leonelmessi Saysthe answer is 16hr 35 min guys .
Thanks.that's right.what's the approach?
Thanks.that's right.what's the approach?
In 2hr the ant will move 7metre .so in 16hr it will move 56 metre and in the next 35 min it will travel 7metre .in 5min it will travel 1metre so in 35 min it will travel 7metre .
yeah thank you buddy.....!!
ma approach is like
for 2 hrs ant will cover 7m....
so in 16 hrs ant will cover 56m
nw he has to move up 12m (in an hr)...
but he wud move the rest 7m within 35 mins...!!
so in total 16:35...!!
Thank you..
excuse me. can anyone solve the prob of LOD 1 of chap 5 (percentage)from arun sharma.please confirm me by sending a mail to my id given.:banghead::banghead::banghead::banghead:
kar.madhumaya Saysexcuse me. can anyone solve the prob of LOD 1 of chap 5 (percentage)from arun sharma.please confirm me by sending a mail to my id given.:banghead::banghead::banghead::banghead:
please post the q:
An ant climbing up a vertical pole ascends 12 metres and slips down 5 metres in every alternate hour.If the pole is 63 metres high,how long will it take to reach the top?
a)18 hrs b)17 hrs c)16 hrs 35 mins d)16 hrs 40 mins e)none of these
my take for this is 16 hr 35 mins..
Please tell the method for these Qs:-
Find the maximum value of 'n' such that
1) 42*57*92*91*52*62*63*64*65*66*67 is perfectely divisible by 42^n
a)4 b)3 c)5 d)6
2)570*60*30*90*100*500*700*343*720*81 is perfectly divisible by 30^n
a)12 b)11 c)14 d)13
thanks 😃
Please tell the method for these Qs:-
Find the maximum value of 'n' such that
1) 42*57*92*91*52*62*63*64*65*66*67 is perfectely divisible by 42^n
a)4 b)3 c)5 d)6
2)570*60*30*90*100*500*700*343*720*81 is perfectly divisible by 30^n
a)12 b)11 c)14 d)13
thanks :)
For the first one
42 = 7*3*2
Look for how many 7's we have. And it comes out to be 2 in first case. rest 3 and 2 you will get in plenty. SO only 42^2 will divide the above string completely.
Same logic applies for the second question. Hope this is the correct answer.
For the first one
42 = 7*3*2
Look for how many 7's we have. And it comes out to be 2 in first case. rest 3 and 2 you will get in plenty. SO only 42^2 will divide the above string completely.
Same logic applies for the second question. Hope this is the correct answer.
Sorry I meant 3 is the answer for the first one. Same logic applies for the second questionWrong
avinav2712 SaysArun Sharma's book has quite a few errors, so this could be one of them.
Dude you are talking about pairs and the questions says one shoe at a time.. There's a difference. Answer for both the cases is 12.
In 4 throws with a pair of dices,what is the chance of throwing a double twice?
Can some one explain the answer to this question?
In 4 throws with a pair of dices,what is the chance of throwing a double twice?
Can some one explain the answer to this question?
my take:
1/36..
if correct will tell the approach..
In 4 throws with a pair of dices,what is the chance of throwing a double twice?
Can some one explain the answer to this question?
Use the binomial theorem:
4C2*(1/6)^2*(5/6)^2=25/216.
Use the binomial theorem:
4C2*(1/6)^2*(5/6)^2=25/216.
Hey Divish can you please explain this method?
virus_rock SaysDude you are talking about pairs and the questions says one shoe at a time.. There's a difference. Answer for both the cases is 12.
It's clearly mentioned in the question that "how many no. of shoes you need to pick to get ONE PAIR of shoes of the same colour". We will obviously be taking out one shoe at a time but we need a pair at the end.
So assuming 1st shoe = white
2nd = black
3rd has to be either white/black and thus, we have a pair here. So 3 has to be the answer here. If you still disagree, post your approach.
Posting the 2 questions for your reference:
2.there are 7 pairs fblack nd 5 paird f white shoes.they are put in a box and are drawn one at a time.To ensure at least one pair of black shoes are taken out,what is no f shoes reqiured to be drawn out?
a.12 b.13 c.7 d.8
3.In d above qstn,what s d minimum no f shoes 2 b drawn out 2 get atleast one pair f correct shoes(either black or white)?
a.12 b.7 c.13 d.8
Can anyone solve this pls.
The letter of the word `article` are arranged at random. Find the probability that the vowels may occupy the even places.
1)2/35
2)1/35
3)3/36
4)1/17
can anyone solve this pls.
The letter of the word `article` are arranged at random. Find the probability that the vowels may occupy the even places.
1)2/35
2)1/35
3)3/36
4)1/17
3!4!/7! = 1/35
what is the remainder when 73*75*78*57*197*37 is divided by 34?
pguser Sayswhat is the remainder when 73*75*78*57*197*37 is divided by 34?
The answer would be 32. Here's the method:
73*75*78*57*197*37 mod 34
5*7*10*(-11)*(-7)*3 mod 34
35*110*21 mod 34
1*8*(-13) mod 34
-104 mod 34
-2 mod 34
32
The answer would be 32. Here's the method:
73*75*78*57*197*37 mod 34
5*7*10*(-11)*(-7)*3 mod 34
35*110*21 mod 34
1*8*(-13) mod 34
-104 mod 34
-2 mod 34
32
thanx avinav i also got the same answer but in the book the ans. was given as 28, so got confused and needed to check.