ShoutBox (Part 1)

@ashishpai2001 said:
AD||EC, DE||BC 2/x = y/4
xy=8
1/2xysin30 = 2
Correct.
@ankita14 said:
Nahi pooch lo usse, meri wajah se uski zindagi mai khushiyo ki bahaar hai
iska kya mtlb nikalu mai??? ;)

khushiyo ki bahaar hai πŸ˜› :P

aisa kya kiya hai ?? πŸ˜‰ :)

Haal kaisa hai janaab ka.... S S S

Kya khayaal hai aapka.... S S S

Chalo Ciao all.


Mock deta huun ek.
@ashishpai2001 - CPLC ke 8 ya 9 diye ho ?
@ankita14 said:
Nahi pooch lo usse, meri wajah se uski zindagi mai khushiyo ki bahaar hai
:clap:
:O
:P

@Estallar12 any comments?

@anupam001 said:
hum goli maar diya hun dono ko
Oo log kabka marr chuke bevkuf :p
@bluechameleon18 said:
@Estallar12 any comments?
aapko loke mode se nikalna hi pada :mg:...aur bato kaisi chal rahi hai catting shatting :D:D
@Estallar12 Tell me,


@karl said:
If x lies between ( β‚¬β€œ7) and 13, then find the greatest possible value of (13 β‚¬β€œ x)7(x + 7)3.
observe that sum of all the terms containing x is constant (13-x)+(x+7) =20. Hence their product will be maximum when they both are equal i.e =20/2 =10 hence at x=3 the value would be greatest.

=10*7*10*3 =2100

ATDH.
@ankita14 said:
Oo log kabka marr chuke bevkuf
Madam unki aatmaye Prometric waalo ne botal mei band kar li hain!!

CAT mei computerwa mei chord dete hain kabhi kabhi..!!
@anytomdickandhary said:
observe that sum of all the terms containing x is constant (13-x)+(x+7) =20. Hence their product will be maximum when they both are equal i.e =20/2 =10 hence at x=3 the value would be greatest.
=10*7*10*3 =2100
ATDH.
Lol. Sir, that was (13-x)^7 * (x+7)^3 :P
@anytomdickandhary said:
observe that sum of all the terms containing x is constant (13-x)+(x+7) =20. Hence their product will be maximum when they both are equal i.e =20/2 =10 hence at x=3 the value would be greatest.
=10*7*10*3 =2100
ATDH.
gm sirji :)
@ashishpai2001 said:
@Estallar12 Tell me,
:clap:
@ashishpai2001 said:
@Estallar12 Tell me,
Abbe jaldi batao CPLC ke 8 aur 9 main se koi diya hai ?
True dat !!


@anytomdickandhary said:
observe that sum of all the terms containing x is constant (13-x)+(x+7) =20. Hence their product will be maximum when they both are equal i.e =20/2 =10 hence at x=3 the value would be greatest.
=10*7*10*3 =2100
ATDH.
Sorry for the typo, question is Maximize (13-x)^7 *(X+7)^3. sorry lazy habits :)
@vikky312 said:
Madam unki aatmaye Prometric waalo ne botal mei band kar li hain!!CAT mei computerwa mei chord dete hain kabhi kabhi..!!
@anytomdickandhary said:
observe that sum of all the terms containing x is constant (13-x)+(x+7) =20. Hence their product will be maximum when they both are equal i.e =20/2 =10 hence at x=3 the value would be greatest.
=10*7*10*3 =2100
ATDH.
2^10*7^7*3^3 ????
@Estallar12 said:
Abbe jaldi batao CPLC ke 8 aur 9 main se koi diya hai ?
9 easy hai de do, tujhe 160 aayega :D
@ashishpai2001 said:
9 easy hai de do, tujhe 160 aayega
Wokay. Thanks!
Abhi wahi deta huun phir :)
@anupam001 bas.. old mocks etc revision ki koshish.. usually ending in a couple of hours of :P