Quant by Arun Sharma

MBA CAT 2024
5946
@techsurge m also getting 1333,but the answer is 1336
5947
@heycat1012 answer is 1336..m also getting 1333
5948

72/5=14 ,now again 14/5=2

so 14+2=16.
5949

Q. Find the remainder when 43^197 is divided by 7.


As per one tip(related to remainder theorem) mentioned in the book - if an expression can be written in the form of {(ax + 1)^n}/a, the remainder will always be 1.

Here - the expression can be written as {(7x+1)^197}/7. As per the explanation, the remainder should be 1 but the answer is given as 2.
5950
@Revenous said:
72/5=14 ,now again 14/5=2
so 14+2=16.
are you sure it is done like that??
@scrabbler @antodaya @naga25french : sir, please help on this.

@Revenous vivek bhai, when you reply someone's post please use reply option or quote option. so that the user will get to know you have replied 😃 😃
5951
@pandeyn said:
Q. Find the remainder when 43^197 is divided by 7.
As per one tip(related to remainder theorem) mentioned in the book - if an expression can be written in the form of {(ax + 1)^n}/a, the remainder will always be 1.
Here - the expression can be written as {(7x+1)^197}/7. As per the explanation, the remainder should be 1 but the answer is given as 2.
Leave about all those tips..
43 when divided by 7 will give you remainder 1

so 1^197 /7 will also give you remiander 1
btw an information. there are lot of printing mistakes in arun sharma 😃
5952
@chandrakant.k bhai apka approach thek hai,,,
5953
@chandrakant.k bhai just i saw in book its 16 not 18.......sorry yar .....i think 18 option is wrong.
5954
@chandrakant.k achaa aap 72! vala puch rahe the...uski approaach toh yeh hoti hai nof of 5 dekhne hote hain....
uske liye [72/5] + [72/5^2] [] greatest integer value hai
====14+2=16 ans....
5955
@antodaya said:
@chandrakant.k achaa aap 72! vala puch rahe the...uski approaach toh yeh hoti hai nof of 5 dekhne hote hain....
uske liye [72/5] + [72/5^2] [] greatest integer value hai
====14+2=16 ans....
ha bhai.. tho aap konsa dekhe the??? remainder wala?? actually after you replied i thoght that ki question ko bhi quote karna tha.. 😁 😁
5956

i think i got it


first we need to consider 1 and 3000 included and along with the same also include a 9k + form number as their wont be another 9k form number so it can be included

@leo12
5957

Q. Find the unit's digit -


1^1 + 2^2 + 3^3 + .... + 100^100

Explain also @chandrakant.k TIA
5958
@pandeyn said:
Q. Find the unit's digit -
1^1 + 2^2 + 3^3 + .... + 100^100
Explain also @chandrakant.k TIA
1^ 1 =1
2^2 = 4
3^3 =7
4 ^ 4 =6
5^5 = 5
6^ 6 = 6
7^ 7 = 3
8^ 8 = 6
9 ^ 9 = 9
is the answer 7???
5959
@chandrakant.k said:
1^ 1 =1
2^2 = 4
3^3 =7
4 ^ 4 =6
5^5 = 5
6^ 6 = 6
7^ 7 = 3
8^ 8 = 6
9 ^ 9 = 9
is the answer 7???
ans is zero
units digit of 1st 10 numbers = 7
There are 10 such set of 10 nos
so sum of units digit 7x10=70 ....
zero is the units digit

5960
@MBAVichar said:
ans is zero
units digit of 1st 10 numbers = 7
There are 10 such set of 10 nos
so sum of units digit 7x10=70 ....
zero is the units digit
oh yeah.. while solving i had considered this.. but at final step forgot
5961

thanks guys.. got it

5962

folks,

just wanted to know whether Arun Sharma's quant will be enough for IIFT preparation and also to add on it do i nedd to solve lod 2 questions or lod1 will be enough....???

Awaiting for a reply,TIA:)
5963
@UnCharismatic said:
folks,
just wanted to know whether Arun Sharma's quant will be enough for IIFT preparation and also to add on it do i nedd to solve lod 2 questions or lod1 will be enough....???
Awaiting for a reply,TIA
Bro.. i'm not sure about the sufficiency of Arun Sharma, but I believe lod 2 is a must.
5964
@abhijit111 thanx bro , i think the author should have also given hints or solutions to the block tests also , there are some mindboggling ques there
5965
@UnCharismatic i guess arun sharma's book is really good , although it contains some errors but its nice . besides lod 2 you can also solve block review tests that will be fine