@hanushanand said:Yo Dude, Its the MAHA-ASUR style! Gives me edge over DAYANS! Marketing stunt hai yaar .. samjha karo!
Few days left for Ramlila. Prepaing well... BU HAHAHAHA
@hanushanand said:Yo Dude, Its the MAHA-ASUR style! Gives me edge over DAYANS! Marketing stunt hai yaar .. samjha karo!
oh fir thik hai. 
BUHAHAHAHAHA!!!
promotion kar raha hoon :mg:
@abhibeloved said:oh fir thik hai. BUHAHAHAHAHA!!!promotion kar raha hoon
aaj kal waise b prepration se jyada promotion pe dhyan dena padta hai... 
@hanushanand
yaar now a days RAVAN'S HU/BUhahahaha wont fetch u more customers.....
u shud go for hihihihihihihihih...
yaar now a days RAVAN'S HU/BUhahahaha wont fetch u more customers.....
u shud go for hihihihihihihihih...
@lihs.niaj91 said:@hanushanandyaar now a days RAVAN'S HU/BUhahahaha wont fetch u more customers.....u shud go for hihihihihihihihih...
tum log RAAVAN ka majak uda rahe ho.... isse kya Abhishek Bachan samjh rakha hai...?
@lihs.niaj91 said:@hanushanandyaar now a days RAVAN'S HU/BUhahahaha wont fetch u more customers.....u shud go for hihihihihihihihih...
I don't know what he used to do.. neither do you! 
Hence, its MY signature style.. 
I gotta get my Patent! 
Hence, its MY signature style.. I gotta get my Patent! RA.One
@maddy2807 said:tum log RAAVAN ka majak uda rahe ho.... isse kya Abhishek Bachan samjh rakha hai...?
@maddy2807
yar vo RAvan tha tbi to mazak b udaya ja sakta hai.....
koi mazak(AB) ka mazak kaise udaya ja sakta hai????
yar vo RAvan tha tbi to mazak b udaya ja sakta hai.....
koi mazak(AB) ka mazak kaise udaya ja sakta hai????
@lihs.niaj91 said:@maddy2807yar vo RAvan tha tbi to mazak b udaya ja sakta hai.....koi mazak(AB) ka mazak kaise udaya ja sakta hai????
sahi baat hai... uska majak to har movie me udta hi hai... Dosti se le kar Bolbachan tak...
@sameersapre23 said:In a 400 metres race, A gives B start of 5 seconds and beats him by 15m. In another race of 400 metres, A beats B by 50/7 seconds, find their speeds.please solve this and give me ur approach as well....!!
I did it by longer method.... Assume A finisher race in time t with speed = A..then B finishes 400 m in t + 50/7 in second case.
eq1. t/ (t + 50/7 ) = B/ A
in first case A finishes 400 m in same t and b completes 385 m in t+5
eq.2 At / B(t+5) = 400/ 385
from 1 and 2 we get t = 50.
Speed A = 8
Speed B = 7
I may be wrong though as i did calculation in hurry.
eq1. t/ (t + 50/7 ) = B/ A
in first case A finishes 400 m in same t and b completes 385 m in t+5
eq.2 At / B(t+5) = 400/ 385
from 1 and 2 we get t = 50.
Speed A = 8
Speed B = 7
I may be wrong though as i did calculation in hurry.
@sameersapre23 said:In a 400 metres race, A gives B start of 5 seconds and beats him by 15m. In another race of 400 metres, A beats B by 50/7 seconds, find their speeds.please solve this and give me ur approach as well....!!
Let time taken by A in first race be t. Then in t+5 seconds, B could only get to the 400-15 = 385 m point. If the speeds are A and B, we get..
t+5 = 385/B
=>(400/A)+5=385/B
In the second race, 400/B - 400/A = 50/7
Eliminating 400/A, we get
5+400/B = 385/B + 50/7
=> 15/B = 15/7
=> B = 7 m/s
A will be 8 m/s.
Using options might also help.. Once you get the equations, put in values from options and see. Of course, here even solving the equations is pretty straightforward.
@sameersapre23
A beats B in a normal 400m race by 50/7 secs...
A beats B in a normal 400m race by 50/7 secs...
After giving a 5 sec headstart, A beats B by 15m...
Thus, B takes ((50/7) - 5) secs to finish-off the remaining 15m..
Therefore, Speed of B = 7 m/s... (15/ ((50/7)-5))
B takes 400/7 = x + (50/7) secs to complete 400m...., where x is the time taken by A to finish the full race.
Solving, x = 50 secs...
A's speed = 400/50 = 8 m/s
P.S. Quant is my weak area and thus I am not at all sure whether the above approach is right or wrong.....
If I am wrong..., please correct me.....
Thus, B takes ((50/7) - 5) secs to finish-off the remaining 15m..
Therefore, Speed of B = 7 m/s... (15/ ((50/7)-5))
B takes 400/7 = x + (50/7) secs to complete 400m...., where x is the time taken by A to finish the full race.
Solving, x = 50 secs...
A's speed = 400/50 = 8 m/s
P.S. Quant is my weak area and thus I am not at all sure whether the above approach is right or wrong.....
If I am wrong..., please correct me.....
@sameersapre23 said:In a 400 metres race, A gives B start of 5 seconds and beats him by 15m. In another race of 400 metres, A beats B by 50/7 seconds, find their speeds.please solve this and give me ur approach as well....!!
Speeds of A and B be a, b
400/ ( 400- 5b -15) = a/b = 400/(400-50b/7) [Equating the ratio of speeds]
=> 50b/7 = 5b + 15 => b = 7 m/s
Put this on the ratio above, get a = 8 m/s ..
find remainder when [ (9999.....(400! times))!^21] / (2222........(22! times))! ]
@hanushanand said:find remainder when [ (9999.....(400! times))!^21] / (2222........(22! times))! ] @YouMadFellow, @aimingCAT12 , @RoadKill , @Ibanez , @fisherking
abe kya kyu kaise bhai...
itna atyachaar...CAT mushkil kya sunlia...tum toh pagal hi hogaye hoon...:O :O
@hanushanand said:find remainder when [ (9999.....(400! times))!^21] / (2222........(22! times))! ] @YouMadFellow, @aimingCAT12 , @RoadKill , @Ibanez , @fisherking
waise ans 1 hoga if i m not wrng??
@nits2811 said:abe kya kyu kaise bhai...itna atyachaar...CAT mushkil kya sunlia...tum toh pagal hi hogaye hoon...
