ShoutBox (Part 1)

Jobs & Careers
20311

sab chale gaye 😞

20312
@karl said:
If x lies between ( €“7) and 13, then find the greatest possible value of (13 €“ x)7(x + 7)3.
At x = 3 ?
Value = 10^10 ??
20313
@karl said:
sab chale gaye
wat happen?
20314
@karl said:
If x lies between ( €“7) and 13, then find the greatest possible value of (13 €“ x)7(x + 7)3.
for the value of 3..which is the midpoint between -7 and 13
20315
@karl said:
If x lies between ( €“7) and 13, then find the greatest possible value of (13 €“ x)7(x + 7)3.
assuming q to be

(13-x)^7 * (x+3)^3

we get max value at x=-1

n vaue 14^7 * 6^3
20316
@Estallar12 said:
At x = 3 ?
Value = 10^10 ??
value would be 10^2*21 na?
20317
@Estallar12 said:
At x = 3 ?
Value = 10^10 ??
No, it happens at x = -1 when { (13-x)/7 = (x+7)/3 }
20318
@Estallar12 said:
At x = 3 ?
Value = 10^10 ??
@Brooklyn said:
assuming q to be
(13-x)^7 * (x+3)^3
we get max value at x=-1
n vaue 14^7 * 6^3
20319
@karl said:
If x lies between ( €“7) and 13, then find the greatest possible value of (13 €“ x)7(x + 7)3.
Let y = (13-x)^7 * (x+7)^3

At x = -7, y = 0
At x = 13, y = 0
In between, we have positive values, so we have a maxima between -7,13

Differential w.r.t x and put dy/dx = 0

dy/dx = -7(13-x)^6(x+7)^3 + 3(13-x)^7(x+7)^2 = 0

3(13-x) = 7(x+7)
10x = -10
x = -1

Max(y) = 14^7 * 6^3
20320
@soumitrabengeri said:
value would be 10^2*21 na?
It is 2^10*3^3*7^7.
20321
@karl said:
It is 2^10*3^3*7^7.
misread the question..did not understand that it was (13-x)^7..my bad
20322
@Brooklyn said:
assuming q to be
(13-x)^7 * (x+3)^3
we get max value at x=-1
n vaue 14^7 * 6^3
lol, sorry was lazy in pasting the question :). you got it right.
20323
@lopagargg said:
wat happen?
kuch nahi, shoutbox pe kaafi sannata chaya tha, main darr gaya :(
20324

find meeting tym


Solve wirth ur approach 😃 explain karna plz ache se
20325
@karl Hehe. Sannata may be because you didnt shout here :P
20326
@Brooklyn said:
Solve wirth ur approach explain karna plz ache se
Question missing hai, bas set up hai . Interesting set up.
20327
@Brooklyn said:
Solve wirth ur approach explain karna plz ache se
Question pura nahin hai. Kya nikaalna hai that is only not given. 😛 :P
20328
@karl said:
Question missing hai, bas set up hai . Interesting set up.
@Estallar12 said:
Question pura nahin hai. Kya nikaalna hai that is only not given.
Meeting tym..sry forgot to tell dat!!
20329
@Brooklyn said:
Meeting tym..sry forgot to tell dat!!
Aja - 15 + 30 + 60 + 120 min = 32 km total. (225 minutes)
Indu - 30 + 60 + 120 min = 24 kms total. ( 210 minutes)

Now, next 240 minutes, Indu covers 8 more kms.
=> 450 minutes.

In 450 - 225 = 225 minutes, Aja will cover 225*2/60 = 450/60 = 7.5 kms.

Left distance = 0.5 kms. Speed = 2 and 1.

Thus, 0.5*60/3 = 30/3 = 10 minutes.

So, Total time taken = 450 + 10 = 460 minutes = 7 hours and 40 minutes.
Time = 1 : 40 PM ??
20330
@Estallar12 said:
Aja - 15 + 30 + 60 + 120 min = 32 km total. (225 minutes)
Indu - 30 + 60 + 120 min = 24 kms total. ( 210 minutes)
Now, next 240 minutes, Indu covers 8 more kms.
=> 450 minutes.
In 450 - 225 = 225 minutes, Aja will cover 225*2/60 = 450/60 = 7.5 kms.
Left distance = 0.5 kms. Speed = 2 and 1.
Thus, 0.5*60/3 = 30/3 = 10 minutes.
So, Total time taken = 450 + 10 = 460 minutes = 7 hours and 40 minutes.
Time = 1 : 40 PM ??
P.S. I love committing blunders I know. Yahan bhi kiya hoga.
sahi hai launde 😁 top maroge is baar CAT lag rha hai , meko bas 99.9 lane dena...mai khush hu :D

maine bhi yahi kiya tha idividually solve kiya bt it takes too long doesnt it??? koi aur method nhi hai ???