please help me with the solution ...
q. what is the sum of factors of 18000 which are divisible by 8 but not by 25?
is it 1872???
is it 1872???
Pg 158 Q.44.
A salesman is appointed with a basic salary of 1200/month and the condition that for every sales of 10000 and above he will get 50% of basic and 10% of sales. this scheme does not operate for first 10000 of sales. what would be the value of sales if he wants to earn 7600 in a particular month?
Let x*10000+10000 be the total sales.
Now 1000 x+ 600 * x= 7600-1200 = 6400
=> 1600 x = 6400
=> x = 4
Hence sale should be 10000*4 + 10000 = 50000
Is this correct?
Pg 158 Q42
Aus scored X runs in 50 overs. india tied the score in 10% less overs. if indias avg run rate had been 33.33% higher the scores would have been tied 10 overs earlier. find how many runs were scored by australia.
A.250
B.240
C.200
D. Cannot be determined.
My Sol. I started solving the sum through options.
Aus----240----50overs----4.8
Ind-----240----40overs----6
ind-----240---30overs-----8 (6*4/3)
hence all conditions are fullfilled
Apparently as per the book the ans cannot be determined which i couldnt understand why??
Thanks.
Shouldnt India take 45 overs if it needs to score in 10% less overs?
sorry that was a typo it was "india tied the score in 20% less overs"
The answer to Q44 was Rs.50000
although i still didnt understand the solution to the aust-ind sum.
Thanks a lot for the help puys
Two planes moving along a circle of circumference 1.2 km with constant speed.When they move in diffrent direction they meet every 15 secs and when they move in same direction one place overtakes the the other every 60 secs.Find teh speed of slower plane
please help me with the solution
Two planes moving along a circle of circumference 1.2 km with constant speed.When they move in diffrent direction they meet every 15 secs and when they move in same direction one place overtakes the the other every 60 secs.Find teh speed of slower plane
please help me with the solution
Here..Let Speed of planes be a,b..both in m/s
Now...
(a+b)*15 = 1200..(1)
a+b = 80
Also
a*60 = 1200 + b*60
a-b = 20
So a = 50, b = 30 m/s
Answer = 30 m/s
can anyone give a detailed solution for Q53.in LOD III chap. number system.
Here..Let Speed of planes be a,b..both in m/s
Now...
(a+b)*15 = 1200..(1)
a+b = 80
Also
a*60 = 1200 + b*60
a-b = 20
So a = 50, b = 30 m/s
Answer = 30 m/s
Thanks man.. i wasted a lot of time taking 1.2 Km as radius
anushreebhatt7 Sayscan anyone give a detailed solution for Q53.in LOD III chap. number system.
can you post the question
hi puys... I've a prob from mensuration, plz help...(pg 342 prob 7)
A cylinder and a cone having equal diameter of their bases are placed in the Quatab Minar one on the other, with the cylinder on the bottom. If their curved surface area are in the ratio of 8:5, find the ratio of their heights. Assume the height of the cylinder to be equal to the radius of Quatab Minar.(assume Quatab Minar to be having uniform radius throughout).
(a)1:4
(b)3:4
(c)4:3
(d)2:3
(e)3:2
n ya thr is one more... (pg 342 prob 4)
The sides of a triangle are 21cm, 20cm and 13 cm.find the area of the larger triangle into which the given triangle is divided by the perpendicular upon the longest side from the opposite vertex.
(a)72 sq. cm
(b)96 sq cm
(c)168 sq cm
(d)144 sq cm
(e)150 sq cm
n ya thr is one more... (pg 342 prob 4)
The sides of a triangle are 21cm, 20cm and 13 cm.find the area of the larger triangle into which the given triangle is divided by the perpendicular upon the longest side from the opposite vertex.
(a)72 sq. cm
(b)96 sq cm
(c)168 sq cm
(d)144 sq cm
(e)150 sq cm
its 96....
see its the basic use of triplates...the perpendicular drawn will be 12 cms...rest u can derive using pythagoras theorem...
see its the basic use of triplates...the perpendicular drawn will be 12 cms...rest u can derive using pythagoras theorem...
thanks yaar... i just missed this point... i sud leave room for some time... else i've to post a prob on 2+2 soon...
hi puys... I've a prob from mensuration, plz help...(pg 342 prob 7)
A cylinder and a cone having equal diameter of their bases are placed in the Quatab Minar one on the other, with the cylinder on the bottom. If their curved surface area are in the ratio of 8:5, find the ratio of their heights. Assume the height of the cylinder to be equal to the radius of Quatab Minar.(assume Quatab Minar to be having uniform radius throughout).
(a)1:4
(b)3:4
(c)4:3
(d)2:3
(e)3:2
plz try this one...
hi puys... I've a prob from mensuration, plz help...(pg 342 prob 7)
A cylinder and a cone having equal diameter of their bases are placed in the Quatab Minar one on the other, with the cylinder on the bottom. If their curved surface area are in the ratio of 8:5, find the ratio of their heights. Assume the height of the cylinder to be equal to the radius of Quatab Minar.(assume Quatab Minar to be having uniform radius throughout).
(a)1:4
(b)3:4
(c)4:3
(d)2:3
(e)3:2
sry wrong post...
my answer is coming out to be 4:3..
is it correct??
sry bt no... its not the right one... can u gimme some solution part in detail plz...
nikhil r u coming wd solution... actualy i was logging off... just w8ing fr this ans to come(plz wd solution details)...
hi puys... I've a prob from mensuration, plz help...(pg 342 prob 7)
A cylinder and a cone having equal diameter of their bases are placed in the Quatab Minar one on the other, with the cylinder on the bottom. If their curved surface area are in the ratio of 8:5, find the ratio of their heights. Assume the height of the cylinder to be equal to the radius of Quatab Minar.(assume Quatab Minar to be having uniform radius throughout).
(a)1:4
(b)3:4
(c)4:3
(d)2:3
(e)3:2
is the answer 3:4
bhupi3149 Saysis the answer 3:4
yes it is... wil u explain if u dont mind???:-P
passionate_play Saysyes it is... wil u explain if u dont mind???:-P
2*pi*r*h/pi*r*l=8/5 (given )
r = h (given for cylinder)
therefore
r/l=8/10
now hight of cone= sqrt((10/8*r)^2-r^2))
=6/8r=3/4r
ratio of hieghts = 3/4