chalo all sb bhai log, 1:45 tak seriously pado......1:45 pe discuss karte he...
@tushar100p said: @mbajamesbond @yesarpit m in agreement.... yahi hu mai b aaj subah tk... aur sone jaao to bata dena... nai to @decentb
@tushar100p said: @mbajamesbond @yesarpit m in agreement.... yahi hu mai b aaj subah tk... aur sone jaao to bata dena... nai to
ok milte hai baad mein @tushar100p @yesarpit
@decentb said: @yesarpit :done dna dan done.....i ll report at 1:45 AM ...
@mbajamesbond @tushar100p .....@decentb .....
i learned these many things in past 45 mins:
1) anecdote : means : interesting story or unreliability
2) Naive : means : unexperienced :P
3) Gutted : means : Destroy completely
Also i completed qa 1307 review....what abt u guys....
i learned these many things in past 45 mins:
1) anecdote : means : interesting story or unreliability
2) Naive : means : unexperienced :P
3) Gutted : means : Destroy completely
Also i completed qa 1307 review....what abt u guys....
@yesarpit wao... nice work... working on having a concrete rc strategy... devised a few rules//
1. categorise the passage... if its descriptive or informative just read the questions and solve
2. focus on adjectives and see where the author is giving his own thoughts on the subject for inference based ques
3. go by the topic scope purpose method
@yesarpit said:@mbajamesbond @tushar100p .....@decentb .....i learned these many things in past 45 mins:1) anecdote : means : interesting story or unreliability 2) Naive : means : unexperienced 3) Gutted : means : Destroy completelyAlso i completed qa 1307 review....what abt u guys....
bhai main cl proc 1 phir se review kar raha tha...
@tushar100p said: @yesarpit wao... nice work... working on having a concrete rc strategy... devised a few rules//1. categorise the passage... if its descriptive or informative just read the questions and solve2. focus on adjectives and see where the author is giving his own thoughts on the subject for inference based ques3. go by the topic scope purpose method
Great work maccha...
can you please elaborate topic score method? or any link
can you please elaborate topic score method? or any link
@notimetowaste said: @reymyst619 thank you!@yesarpit you only come here and do velapanti
madam jee u have a motivating id...
@yesarpit :i ws reading some shortcuts...
If any parallelogram can be inscribed in a circle , it must be a rectangle.
If a quadrilateral circumscribes a circle , the sum of a pair of opposite sides is equal to the sum of the other pair .
The ratio of the radii of the circumcircle and incircle of an equilateral triangle is 2:1 .
for similar cones , ratio of radii = ratio of their bases.
the quadrilateral formed by joining the angular bisectors of another f a quadrilateral is always a rectangle.
Let W be any point inside a rectangle ABCD .
Then
WD^2 + WB^2 = WC^2 + WA^2
Let a be the side of an equilateral triangle . then if three circles be drawn inside
this triangle touching each other then each's radius = a/(2*(root(3)+1))
Area of a regular hexagon : root(3)*3/2*(side)*(side)
the area of a regular n-sided polygon of side 'a' is given by
area=(n/4)*a^2*cot(180/n)
In any triangle
a=b*CosC + c*CosB
b=c*CosA + a*CosC
c=a*CosB + b*CosA
------------------------------------------------------------
------------------------------------------------------------
If a+b+c+d=constant , then the product a^p * b^q * c^r * d^s will be maximum
if a/p = b/q = c/r = d/s .
------------------------------------------------------------
e^x = 1 + (x)/1! + (x^2)/2! + (x^3)/3! + ........to infinity
------------------------------------------------------------
(m+n)! is divisible by m! * n!
------------------------------------------------------------
for squares of numbers between 25 and 50.
let the number be 25+k
first calculate (25-k)^2 and to it add k*100
2)for squares of numbers between 50 and 75.
again let the number 50+k
calculate k^2 and to it add 2500+100*k
------------------------------------------------------------
3)for squares of numbers between 75 and 100
let the number be 100-k
calculate k^2 and to it add (100-2*k)*100
these formulas are basically a derivation from the formulas (a+b)^2 and (a-b)^2.
------------------------------------------------------------
2^2n -1 is always divisible by 3
2^2n -1 = (3-1)^2n -1
= 3M +1 -1
= 3M, thus divisible by 3
----------------------------------
if a number 'n' is represented as
n=a^x * b^y * c^z ....
where, {a,b,c,.. } are prime numbers then
Quote:
(a) the total number of factors is (x+1)(y+1)(z+1) ....
(b) the total number of relatively prime numbers less than the number is n * (1-1/a) * (1-1/b) * (1-1/c).... ???????????????????
(c) the sum of relatively prime numbers less than the number is n/2 * n * (1-1/a) * (1-1/b) * (1-1/c)....
(d) the sum of factors of the number is {a^(x+1)} * {b^(y+1)} * ...../(x*y*...)
-----------------------------------------
what is the highest power of 10 in 203!ANS : express 10 as product of primes; 10 = 2*5
divide 203 with 2 and 5 individually
203/2 = 101
101/2 = 50
50/2 = 25
25/2 = 12
12/2 = 6
6/2 = 3
3/2 = 1
thus power of 2 in 203! is, 101 + 50 + 25 + 12 + 6 + 3 + 1 = 198
divide 203 with 5
203/5 = 40
40/5 = 8
8/5 = 1
thus power of 5 in 203! is, 49
so the power of 10 in 203! factorial is 49
------------------------------------------------------
n how many ways, 729 can be expressed as a difference of 2 squares?
ANS: 729 = a^2 - b^2
= (a-b)(a+b),
since 729 = 3^5,
total ways of getting 729 are, 1*729, 3*243, 9*81, 27*27.
So 4 ways
Funda is that, all four ways of expressing can be used to findout distinct a,b values,
for example take 9*81
now since 9*81 = (a-b)(a+b) by solving the system a-b = 9 and a+b = 81 we can have 45,36 as soln.
--------------------------------------
if x%a=y%a = r then
(x-y)%r =0 (% stands for modulo operator)
---------------------------------------------
total number of primes between 1 and 100 - 25
----------------------------------------------
If any parallelogram can be inscribed in a circle , it must be a rectangle.
If a quadrilateral circumscribes a circle , the sum of a pair of opposite sides is equal to the sum of the other pair .
The ratio of the radii of the circumcircle and incircle of an equilateral triangle is 2:1 .
for similar cones , ratio of radii = ratio of their bases.
the quadrilateral formed by joining the angular bisectors of another f a quadrilateral is always a rectangle.
Let W be any point inside a rectangle ABCD .
Then
WD^2 + WB^2 = WC^2 + WA^2
Let a be the side of an equilateral triangle . then if three circles be drawn inside
this triangle touching each other then each's radius = a/(2*(root(3)+1))
Area of a regular hexagon : root(3)*3/2*(side)*(side)
the area of a regular n-sided polygon of side 'a' is given by
area=(n/4)*a^2*cot(180/n)
In any triangle
a=b*CosC + c*CosB
b=c*CosA + a*CosC
c=a*CosB + b*CosA
------------------------------------------------------------
------------------------------------------------------------
If a+b+c+d=constant , then the product a^p * b^q * c^r * d^s will be maximum
if a/p = b/q = c/r = d/s .
------------------------------------------------------------
e^x = 1 + (x)/1! + (x^2)/2! + (x^3)/3! + ........to infinity
------------------------------------------------------------
(m+n)! is divisible by m! * n!
------------------------------------------------------------
for squares of numbers between 25 and 50.
let the number be 25+k
first calculate (25-k)^2 and to it add k*100
2)for squares of numbers between 50 and 75.
again let the number 50+k
calculate k^2 and to it add 2500+100*k
------------------------------------------------------------
3)for squares of numbers between 75 and 100
let the number be 100-k
calculate k^2 and to it add (100-2*k)*100
these formulas are basically a derivation from the formulas (a+b)^2 and (a-b)^2.
------------------------------------------------------------
2^2n -1 is always divisible by 3
2^2n -1 = (3-1)^2n -1
= 3M +1 -1
= 3M, thus divisible by 3
----------------------------------
if a number 'n' is represented as
n=a^x * b^y * c^z ....
where, {a,b,c,.. } are prime numbers then
Quote:
(a) the total number of factors is (x+1)(y+1)(z+1) ....
(b) the total number of relatively prime numbers less than the number is n * (1-1/a) * (1-1/b) * (1-1/c).... ???????????????????
(c) the sum of relatively prime numbers less than the number is n/2 * n * (1-1/a) * (1-1/b) * (1-1/c)....
(d) the sum of factors of the number is {a^(x+1)} * {b^(y+1)} * ...../(x*y*...)
-----------------------------------------
what is the highest power of 10 in 203!ANS : express 10 as product of primes; 10 = 2*5
divide 203 with 2 and 5 individually
203/2 = 101
101/2 = 50
50/2 = 25
25/2 = 12
12/2 = 6
6/2 = 3
3/2 = 1
thus power of 2 in 203! is, 101 + 50 + 25 + 12 + 6 + 3 + 1 = 198
divide 203 with 5
203/5 = 40
40/5 = 8
8/5 = 1
thus power of 5 in 203! is, 49
so the power of 10 in 203! factorial is 49
------------------------------------------------------
n how many ways, 729 can be expressed as a difference of 2 squares?
ANS: 729 = a^2 - b^2
= (a-b)(a+b),
since 729 = 3^5,
total ways of getting 729 are, 1*729, 3*243, 9*81, 27*27.
So 4 ways
Funda is that, all four ways of expressing can be used to findout distinct a,b values,
for example take 9*81
now since 9*81 = (a-b)(a+b) by solving the system a-b = 9 and a+b = 81 we can have 45,36 as soln.
--------------------------------------
if x%a=y%a = r then
(x-y)%r =0 (% stands for modulo operator)
---------------------------------------------
total number of primes between 1 and 100 - 25
----------------------------------------------
@tushar100p bhai bhaut addictive hai yaar
roz sochta hu ki ab nhi khelounga but...."dil toh Baccha hai ji"
sir mat bolo yaar plz
@gudda1122 said: @yesarpit bhai main FB pool khel rha hu last 1 hour se
Gudda saar......aap to badhshaah ho...
I know you are one of the quant thread heroes here....hum garib logo ko kuch batado yaar....kaise score improve kare? Aapne kaise improve kiya? i am struggling to clear cutoff for quants :(
I know you are one of the quant thread heroes here....hum garib logo ko kuch batado yaar....kaise score improve kare? Aapne kaise improve kiya? i am struggling to clear cutoff for quants :(
@yesarpit
topic--- to answer questions of title, main idea, central theme etc...
scope-- to answer questions based on tone of the author
puprose-- used for inference and implied idea questions
i had read it somewhere... dont remember where... ill try to find the link if i can...
@gudda1122 okay... but sirjee to bol skte h.. n @yesarpit bhaiya aapko saar keh rhe h... meko hi daanto sab... 
@yesarpit said:Gudda saar......aap to badhshaah ho... I know you are one of the quant thread heroes here....hum garib logo ko kuch batado yaar....kaise score improve kare? Aapne kaise improve kiya? i am struggling to clear cutoff for quants
bhai kuch nhi aata h QA mein maje mat lo 
bhai apne aap ho jati hai yaar
DI sahi karna bas pakka se....usse kafi kaam ban ajyega
and bhai bas last tak fight maarna bcoz CAT k paper mein n Mocks mein kafi difference hota hai....
+Arun sharma aur kar lo...
@decentb said: @yesarpit :i ws reading some shortcuts... If any parallelogram can be inscribed in a circle , it must be a rectangle.If a quadrilateral circumscribes a circle , the sum of a pair of opposite sides is equal to the sum of the other pair .The ratio of the radii of the circumcircle and incircle of an equilateral
waise yeh main galat thread par aa gaya hu
ya galat thread par post kar diya hai????
@gudda1122 said:bhai kuch nhi aata h QA mein maje mat lobhai apne aap ho jati hai yaarDI sahi karna bas pakka se....usse kafi kaam ban ajyegaand bhai bas last tak fight maarna bcoz CAT k paper mein n Mocks mein kafi difference hota hai....+Arun sharma aur kar lo...waise yeh main galat thread par aa gaya huya galat thread par post kar diya hai????
Thanks bade.....
Aap sahi post pe ho.....sboxers sab serious he aajkal.......
Aap sahi post pe ho.....sboxers sab serious he aajkal.......