@insanebasilisk said: Hi! i wanted to know if solving lod 1 and lod 2 from arun sarma is enough for quant
Never Back Down @insanebasilisk said: Hi! i wanted to know if solving lod 1 and lod 2 from arun sarma is enough for quant
Never Back Down Pls. solve the below mentioned questn from Time and Work:-
Q1) X can do as much work in 2 days as Y can do in 3 days and Y can do as much work in 4 days as Z can do in 5 days. It takes 20 days if all the 3 work together to complete the work. How much time will Y take to complete the work all by himself?
Options:- 82 days, 44 days, 66 days, 50 days, 46 days
My approach:-
8X=12Y =15Z
Substituting the value of X and Z in the equation:-
1/X + 1/Y + 1/Z = 1/20
My ans is coming to 58 approx.
Q2) it takes 6 days for 3 girls and 2 boys working together to complete a work. 3 boys would do the same work 5 days sooner than 9 girls. How many times does the output of a boy exceed that of a girl??
Option - 3 times , 4 times, 5 times, 6 times, 7 times
My approach:-
3G + 2B = 6
3B = 9G - 5
since the work hours will remain the same:-
(3G + 2B)*6 = (9G - 3B)*5
here B=G...
Find the change in % profit for a fruit vendor who, after finding 20% of the fruits rotten. increased his SP by 10% over and above 15% that he was already charging.
A) -15 B) +11.5 c) -13.8 d) -11.5 e) Insufficient data.
A shopkeeper makes a profit of Q% by selling an object for Rs. 24. Had the CP and SP been interchanged, it would have led to a loss of 62.5Q%. With the latter CP, what should be the new selling price to get a profit of Q%.
a) Rs. 34.4 b) 32.5 c) 25.6 d) 38.4
pls solve these two Qs wid soln...
@PriyankaMitra said: Hi Puys,i know this is completely off the topic............i want to know how do i get a vivid idea of 2009 2010 and 2011 online papers.....???as they are not available.....easily... is there a book by arun sharma or so?kindly help......
@[571537:PriyankaMitra]
@[67562:Elusionist] so which books are best these quant topics...
@ayushbhalotia said:Pls. solve the below mentioned questn from Time and Work:-
Q1) X can do as much work in 2 days as Y can do in 3 days and Y can do as much work in 4 days as Z can do in 5 days. It takes 20 days if all the 3 work together to complete the work. How much time will Y take to complete the work all by himself?
Options:- 82 days, 44 days, 66 days, 50 days, 46 daysMy approach:-
8X=12Y =15Z
Substituting the value of X and Z in the equation:-
1/X + 1/Y + 1/Z = 1/20
My ans is coming to 58 approx.
Let the efficiecny or Rate of doing work for Y be 10 unit/day.
This means that Y does 10 unit of work per day, irrespective of any condition, or any other person involved.
Now given, X = 3/2 Y
So, X does 15 units of work per day ie efficiency of X = 15
Also given Z = 4/5 Y
So, Y does 8 units of work per day i.e. efficiency of Y = 8
If they work together for 1 day, total work done
= total efficiency = X + Y + Z
= 15 + 10 + 8
= 33 units of work in 1 day
Given that all 3 people work together for 20 days
So total work done = 33*20 = 660 units of work
Now , the number of days Y alone will take to complete this much amount of work = 660/10 (Since he does 10 units of work per day)
= 66 days ................ Answer
***********************
Save urslef from getting tangled in Fractions.
I assumed Y's efficiency as 10 after seeing the ratios 3/2 and 4/5.
LCM(5,2) = 10.
Q3 . If (a/(b+c)) = (c/(b+a)) = (b/(a+c)), then each fraction is equal to
Q28. A cat take 5 leaps for every 4 leaps of a dog, but 3 leaps of dog are equal to 4 leaps of cat. What is the ratio of the speed of the cat to that of the dog?
Q46 . A varies jointly as B and C, and A = 6 when B = 3 and C = 2. Find A when B = 5, C = 7
Guys please give the explanation of the answer don't just reply back the answer, thanks in advance
plz plz reply....
@[568667:Psychamour] hmmm.. y u assumed y as 1/10 why not 1 or 100%?? also how u got the values of x and z that are 15 and 8 ?
answer is 96meters
sol:
let total distance be x
then A...completes x
B ...completes x-24
C...completes x-36
as per second statement after A completes race B covers 24 mt to complete his race whereas C has covered 20 (36-16) mt
so B:C = 24:20 = 6:5
therefor (x-24)/(x-36) = 6/5
x = 96
Q. A speaks truth 80% of the time and B speaks truth 75% of time. Find out the probability when A contradicts with B.
a).15 b).20 c).25 d).35
@[260915:saikatdgp] .25?
80/100*25/100+20/100*75/100
@[585700:KatMann]
It is .35
process is correct though
silly calculation mistake..
@ankitgalgat said:@Psychamour hmmm.. y u assumed y as 1/10 why not 1 or 100%?? also how u got the values of x and z that are 15 and 8 ?also is this of arun sharma question??