@saniyamakhijani said:voh toh @Estallar12
Doft Nhi ho Meri you doft 
Mai Kitna Blush hu or Vehryy Bad
Vehryy Bad @techsurge said:bhai iski roots to imaginary aa rahi hainand new eqn coming i sax+b*sqrt(x)+c
roots toh imaginary nahi hongi..if we do by conventional method we find sum and product of roots,
Sum= a^2 + b^2 = (a+b)^ - 2ab = (3/2)^2 -2 = 1/4
and produt of roots= a^2b^2 =(ab)^2= 1
so the eqn will be x^2 - x/4 +1 =0 -> 4x^2 -x + 4=0
But Im not getting this eqn by applying that property of replacing x with root(x). That's the doubt.
Sum= a^2 + b^2 = (a+b)^ - 2ab = (3/2)^2 -2 = 1/4
and produt of roots= a^2b^2 =(ab)^2= 1
so the eqn will be x^2 - x/4 +1 =0 -> 4x^2 -x + 4=0
But Im not getting this eqn by applying that property of replacing x with root(x). That's the doubt.
@bluechameleon18 wat abt
or zindagi ki yahi reet hai,haar ke baad hi jeet hai
창€œEvery person can, if he so desires, become the sculptor of his own brain"
@Ibanez said:yeah I did that by finding sum and produt of roots too. But I want you to apply that property and then get to this?
basically..
2(rootx)^2 - 3(root x) + 2 = 0
2 x + 2 = 3 (root x)
Squaring both sides!
4x^2+8x+4=9x
4x^2-x+4=0
but D
2(rootx)^2 - 3(root x) + 2 = 0
2 x + 2 = 3 (root x)
Squaring both sides!
4x^2+8x+4=9x
4x^2-x+4=0
but D@Ibanez said:yeah I did that by finding sum and produt of roots too. But I want you to apply that property and then get to this?
2x - 3*root(x) + 2 = 0
2x + 2 = 3*root(x)
Squaring both the sides, get the result
@frostie said:ussi ko apply karo...and square both sides.
square karne pe bhi nahi aa rahi. root(x) wala term nahi hatega :S it will lead to x^4 terms if ew square again.
@lopagargg said:@bluechameleon18 wat abtor zindagi ki yahi reet hai,haar ke baad hi jeet hai창€œEvery person can, if he so desires, become the sculptor of his own brain"
Only if you promise to change your modal smiley 😛 :P
Edit:: Me n my poor stats.. Surprised that (one of) the resident economist(s) @saniyamakhijani missed it too :P
@Ibanez said:square karne pe bhi nahi aa rahi. root(x) wala term nahi hatega :S it will lead to x^4 terms if ew square again.
2x + 2 = 3rt(x)
Now square both sides.
@YouMadFellow said:2x - 3*root(x) + 2 = 02x + 2 = 3*root(x)Squaring both the sides, get the result
yes
I was squaring the wrong terms. What's wrong with me
I was squaring the wrong terms. What's wrong with meabh jaake thodi padhai ho rahi hai shout box mein. Shaam se masti ho rahi hai yahan pe!
@saniyamakhijani said:@miseera --rofll.. nai nai.. @sabrinakhan jii ke baare mei
doft you don't know she is the biggest chudel mere peeche padi rahti h
mere peeche padi rahti h @hanushanand said:
tum sar phodte raho...tumhe nahi bataane wali. Yeh @YouMadFellow aur mere beech ka joke hai 
@miseera said:doft you don't know she is the biggest chudel mere peeche padi rahti h
mafti karte honge.. but sabrinaji ke liye:nono: chalo tc ..tataz all:)