial :lookround:
@ankita14 said:
Different rings or same rings? Different rings: 5*6*7 . 5 fingers to choose from, then once the 1st ring goes in, you have 6 positions to choose from, 4 of the remaining fingered and the two positions behind and in front of the 1st ring and so on.
different cases can be considered all rings go to same finger, two on same finger , all three in different fingers
@ankita14 said:
Aise nhi

:gm: :gm: :gm: aise ;)
@viewpt said:
different cases can be considered all rings go to same finger, two on same finger , all three in different fingers
Yea I'm considering all of that :/
@miseera said:
Aise nhi
aise
Abhi utni khush nai hu :(
@viewpt said:
different cases can be considered all rings go to same finger, two on same finger , all three in different fingers
in essence ur saying rings arent different ???
@aimingCAT12 said:
ditch kar rahe ho sir aap! chalo jao..hum bhi jaate hai fir. alvida!
Arey main to bas thodi der ke liye gaya tha.. tum to chale hi gaye... Chitti na koi sandes.. jaane wo kounsa des.. jahan tum chale gaye... ! 😞
@viewpt said:
different cases can be considered all rings go to same finger, two on same finger , all three in different fingers
Similar rings hai to. A+b+c+d+e=3 solve 7c4=35
@ankita14 said:
Abhi utni khush nai hu
Ki hoya ?
@ankita14 said:
Similar rings hai to. A+b+c+d+e=3 solve 7c4=35
arey correct hai ..mai toh bas itna keh rha tha ke diff cases honge.
@Estallar12 said:
Ki hoya ?
Sab tumhara hi kiya dhara hai :nono:
@viewpt said:
different cases can be considered all rings go to same finger, two on same finger , all three in different fingers
very much safe to assume that rings are different when nothing is given .. so 5 * 6 * 7 = 210
@shashankg13 said:
If the 3 rings are different, we can select 3 places out of 15 in C(15,3) ways and then internally arrange the rings in 3! ways. So it comes to be C(15,3)*3! ways
If the rings are the same, It is C(15,3) ways
Is it ok?
15 places? :II
@ankita14 said:
Sab tumhara hi kiya dhara hai
What I do ?
@viewpt said:
arey correct hai ..mai toh bas itna keh rha tha ke diff cases honge.
Ha honge, lekin ek line mai sab ho raha hai to cases kyu le :mg: