Can u plz help me to solve this question:
If 2
Answer is 4.
Can u plz help me to solve this question:
If 2
Answer is 4.
if x n y are integers then x = 3 and y = 2 then the ratio comes out be 5?
Hi, i a newbie on this site and have just started preparing for MAT, wanted to know if the arun sharma book for DO and LR will be as per MAT question stndards or is it much more advanced?
Please do help
LOD 1 for QA will surely help u....
shanks4mba Saysif x n y are integers then x = 3 and y = 2 then the ratio comes out be 5?
They aren't necessarily integers as its not mentioned in the question. and the answer given is 4. Its question no.55 of LOD 1 of number system.
saru421 SaysThey aren't necessarily integers as its not mentioned in the question. and the answer given is 4. Its question no.55 of LOD 1 of number system.
If they aren't integers, then the answer should be nearly 7, as the upper limit of x+y would be 3.999999......+2.99999..... ~ 7 and lower limit of x-y would be 1.
avinav2712 SaysIf they aren't integers, then the answer should be nearly 7, as the upper limit of x+y would be 3.999999......+2.99999..... ~ 7 and lower limit of x-y would be 1.
Even i thought the same. Then may be the answer given is wrong.
Please solve this
number system
Q64.28383rd term in 123456789101112........
Q65 if you form a subset of integers b/w 1 to 3000,such that no two of them add upto a multiple of 9,whats the max num of elements in subset?
Q64. can be answered as
0-9 => 9 digits
10-99 => 90*2= 180 digits
100-999 => 900*3= 2700 digits
so, 9+180+2700= 2889 digits and 9+90+900=999 numbers
now we are left with 28383-2889=25494 digits
so, 25494/4 gives 6373 as quotient and 2 as remainder.
(we divide by 4 bcoz now we ll be dealing with 4 digit numbers)
now 999+6373=7372 numbers are over with 28381 digits.
and the next number is 7373 and 2 left as remainder.
So the 28383th term is 3.
Thanks Saru. It's really helpful for me. Plz post some more problems.
Please solve this
number system
Q64.28383rd term in 123456789101112........
Q65 if you form a subset of integers b/w 1 to 3000,such that no two of them add upto a multiple of 9,whats the max num of elements in subset?
64) 9+2*90+3*900+4*9000=9+180+2700+36000=38889
28383=2889+25494
25494=4*6373+2
now,first number is 1000.
so,6373rd number is 7372.
so,123......737273
so,its 3.
65){9k+5,9k+6,9k+7,9k+8,....} where,k is an integer>=0
{5,6,7,8,9......2993,2994,2995,2996}
333*4+1
1333
any short method for Q. 12-14 of Geometry LOD1...
i tried using pythagoras... but that seems to be too much long...
not able to recall the shorter method...
any short method for Q. 12-14 of Geometry LOD1...
i tried using pythagoras... but that seems to be too much long...
not able to recall the shorter method...
question 12-14 of LOD1 Geometry can be solved as
Q12.
PT^2 = PA * PB
Similarly Q13 can be solved.
Q14.
PA*PB = PC*PD
Can someone explain ?
On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?
10201
12301
13440
10200
Can someone explain ?
On July 1, 1982, Ms. Fox deposited $10,000 in a new account at the annual interest rate of 12 percent compounded monthly. If no additional deposits or withdrawals were made and if interest was credited on the last day of each month, what was the amount of money in the account on September 1, 1982?
10201
12301
13440
10200
The answer should be 10201. 12% compounded monthly means a monthly interest rate of 1%. The period mentioned is 2 months. Thus, the formula for calculating the amount would be:
P* = 10000* = 10201
Hope you got it.
hi plz solve dis..its frm L2 quadratic
if both the rootsof the quadratic eqn ax^2+bx+c=0 lie in the interval (0,3)then 'a' lies in..??
hi plz solve dis..its frm L2 quadratic
if both the rootsof the quadratic eqn ax^2+b^x+c=0 lie in the interval (0,3)then 'a' lies in..??
hey dude the eqn u have given is ax^2 + b^x + c = 0. is there any typo? are u sure it is b^x?
ive edited the post! sorry!!
Hi,
has anybody solved the 'Permutations and Combination' Chapter from Arun Sharma.
I wanted to match my answers.
Also, had several doubts. will post them here.
Quoting the Questions from LOD(III) - Permutations and Combinations
1. The number of ways in which four particular persons A,B,C,D and six more persons can stand in a queue so that A always stands before B, B always before C and C always before D is?
2. The number of circles that can be drawn out of 10 points of which 7 are collinear is ?
3. In an examination, the maximum marks for each of the 3 papers is 50 each. The maximum marks for the fourth paper is 100. Find the number of ways with which a student can score 60% of the marks in aggregate?
4. A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?
5. In how many ways can a cricketer score 200 runs with fours and sixes only?
6. The AMS MOCK CAT Test Catalyst 19 consists of four sections. Each section has a maximum of 45 marks. Find the number of ways in which a student can qualify in the n the AMS MOCK CAT if the qualifying marks is 90.
I am able to get the ans for the question but could some1 explain how to solve these problems quickly...plz elaborate your method !
LOD2 : no. system 88
A, B and C have a total of 80 coins among them. A triples the no. of coins with the others by giving them some coins from his own collection. Nest, B repeats the same process. After this B now has 20 coins. Find the no. of coins he had at the beginning?
a)11
b)10
c)9
d)12
$U!\!$H|!\!E SaysThere are 5 blue socks, 4 red sochs and 3 green socks. In how many ways 4 socks could be selected?
Ans : 12c4 ways.