Stuck in the following questions
Q1.)For what value of a do the roots of the equation 2x^2 + 6x + a =0 satisfy the condition (alpha/beta) + (beta/alpha)
a) a9/2
b)a>0
c)-1d)-1
Q2.) If p and q are the roots of the equation x^2 - px + q = 0 then
a) p=1,q=-2
b)p=0,q=1
c)p=-2,q=0
d)p=-2,q=1
e)p=1,q=1
i got stuck...plz help me out....
Q-two pipes A and B can fill up half full tank in 1.2 hours.the tank was initially empty.pipe B was kept open for half the time required by pipe A to fill the tank by itself.then pipe A was kept open for as much required by pipe B to fill up 1/3 of the tank itself.it was found that the tank was 5/6 full.the least time in which any of the pipe can fill the tank fully is
a) 4.8 h
b) 4 hours
c) 3.6 hours
d) 6 hours
According to the first condition, the time to fill the tank when both the pipes are on would be 2.4 hours.
=> 1/A + 1/B = 1/2.4
The second condition gives that
(A/2) * (1/B) + (B/3) * (1/A) = 5/6
=> A/2B + B/3A = 5/6
Put A/B = X
=> X/2 + 1/3X = 5/6
=> 3X^2 - 5X +2 = 0
Solve the quadratic to get the value of X as 2/3 or 1
That brings up 2 cases A=2y and B=3y or A=B
When A = B, each pipe would individually fill the tank in 4.8 hrs.
By the other case, 1/2y + 1/3y = 1/2.4
Solve to get y= 2
=> A = 4 hrs and B = 6 hrs.
So, the least time possible is 4 hrs.
Hope that helps 😃
Aditya answer to your 2nd question:
Q2.) If p and q are the roots of the equation x^2 - px + q = 0 then
a) p=1,q=-2
b)p=0,q=1
c)p=-2,q=0
d)p=-2,q=1
e)p=1,q=1
will be option number 1 1.e. p=1 and q=-2
Thanks - Sameer
Stuck in the following questions
Q1.)For what value of a do the roots of the equation 2x^2 + 6x + a =0 satisfy the condition (alpha/beta) + (beta/alpha)
a) a9/2
b)a>0
c)-1d)-1
Ans- a
Q2.) If p and q are the roots of the equation x^2 - px + q = 0 then
a) p=1,q=-2
b)p=0,q=1
c)p=-2,q=0
d)p=-2,q=1
e)p=1,q=1
Ans-c
use sum of root and product of root concept
number system ...level 1... q. no. 93?? plz anyone post detailed sol'n..
rakshaarya Saysnumber system ...level 2... q. no. 93?? plz anyone post detailed sol'n..
Kindly post question
as different people will be having different version of the book
number system
LOD 2
K is a three digit number such that ratio of the number to the sum of its digits is the least.what is the difference between the hundreds and tens digits of k?
number system
LOD 2
K is a three digit number such that ratio of the number to the sum of its digits is the least.what is the difference between the hundreds and tens digits of k?
my take
1...
i think number will be 189....or 198
A and B are stationed at two points Q and R respectively on a flowing river.The direction of flow of river is from Q to R.When A and B swim towards each other,they meet at P,which is at a distance of 20m from the point R.When A swims towards B and B swims away from A,they meet at S,which is at a distance of 40m from the point R.B's speed in still water is five times the speed at which the river flows.
1)Find the ratio of speeds of A and B in still water
a)6:1
b)7:1
c)8:1
d)5:1
2)On a particular day A and B start swimming towards each other simultaneosly from the points where they are stationed.When A was 'y'm away from the point P,B turns back and they meet at the point R.Find the value of y.
a)52m
b)56m
c)58m
d)60m
e)none of these
pls show detailed sol.
Can someone ans this- a number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to this mistake.
quidditch88 SaysCan someone ans this- a number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to this mistake.
Let the no. be x
Actual value to be obtained = 5x
Value obtained = 0.2x
Percent change = 4.8/5 X 100 = 96%
quidditch88 SaysCan someone ans this- a number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to this mistake.
let no be : a
as per question: ((5a-(a/5))/5a )*100= 96%
let me know if I am wrong
quidditch88 SaysCan someone ans this- a number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to this mistake.
instead of 5a we got a/5
to know the % change..just put a = 100 [ makes cal easier;)]
so 500 became 20..a change of 480..480/500 = 96%
:)
quidditch88 SaysCan someone ans this- a number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage change in the result due to this mistake.
Let the number be 5.
=> 5/5 = 1 and 5*5 = 25.
=> %change = (25-1)/25 = 24/25 = 96%.
Could you please send me the Arun Sharam's free ebook link?
Thanks in advance..
Could you please send me the Arun Sharam's free ebook link?
Thanks in advance..
Arun Sharma is a book which is worth an investment. Costs just about 370 bucks on flipkart.
Let the author and publishers earn a little for the great book that they've prepared. 😃
Here's a question from Number System(Pg-46)-
What is the highest power of 3 available in the expression 58!-38!?
a) 17 b) 18 c) 19 d) None of these.
Help!
What is the highest power of 3 available in the expression 58!-38!?
a) 17 b) 18 c) 19 d) None of these.
Help!
Number System(Pg-46)--
Find the 28383rd term of the series: 123456789101112....
a) 3 b) 4 c) 9 d) 7
i'm having problem in one question from Number system:
n is number such that 2n has 28 factors and 3n has 30 factors, 6n has
a) 35
b)32
c)28
d) None of these
plz tell me how to solve...