@Brooklyn i also made a mistake 1st time multiplied 5 with 111111 :P
@ankita14 said:Kitna method yaad rakhenge jo aaram se ho raha hai uske liye formula kyu yaad rakhu.
VA ke liye tips any???
sab moh maaya hai.@ankita14 said:;splat: tips bolke kuch nai hota sab moh maaya hai.
abe bole to wat ru doing dese last days as prep for VA?
Ok try this:
The first train to A leaves at 6:00 in the morning and there is a train to A after every 10 mins. First Train to B leaves at 6:06 in the morning and then there is train leaving for B every 10 minutes. Tom arrives to station any time between 10:00 AM to 11:00 AM every day and takes the first train that comes. what is the probaility that he will go to B on a given day? (assume there are only two trains one to A, other to B that come on Tom's platform)
@Brooklyn said:abe bole to wat ru doing dese last days as prep for VA?
Only the mocks 😞 will do cat questions in the last 2-3 days
@Angadbir said:Ok try this:
The first train to A leaves at 6:00 in the morning and there is a train to A after every 10 mins. first Train to B leaves at 7:06 in the morning and then there is train leaving for B every 10 minutes. Tom arrives to station any time between 10:00 AM to 11:00 AM every day and takes the first train that comes. what is the probaility that he will go to B on a given day? (assume there are only two trains A,B that come on Tom's platform)
6/13?
@Angadbir said:Ok try this:
The first train to A leaves at 6:00 in the morning and there is a train to A after every 10 mins. First Train to B leaves at 7:06 in the morning and then there is train leaving for B every 10 minutes. Tom arrives to station any time between 10:00 AM to 11:00 AM every day and takes the first train that comes. what is the probaility that he will go to B on a given day? (assume there are only two trains one to A, other to B that come on Tom's platform)
6/13...??..
@Angadbir said:Ok try this:
The first train to A leaves at 6:00 in the morning and there is a train to A after every 10 mins. First Train to B leaves at 7:06 in the morning and then there is train leaving for B every 10 minutes. Tom arrives to station any time between 10:00 AM to 11:00 AM every day and takes the first train that comes. what is the probaility that he will go to B on a given day? (assume there are only two trains one to A, other to B that come on Tom's platform)
Im getting 6/12 = 1/2 if u don't consider the 10:00AM waali train...ekdum se toh nai chadega 
warna..6/13..answer?
How to solve this question? Thanks.
In a Mock LSAT Paper, 6 multiple-choice questions were asked which are numbered 1 to 6 & whose answers are one among A, B, C or D. 3 students P, Q, R gave responses to these 6 questions in that order as ABCDCA, CAABBC & DBACBC. Also, all 3 of them gave 3 correct answers each and each question is given a correct answer by at least one student.
The correct response of which of the questions can be determined?
a) 2nd b) 3rd c) 5th d) 6th
@deedeedudu said:6/13?
@tequierocr7 said:6/13...??..
There are 6 out of 13 trains that leave for B. Sure, but what about the fact that given a time of his arrival to the station, he boards the train that comes first!!!
eg, if he just after 10AM, he boards the train to B, but not the train to A that leaves at 10:00AM.
Try considering 'time' as the sample space.
@Angadbir said:Ok try this:
The first train to A leaves at 6:00 in the morning and there is a train to A after every 10 mins. First Train to B leaves at 7:06 in the morning and then there is train leaving for B every 10 minutes. Tom arrives to station any time between 10:00 AM to 11:00 AM every day and takes the first train that comes. what is the probaility that he will go to B on a given day? (assume there are only two trains one to A, other to B that come on Tom's platform)
Between 10:00AM - 11:00AM (10 and 11 not included)
10:01,02,03,04,05,06 - Train B
10:07,08,09,10 - train A
6*6/59 = 36/59?
@frostie said:Im getting 6/12 = 1/2 if u don't consider the 10:00AM waali train...ekdum se toh nai chadegawarna..6/13..answer?
@MI8888 said:Between 10:00AM - 11:00AM (10 and 11 not included)10:01,02,03,04,05,06 - Train B10:07,08,09,10 - train A6*6/59 = 36/59?
He arrives between 10AM and 11AM, so 10AM train cannot be included, but 11 AM train can be.
Answer aint 1/2 or 6/13 or 36/59 
@Angadbir said:There are 6 out of 13 trains that leave for B. Sure, but what about the fact that given a time of his arrival to the station, he boards the train that comes first!!!eg, if he arrives 10AM, he boards the train to A, but not the train to B that leaves at 10:06AM.Try considering 'time' as the sample space.
3/5.....??..
@Angadbir said:10AM and 11AM trains can be included.Answer aint 1/2 or 6/13 or 36/59
3/5 OR 36/61 ?? 
@tequierocr7 said:3/5.....??..
@MI8888 said:3/5 OR 36/61 ??
3/5 is correct 
@deedeedudu said:2/5?
2/5 hoga prob of him going to A. So for B, it is 1-2/5 = 3/5
@Angadbir said:3/5 is correct2/5 hoga prob of him going to A. So for B, it is 1-2/5 = 3/5
logic dena sir
Guys CL wale bol re hai old CAT papers karo
@Brooklyn said:logic dena sir
He arrives between 10AM and 11AM.
Divide the time period into brackets of 10 mins each..
Take first such bracket 10:00 ?>?>
If Tom arrives at first 6/10th of time period t, he goes to B, else he goes to A
Since all 6 brackets of 10 mins each are similar.,, cumulative prob = 6/10