ShoutBox (Part 1)

set theory kahan se karun??? free ke question galat ho jaate hain har baar... :banghead: :splat:

@paridhi11890 said:
areee you quoted me..
:| and now that post no longer exist..
I think like SB(old) your post is also ephemeral 😞
I am same lay_man whom you know since SBhood days :sigh:
Yes! the same jolly, humorous, irritable, brainsick

Time to go nostalgic puys/pirls

@lay_man said:

Hail, lay_man!
@RoadKill @Estallar12 Yahan discuss kare ? No. of integral solns for abc = 27 :)
@YouMadFellow said:
@RoadKill @Estallar12 Yahan discuss kare ? No. of integral solns for abc = 27
Lol. :mg:

Btw he has changed th question. @Brooklyn - SB pe haaazir ho.!!
Question batao sahi se. :D
@Estallar12 Bas like mat karo... solution bhi batao kuch.. :(
@Estallar12 said:
Lol.
Btw he has changed th question. @Brooklyn - SB pe haaazir ho.!!
Question batao sahi se.
Haan changed question is abc = 27 .. Earlier it was abc = 42 .. Dono hi solve kar lete hai naa !
@YouMadFellow said:
Haan changed question is abc = 27 .. Earlier it was abc = 42 .. Dono hi solve kar lete hai naa !
Ab phir se abc = 42 kar diya hai Kaminey ne !! :P
Okay ruko..Lemme wind up 1 assignment here. :D

Copy pasting from PM sent to @YouMadFellow :


Solving for abc=42
abc = 2*3*7

I am expressing them as
a = 2^a1 * 3^a2 * 7^a3
b = 2^b1 * 3^b2 * 7^b3
c = 2^c1 * 3^c2 * 7^c3

Now a1+b1+c1 = 1 => there are 3C2 ways as they can each be greater than or equal to 0
Similarly, a2+b2+c2 =1 => 3 ways
a3+b3+c3 = 1=> 3 ways

Total 3*3*3 = 27 ways. Now, I think each of these 27 cases is distinct. E.g. a=2, b=3, c=7 will occur only once. Agar galti ho rahi hai kahin to yahi pe hogi I guess...

So in each of these 27, just select any 2 as negative nos, which can be done in 3c2 ways. Answer mera aaya 81.

EDIT: Add the all positive cases as well! Final aayega 81+27?

@paridhi11890 said:
@Estallar12 Bas like mat karo... solution bhi batao kuch..
Solution for Set Theory questions..?? TG has a good lesson on Set Theory under CAT 2012 Quant Lesons. So, woh kar lo :D
@YouMadFellow said:
Haan changed question is abc = 27 .. Earlier it was abc = 42 .. Dono hi solve kar lete hai naa !
a)10+30 =40
b)27+81=108
@RoadKill Arey yaar.. abhi tak main total solutions bol raha tha .. aur tu sirf negative solution !! uff ! I also got 27 + 81 and 10 + 30 :)
@YouMadFellow said:
@RoadKill Arey yaar.. abhi tak main total solutions bol raha tha .. aur tu sirf negative solution !! uff ! I also got 27 + 81 and 10 + 30
:thumbsup:
@Enigma001 said:
a)10+30 =40
b)27+81=108
@Brooklyn - Yahi OA hai na ? :D
Yes ppl 😁 😁 thnx to all :D
@Brooklyn said:
Yes ppl thnx to all
@RoadKill - This is especially for you as you solved 6 questions when he only asked for 2 of them :P
@YouMadFellow & @Enigma001 - :D
@RoadKill : sry bhai :)
People Copy Paste on GOOGLE :
2 sqrt(-abs(abs(x)-1)*abs(3-abs(x))/((abs(x)-1)*(3-abs(x))))(1+abs(abs(x)-3)/(abs(x)-3))sqrt(1-(x/7)^2)+(5+0.97(abs(x-.5)+abs(x+.5))-3(abs(x-.75)+abs(x+.75)))(1+abs(1-abs(x))/(1-abs(x))),-3sqrt(1-(x/7)^2)sqrt(abs(abs(x)-4)/(abs(x)-4)),abs(x/2)-0.0913722(x^2)-3+sqrt(1-(abs(abs(x)-2)-1)^2),(2.71052+(1.5-.5abs(x))-1.35526sqrt(4-(abs(x)-1)^2))sqrt(abs(abs(x)-1)/(abs(x)-1))+0.9
@reymyst619 said:
Stefan: She's better off without me? She's sure as Hell better off without you.
Damon: Fine. Neither one of us gets her !
:inlove: totally .. trst me.. he'll be the one:)
@saniyamakhijani said:
:inlove: totally .. trst me.. he'll be the one
And you`l be the second. He1s already with Nina Dobrev!


And waise bhi stay away...he`s a bad boy !