ShoutBox (Part 1)

Jobs & Careers
22189
@ashishpai2001 said:
OPTIONS
220/221 option se kiya par sahi hona chahiye :P
22190
@anupam001 said:
220/221 option se kiya par sahi hona chahiye
Yeh options se karne wala method samjhao toh zara
22191
@ashishpai2001 said:
OPTIONS
Last? Sirf options dekh kar :splat:
22192
@ashishpai2001 Kal 86 wala bataiye :sneaky:
22193
@ashishpai2001 said:
Yeh options se karne wala method samjhao toh zara
sum of first term 4/5 sum of first 2 is 12/13...ab n-1/n hi aana hai :mg:
22194
@ashishpai2001 said:
OPTIONS
220/221 ?

The 1st term 4/5=0.8
There are just 2 options just above 0.8 . And one of the options can be eliminated if we take the next few terms also.
22195
@ankita14 said:
@ashishpai2001 Kal 86 wala bataiye
:O

5 rows of 10 rods, and 4 rows of 9 rods in the voids. Aisa mere samjh me aaya hai, so you try it too...
22196
Let ABC be a triangle such that AB = AC. Let I be its in-centre. If BC = AB + AI, find ∠BAC.
OPTIONS
1) 45°
2) 90°
3) 120°
4) None of the above
22197
@tequierocr7 said:
@fisherking Sir 23min ho gye but aap abhi tk gaye ni sone......
Aapko raat main reply likhte hue net chala gaya aur phir vapas hi nahi aaya
22198

@fisherking said:
Aapko raat main reply likhte hue net chala gaya aur phir vapas hi nahi aaya
ohh..... Vaise lidhr chla gya tha aapka net..... ??..
22199
@ashishpai2001 said:
Let ABC be a triangle such that AB = AC. Let I be its in-centre. If BC = AB + AI, find ∠BAC.
OPTIONS
1) 45°
2) 90°
3) 120°
4) None of the above

samajh nahi aa raha..BC=AB+BI nahi aa raha kaise bhi :angry:...@Estallar12 @ashishpai2001 samjhao :splat:
22200
@ashishpai2001 said:
Let ABC be a triangle such that AB = AC. Let I be its in-centre. If BC = AB + AI, find ˆ BAC.

90??
22201
@ashishpai2001 said:
Let ABC be a triangle such that AB = AC. Let I be its in-centre. If BC = AB + AI, find ∠BAC.
OPTIONS
1) 45°
2) 90°
3) 120°
4) None of the above
90 degrees ko Lock kiya jaaye :mg:
22202
@Estallar12 said:
90 degrees ko Lock kiya jaaye
method likha jaaye :angry:
22203
@anupam001 said:
method likha jaaye
Diagram banaya jaa raha hai. :P
22204
@Estallar12 said:
@RoadKill - And woh bachpan ka Pic lagaane se pehle main bhi "your Avatar" lagaane waala tha. I guess text was not written in that GIF but the rest part was same. But laga nahin woh tab.
Bina onoz (z)omg ke wo avatar hai hi Kya ^_^
22205
@ashishpai2001 said:
Let ABC be a triangle such that AB = AC. Let I be its in-centre. If BC = AB + AI, find ∠BAC.
OPTIONS
1) 45°
2) 90°
3) 120°
4) None of the above
2)90 ??
22206
@fisherking said:
2)90 ??
90 hi hai but humne option daal daal ke kiya..kuch bhi nahi ho raha sahi se :banghead:
22207
@anupam001 said:
method likha jaaye
I first checked for 90 as it seemed most likely
Let AB=AC=a.Then BC=sqrt(2)*a
inradius=(a/2)*(2-sqrt(2))(by r=area/semi perimeter)
Let the point the incircle touches AC be D and its length be x.
Then by property of equal tangents from same point
x=(a/2)*(2-sqrt(2))
By Pythagoras
AI^2=ID(inradius)^2+AD^2
AI=a*(sqrt(2)-1)
AB+AI=sqrt(2)*a=BC
Hence answer :P

22208
@fisherking said:
Let AB=AC=a.Then BC=sqrt(2)*a
inradius=(a/2)*(2-sqrt(2))(by r=area/semi perimeter) Let the point the incircle touches AC be D and its length be x. Then by property of equal tangents from same point x=(a/2)*(2-sqrt(2)) By Pythagoras AI^2=ID(inradius)^2+AD^2 AI=a*(sqrt(2)-1) AB+AI=sqrt(2)*a=BC Hence answer
ye to 90 degree assume karke kiya hai aise humne kar liya :P