@lopagargg said:mock ka que hai
Kounsa mock :splat:
@lopagargg said:choose incorrect1. In 1970s, when I was senior lecturer at Birmingham University,2. I began to do lecture tours of universities in foreign countries at the invitation of the BritishCouncil and to give papers at international conferences in foreign cities.3. The latter were usually much more enjoyable than similar events in England, with their spartan accomodation in student halls and canteen food to match.4. Abroad you stayed in hotels, ate in restaurants and did some sightseeing in congenial company.(a) 3 and 2 (b) 2 and 4 (c) 4 and 1 (d) 1 and 3
@Estallar12 1 main During 1970's nahi hoga?, I guess 3rd should read as "the latter was"
@lopagargg said:mock ka que hai
Woh toh theek hai. But reliable CL / IMS types or unrealistic TIME Verbal ? 😛 :P
@lopagargg said:choose incorrect1. In 1970s, when I was senior lecturer at Birmingham University,2. I began to do lecture tours of universities in foreign countries at the invitation of the BritishCouncil and to give papers at international conferences in foreign cities.3. The latter were usually much more enjoyable than similar events in England, with their spartan accomodation in student halls and canteen food to match.4. Abroad you stayed in hotels, ate in restaurants and did some sightseeing in congenial company.(a) 3 and 2 (b) 2 and 4 (c) 4 and 1 (d) 1 and 3
i thought we present papers not give 
@karl said:@Estallar12 1 main During 1970's nahi hoga?, I guess 3rd should read as "the latter was"
Nahin. In THE 1970s and when I was A senior lecturer IMO.
Awwption 3 main kidhar error hai ? Just spelling mistake hai I feel.
Lo ek accha question -
|x^2 - 5|x| + 4| >= |2x^2 - 3|x| + 1|. Find the solution set of x.
@Estallar12 said:Lo ek accha question -|x^2 - 5|x| + 4| >= |2x^2 - 3|x| + 1|. Find the solution set of x.
1,-3 to aa gya....baaki options se ho jayega. :p
-3 ke liye nhi hoga..
for >-1
|x^2 - 5|x| + 4| >= |2x^2 - 3|x| + 1|. Find the solution set of x.
For x>=0
|(x-4)(x-1)| >= |(2x-1)(x-1)|
|(x-4)| >= |(2x-1)|
(x-4)^2 >= (2x-1)^2
x^2 + 16 -8x >= 4x^2 + 1 -4x
(3x - 5)(x + 3)
-3
But since x>0,
0
For x
|(x+4)(x+1)| >= |(2x+1)(x+1)|
Same way as above,
(3x+5)(x-3)
-5/3
But since x
-5/3
Full range --> -5/3
Sahi/galat ?
5/3 pe zero hota hai..so lesseer than it..and greater than -5/3
Yaar kisi ne gp ka analysis dekha 2nd slot ka?kitne attempts keh rhe h sab?1st day k link pe to koi upload hi nhi kar rha 2nd slot ka.. :scared:
@iimnehajain said:Yaar kisi ne gp ka analysis dekha 2nd slot ka?kitne attempts keh rhe h sab?1st day k link pe to koi upload hi nhi kar rha 2nd slot ka.. :scared:
It's same, no change, but no. of attempts will change everyday because of change in difficulty level...so u can't predict what u'll get in ur plate...these things won't help much i guess.... Bindass jana or fod dena...
@iimnehajain said:Yaar kisi ne gp ka analysis dekha 2nd slot ka?kitne attempts keh rhe h sab?1st day k link pe to koi upload hi nhi kar rha 2nd slot ka.. :scared:
Rehne do. We have seen that surprise elements won't be there. That's it.
Ab har slot main alag alag hoga sab, level, breakup etc. So, just relax.
Prepare your best and Give your best on the C-Day. :D
All the Best :thumbsup:
@Angadbir said:|x^2 - 5|x| + 4| >= |2x^2 - 3|x| + 1|. Find the solution set of x.Full range --> -5/3Sahi/galat ?Perfect Sir.Integer range bolein toh x = -1, 0 and 1. :D
Integer range bolein toh x = -1, 0 and 1. :D@Estallar12 said:@lopagargg - Aap abhi tak yahin ho ma'am ? You're also nocturnal ?
"also" bole toh you too kya?? 
ab toh habit ho gai hai..
and mujhe ma'am 
ab toh habit ho gai hai.. and mujhe ma'am