ShoutBox (Part 1)

Jobs & Careers
26274
@hanushanand said:
ye Abhimukh sir ne maara tha.. .. mere ko to padhne se fursat nhi hai.. 21 morning ka bhi plan kar rakha hai..
aisa kya padh rahe ho :splat: kuch use aaye to batana mereko :P
26275
@Brooklyn said:
Dagny's purse contains 4 coins which can be 1Rs coins or 5Rs coins. 2 coins are drawn and are both found to be 5Rs coins. If the coins are replaced and an another coin is drawn, what is the probability that it is a 1Rs coin ?Aprraoch too
There are already two 5 Rs Coins..

-> The other two coins can be 1,1 or 1,5 or 5,5

Case 1: (1,1)

P(1 is picked) = P(1,1) * P(picking up 1 from 4) = 1/4*[ 2/4] = 1/8

Case 2: (1,5)

P(1 is picked) = P(1,5)*P(picking up 1 from 4) = 2/4*[1/4] = 1/8

case 3: (5,5)

P(1 is picked) = 0

So, P = 1/4 ?

I am weak in P n C 😞 ..
26276
@YouMadFellow said:
There are already two 5 Rs Coins..-> The other two coins can be 1,1 or 1,5 or 5,5Case 1: (1,1)P(1 is picked) = P(1,1) * P(picking up 1 from 4) = 1/4*[ 2/4] = 1/8Case 2: (1,5)P(1 is picked) = P(1,5)*P(picking up 1 from 4) = 2/4*[1/4] = 1/8 case 3: (5,5)P(1 is picked) = 0So, P = 1/4 ? I am weak in P n C ..
mera vi yahi aaya OA ye nhi tha :(
26277
@YouMadFellow said:
I am weak in P n C ..
Aap kaise?? Aap to topper the..
26278
@Brooklyn to kya hai OA bhai ?
26279
@YouMadFellow said:
There are already two 5 Rs Coins..-> The other two coins can be 1,1 or 1,5 or 5,5Case 1: (1,1)P(1 is picked) = P(1,1) * P(picking up 1 from 4) = 1/4*[ 2/4] = 1/8Case 2: (1,5)P(1 is picked) = P(1,5)*P(picking up 1 from 4) = 2/4*[1/4] = 1/8 case 3: (5,5)P(1 is picked) = 0So, P = 1/4 ? I am weak in P n C ..
weak :angry::sneaky:
26280
@anupam001 said:
weak
Arey weak hu bhai.. dekho answer galat hai !
26281
@YouMadFellow said:
@Brooklyn to kya hai OA bhai ?
1/8 pta nhi kaise aaya :(
26282

quants pad lo bas ....its the only thing that will determine ur rank

26283
@Brooklyn said:
1/8 pta nhi kaise aaya
OA ??
26284
@hanushanand Kounsa topper bhai :splat: ..
26285
@YouMadFellow said:
@hanushanand Kounsa topper bhai ..
jee! ((_0______//
26286
http://www.facebook.com/photo.php?v=233542483440492
26287
@Brooklyn Solution de do bhai ! 1/8 to half of the answer hai.. Nahi chamak raha .. kaise aayega.. maine to prudently follow kiye the steps 😞 .. par kat gaya mera !
26288
@abhimukh19 said:
26289
@YouMadFellow said:
@Brooklyn to kya hai OA bhai ?
@Brooklyn said:
1/8 pta nhi kaise aaya
O.A was wrong answer 1/4 hi h
1/8 to samjh mai hi nahi aarha kese aayga?
three cases
remaing coins were 1,1 both
5 ,5
and 1,5
26290
@hanushanand said:
Arey yaar.. us ladki pe dil aa gaya tha mera.. ab wapas aa gaya :splat: :thumbsup:
26291
@sameersapre23 said:
O.A was wrong answer 1/4 hi h1/8 to samjh mai hi nahi aarha kese aayga?three casesremaing coins were 1,1 both5 ,5and 1,5
@Brooklyn :angry: >. !!
26292
@Brooklyn said:
Dagny's purse contains 4 coins which can be 1Rs coins or 5Rs coins. 2 coins are drawn and are both found to be 5Rs coins. If the coins are replaced and an another coin is drawn, what is the probability that it is a 1Rs coin ?Aprraoch too
P(A/B) = P(A(intersection)B)/P(B)

A - prob to get 1
B - Prob to get 2 - 5's (min)

Possible cases -
1111, 1115, 1155, 1555, 5555

P(B) = Case 1 - 1155 - 1/5 * 1/6
Case 2 - 1555 - 1/5 * 3/6
Case 3 - 5555 - 1/5 * 1

= 1/3

P(A(intersection)B)

Case - 1 ----> 1155 - 1/5*1/6*1/2
Case - 2 ----> 1555 - 1/5*1/2*1/4

P(A/B) = [1/2*1/5 (1/6 + 1/4)] / [1/3] = 1/8


26293
@YouMadFellow said: