Arey.. sirjee.. saare 4 digits pe Prob loge naa.. Distinct wale pe thodena loge! Ye kaisa shadyantra hai
Kyun ?? Question said - Find the probability of 4 digit numbers having distinct digits being divisible by 11. So, distinct pe hi toh niklega probability !! :splat:
Ek baar yeh dekho.. do you consider these two cases as different or same in this question ?
Arey.. Sirjee.. Ye JEE ka question nhi hai!! Basically.. here we are not talking abt Realtive Placements.. but just the distribution.. ab wo dono groups alag alag kamre me bhi to baith sakte hai.. So basically.. we just need to selct 7 people.. rest 8 will be selected themselves.. and then place both of them by (n-1)! ..
I guess, this can be correct explanation.. as far as my answer is correct! Koi answer to batao.. Khaali hawa me teer mar rhe hai sab!
Arey.. Sirjee.. Ye JEE ka question nhi hai!! Basically.. here we are not talking abt Realtive Placements.. but just the distribution.. ab wo dono groups alag alag kamre me bhi to baith sakte hai.. So basically.. we just need to selct 7 people.. rest 8 will be selected themselves.. and then place both of them by (n-1)! ..I guess, this can be correct explanation.. as far as my answer is correct! Koi answer to batao.. Khaali hawa me teer mar rhe hai sab!
Kyun ?? Question said - Find the probability of 4 digit numbers having distinct digits being divisible by 11. So, distinct pe hi toh niklega probability !!
My point: Here, the Favorable condition is being distinct integers.. but I guess prob should be found on all 4-Digit nos.. I guess.. It must be specified in the Question! Ye wala clear nhi hai! Leave it.. anyways.. Cases to aa hi gye hai! I better check with mine!
Arey.. Sirjee.. Ye JEE ka question nhi hai!! Basically.. here we are not talking abt Realtive Placements.. but just the distribution.. ab wo dono groups alag alag kamre me bhi to baith sakte hai.. So basically.. we just need to selct 7 people.. rest 8 will be selected themselves.. and then place both of them by (n-1)! ..I guess, this can be correct explanation.. as far as my answer is correct! Koi answer to batao.. Khaali hawa me teer mar rhe hai sab!
Dekho, obv mera pehla answer is (15!/7!*8!) * 6!*7! .. par maine yahan food for thought diya hai.. ki what will happen in such a case, where the two circles are nearby.. tab kya hoga.. ?
Tab har circle me normally jo (n-1)! hota hai.. wo apply hoga ya nahi ? Kyunki har ek position matters.. A and D in one case were not nearby, dusre me hai .. but dekha jaye to pehle circle ke ABC ka orientation same hai.. -> for the first circle, this is a redundant case..
My point: Here, the Favorable condition is being distinct integers.. but I guess prob should be found on all 4-Digit nos.. I guess.. It must be specified in the Question! Ye wala clear nhi hai! Leave it.. anyways.. Cases to aa hi gye hai! I better check with mine!
Here, if the favourable condition will be being distinct integers, then probability main divisibility by 11 nahin lag paega.
See, it could be done 2 ways. Ya toh distinct digits waale numbers pe nikaalo or do it using Conditional Probability if total possible numbers pe nikaalna hai toh.
Dekho, obv mera pehla answer is (15!/7!*8!) * 6!*7! .. par maine yahan food for thought diya hai.. ki what will happen in such a case, where the two circles are nearby.. tab kya hoga.. ?
Tab har circle me normally jo (n-1)! hota hai.. wo apply hoga ya nahi ? Kyunki har ek position matters.. A and D in one case were not nearby, dusre me hai .. but dekha jaye to pehle circle ke ABC ka orientation same hai.. -> for the first circle, this is a redundant case..
Dekho, obv mera pehla answer is (15!/7!*8!) * 6!*7! .. par maine yahan food for thought diya hai.. ki what will happen in such a case, where the two circles are nearby.. tab kya hoga.. ?
Tab har circle me normally jo (n-1)! hota hai.. wo apply hoga ya nahi ? Kyunki har ek position matters.. A and D in one case were not nearby, dusre me hai .. but dekha jaye to pehle circle ke ABC ka orientation same hai.. -> for the first circle, this is a redundant case..
haan agar.. Keval Distribution naa karna ho.. and Placements bhi dekhne ho.. to obv answer wud be totally different.. Wo to Deep Thought dena padega! hum aapki tarah BOND nhi hoon!