Quant by Arun Sharma

Q1. The greatest no. which will divide 4003,4126 and 4249:
  1. 43
  2. 41
  3. 45
  4. None of these

Q2. what is the no. of zeroes in the following:
3200*1000*40000*32000*15000000
Q3. A 2 digit no. is thrice as large as the sum of its digits, and the sq. of that sum is equal to the trebled required no.. Find the no?
Q4 if we divide a 2 digit no by the sum of its digits we get 4 as a quotient and 3 as a remainder. Now, if we divide that 2-digit no. by the product of its digits, we get3 as quotient and 5 as remainder. Find the no?
Q5 there is a natural no that becomes equal to the sq. of a natural no. when 100 is added to it and the sq of another no. when 169 is added to it. Find the no. ?
Q6 find 2 three digit no whose sum is a multiple of 504 and quotient is a multiple of 6?
Q7 find the 3 digit no. if it is known that the sum of its digits is 17 and the sum of the square of its digits is 109 . If we subtract 495 from this no. , we obtain a no consisting of the same digits written in reverse order.

Q. M is a 2 digit no. which has the property that the product of factorial of its digits ? Sum of factorials of its digits. How many values of M exist?
  1. 56
  2. 64
  3. 63
  4. None of these

Q9 K is a 3 digit no such that the ratio of the no. to the sum of its digits is least. What is the difference b/w the hundredth and tenth digit of K?
  1. 9

  1. 8

  1. 7

  1. None of these

Q10. x and y are 2 positive integers . Then what will be the sum of coefficients of the expansion of the expression (x+y)^44?
  1. 2^43

  1. (2^43) + 1

  1. 2^44

  1. (2^44) - 1

Q11. find the remainder when 7^99 is divided by 2400
  1. 1
  2. 343
  3. 49
  4. 7

Q12. find the remainder when (10^3 + 9^3)^752 is divided by 12^3
  1. 729

  1. 1000
  2. 752
  3. 1

Q13. how many values of x and y are such that 4x + 7y = 3, while x
  1. 144
  2. 141
  3. 143
  4. 142

Q97.
Difficulty level
+ve marks
-ve marks
Lod 1
4
2
Lod2
3
1.5
Lod 3
2
1
The test had 200 question with 80 on lod 1, 60 lod2 and lod 3.
If a student has solved 100 question exactly and question that he or she might have marked is
  1. 44
  2. 56
  3. 60
  4. None of these



Hi friends Q97,Q5,Q6,Q9 still unanswered

Progression Lod 2
Q27 . If a man saves Rs. 1000 each year and invest at the end of the year at 5% compound interest , how much will the amount be at the end of 15 year?

  1. 21478
  2. 21578
  3. 22578
  4. 22178


Q32 . The sum of series
1/(21/2 + 11/2) + 1/(21/2 + 31/2 )+ + 1/(1201/2 + 1211/2)
  1. 10
  2. 11
  3. 12
  4. none of these
Block 1 Test Review



Review -1
Q11 . 139 person have signed up for an eliminating tournament. All player are to be prepared up for the first round but because 139 is an odd no. one player will get bye, which promotes him to the second round , without actually playing in the first round. The pairing continues, with a bye to any player left over. If the scheduled is planned so that minimize no. of matches required to determine the champion, the no. of matches which must be played is ?
  1. 136
  2. 137
  3. 138
  4. 139

Q13 . There are ten 50 paise coins placed on a table. Six of these show tail, 4 shows head. A coin chosen at random and flipped over(not tossed). This operation performed 7 times. One of the coin then covered . Of the remaining 9 coin five show tails 4 shows head. The covered coin shows
  1. Head
  2. Tail
  3. More likely head

  1. More likely tail

Q18 . It takes the pendulum of a clock 7 sec to strike 4 o'clock. How much time will it take to strike 11 o'clock?
  1. 18 sec
  2. 20 sec
  3. 19.25 sec
  4. 23.33 sec

Review - 2
Q11 . Abc is a 3 digit no. in which A>0. the value of Abc is equal to the sum of factorial of its 3 digits. What is the value of B?
  1. 9
  2. 7
  3. 4
  4. 2

Q20 . The infinite sum of 1 + (4/7) + (9/72) + (16/73) +
  1. 27/14

  1. 29/13

  1. 49/27
  2. 256/147

Q24 . A +ve whole no. M less than 100 is represented in base 2, 3 and 5. it is found that in all 3 cases the last digit is 1, while in exactly 2 out of 3 case the leading digit in 1. Then M equals:
  1. 31

  1. 63
  2. 75
  3. 91

Review 3
Q3 . Find the digit at ten's place of the no. N = 7281 * 3264
  1. 0
  2. 1
  3. 6

  1. 5

  1. None of these

Q10 . A one digit no. , which is the ten's digit of a 2 digit no . X is subtracted from X to give Y which is the quotient of the division of 999 by the cube of a no. find the sum of digits of x.
  1. 5

  1. 6

  1. 7

  1. 8

  1. 9

Q14 . The no. of +ve integer value pair (x, y). Satisfying 4x-17y= 1 and x
  1. 59

  1. 57

  1. 55
  2. 58
  3. None of these

Review 4

Q1. Find the no. of 6 digit no that can be formed using the digits 1,2,3,4,5,6 once such that 6-digit no. is divisible by it s unit digit:

  1. 648
  2. 528
  3. 728
  4. 128
  5. None of these


Review 5

Q3 . Find the highest power of 2 in 1! + 2! + 3!+.+600!
  1. 1
  2. 494
  3. 3.0
  4. 256
  5. None of these


Q7 . What is the remainder when 789456123 is divided by 999?

  1. 123
  2. 369
  3. 963
  4. 189

  1. 998


Q8 . What is the total no. of factor of 16! ?

  1. 2016

  1. 1024

  1. 3780

  1. 4032


My answer was coming 5376
Factors of 2 is 15, 3 is 6, 5 is 3 , 7 is 2, 11 is 1 and 13 is 1
So (15 +1) * (6+1)*(3+1)*(2+1)*(1+1)*(1+1) = 5376

Q9 . Find the sum of first 125 term of the sequence1,2,3,2,1,4,3,2,1,5,4,3,2,1
  1. 616

  1. 460

  1. 750
  2. 720
  3. 680


Q10 . Umesh purchased a tata nano recently , but the faulty car odometer of car proceeds from digit 4 to digit 6 always skipping digit 5, regardless of position. If the meter shows 003008(starting with 000000) how many km has nano actually travelled?

  1. 2100

  1. 1999

  1. 2194
  2. 2195
  3. None of these


Q11 . What is the remainder when 123412341234.. upto 100 digit is divided by 909?
  1. 623
  2. 650
  3. 685
  4. 675
  5. None of these


Q12 . Mr. Ramlal lived his entire life during his 1800s. In the last year of his life, ramlal stated: once I was x year old in the x^2. he was born in the year?

  1. 1822
  2. 1851
  3. 1853
  4. 1806
  5. 1830


Q16 . What is the remainder when 2^100 is divided by 101?

  1. 1
  2. 100
  3. 0
  4. 99
  5. None of these


Q17 . Find the last 2 digit of 2^134
  1. 04
  2. 84
  3. 24
  4. 64
  5. None of these

hey puys first Thanks for such thread and I've got some problems plz help me out of dis.
gives remainder and {.} denotes the fractional part of that. the fractional part is of the form (0.bx). the value of x could be a)2 , b) 4, c) 6, d) 8.
Option a is correct bt d xplanation given in d books is as nothing.

one more question puys.
find the three digit number if it is known that the sum of its digits is 17 and the sum of the squares of its digits is 109. If we subtract 495 from this number, we obtain a number consisting of the same digits written in reverse order.
thanks in advance ....

one more question puys.
find the three digit number if it is known that the sum of its digits is 17 and the sum of the squares of its digits is 109. If we subtract 495 from this number, we obtain a number consisting of the same digits written in reverse order.
thanks in advance ....

let the number be
100a+10b+c(abc)
the it's reverse would be 100c+10b+a subtract the both equations
you will get 99(a-c)=99*5
a-c=5 and it is also given a+c+b=17
and a^2+b^2+c^2=109
just solve them you will get your answer....

P.s.-request to all the puys that if you are making continuous post then rather than making a new post every time please edit your earlier one....
Shyam's house,his office and his gym are all equidistant from each other. The distance between any 2 of them is 4km. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office. He then reverses direction and walks till he reaches a point directly south of his office . The total distance walked by Shyam is-

Options---->6,9,16,12,8

Plz help me ...
Shyam's house,his office and his gym are all equidistant from each other. The distance between any 2 of them is 4km. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office. He then reverses direction and walks till he reaches a point directly south of his office . The total distance walked by Shyam is-

Options---->6,9,16,12,8

Plz help me ...

answer should be 12 :)

how make a equilateral triangle with base as house gym and top as office ...


we will walk parallel to House and office line and cover and will cover 4 km say till point r

then return back and make right angle triangle with Office ,Point R and his new Point ... = hence he will cover 8 more km... so answer is 8+4=12
answer should be 12 :)

how make a equilateral triangle with base as house gym and top as office ...


We will walk parallel to house and office line and cover and will cover 4 km say till point r

then return back and make right angle triangle with office ,point r and his new point ... = hence he will cover 8 more km... So answer is 8+4=12


thanks.....:)

Q) Find the GCD of the numbers 2n + 13 and n+7.
Ans : 1

Now by substituting values of n, i have deduced that the GCD will be 1. Can any1 provide a more rational explanation ??

I thought it would be better if i mention the problem here :

At a particular time in the 21st cebtury there were seven bowlers in the indian cricket team's list of 16 players shortlisted to play the next wc . Statisticians discovered that if u looked at the no of wickets taken by any of the 7 bowlers in the current indian cricket team , the number of wickets taken by them had a strange property . The numbers were such that for any team selection of 11 players (having 1 to 7 bowlers) by using the number of wickets taken by each bowler and attaching coefficients 0f +1 , 0 , -1 to eachvalue available and adding the resultant values , any number from 1 to 1093 both included could be formed . If we denote W1,W2,W3,W4,W5,W6,W7 as the 7 values in the ascending order what would be the answer to the following questions :

47) Find the value of W1+2W2+3W3+4W4+5W5+6W6
a) 2005 b) 1995
c)1985 d)NOT

4 Find the index of the largest power of 3 contained in the product W1 W2 W3 W4 W5 W6 W7
a) 15 b) 10
c) 21 d) 6

49) If the sum of the seven coefficients is 0 , find the smallest number that can be obtained

a) -1067 b)-729
c) -1040 d) -1053


Please help !!!!


>> There was a solution posted for this question by nitrjswcoke .... but that solution is itself confusing ..... can any1 be more explanatory on how to arrive onto that GP that nitrjswcoke has explained ????
Solution by nitrjswcoke on this page >> http://www.pagalguy.com/forum/quantitative-questions-and-answers/23813-quant-by-arun-sharma-382.html#post2873459
Block 1 Test Review



Review -1
Q11 . 139 person have signed up for an eliminating tournament. All player are to be prepared up for the first round but because 139 is an odd no. one player will get bye, which promotes him to the second round , without actually playing in the first round. The pairing continues, with a bye to any player left over. If the scheduled is planned so that minimize no. of matches required to determine the champion, the no. of matches which must be played is ?
  1. 136
  2. 137
  3. 138
  4. 139

Q13 . There are ten 50 paise coins placed on a table. Six of these show tail, 4 shows head. A coin chosen at random and flipped over(not tossed). This operation performed 7 times. One of the coin then covered . Of the remaining 9 coin five show tails 4 shows head. The covered coin shows
  1. Head
  2. Tail
  3. More likely head

  1. More likely tail

Q18 . It takes the pendulum of a clock 7 sec to strike 4 o'clock. How much time will it take to strike 11 o'clock?
  1. 18 sec
  2. 20 sec
  3. 19.25 sec
  4. 23.33 sec

Review - 2
Q11 . Abc is a 3 digit no. in which A>0. the value of Abc is equal to the sum of factorial of its 3 digits. What is the value of B?
  1. 9
  2. 7
  3. 4
  4. 2

Q20 . The infinite sum of 1 + (4/7) + (9/72) + (16/73) +
  1. 27/14

  1. 29/13

  1. 49/27
  2. 256/147

Q24 . A +ve whole no. M less than 100 is represented in base 2, 3 and 5. it is found that in all 3 cases the last digit is 1, while in exactly 2 out of 3 case the leading digit in 1. Then M equals:
  1. 31

  1. 63
  2. 75
  3. 91

Review 3
Q3 . Find the digit at ten's place of the no. N = 7281 * 3264
  1. 0
  2. 1
  3. 6

  1. 5

  1. None of these

Q10 . A one digit no. , which is the ten's digit of a 2 digit no . X is subtracted from X to give Y which is the quotient of the division of 999 by the cube of a no. find the sum of digits of x.
  1. 5

  1. 6

  1. 7

  1. 8

  1. 9

Q14 . The no. of +ve integer value pair (x, y). Satisfying 4x-17y= 1 and x
  1. 59

  1. 57

  1. 55
  2. 58
  3. None of these

Review 4
Q1. Find the no. of 6 digit no that can be formed using the digits 1,2,3,4,5,6 once such that 6-digit no. is divisible by it s unit digit:
  1. 648
  2. 528
  3. 728
  4. 128
  5. None of these

Review 5
Q3 . Find the highest power of 2 in 1! + 2! + 3!+.+600!
  1. 1
  2. 494
  3. 3.0
  4. 256
  5. None of these

Q7 . What is the remainder when 789456123 is divided by 999?
  1. 123
  2. 369
  3. 963
  4. 189

  1. 998

Q8 . What is the total no. of factor of 16! ?
  1. 2016

  1. 1024

  1. 3780

  1. 4032

My answer was coming 5376
Factors of 2 is 15, 3 is 6, 5 is 3 , 7 is 2, 11 is 1 and 13 is 1
So (15 +1) * (6+1)*(3+1)*(2+1)*(1+1)*(1+1) = 5376
Q9 . Find the sum of first 125 term of the sequence1,2,3,2,1,4,3,2,1,5,4,3,2,1
  1. 616

  1. 460

  1. 750
  2. 720
  3. 680

Q10 . Umesh purchased a tata nano recently , but the faulty car odometer of car proceeds from digit 4 to digit 6 always skipping digit 5, regardless of position. If the meter shows 003008(starting with 000000) how many km has nano actually travelled?
  1. 2100

  1. 1999

  1. 2194
  2. 2195
  3. None of these

Q11 . What is the remainder when 123412341234.. upto 100 digit is divided by 909?
  1. 623
  2. 650
  3. 685
  4. 675
  5. None of these

Q12 . Mr. Ramlal lived his entire life during his 1800s. In the last year of his life, ramlal stated: once I was x year old in the x^2. he was born in the year?
  1. 1822
  2. 1851
  3. 1853
  4. 1806
  5. 1830

Q16 . What is the remainder when 2^100 is divided by 101?
  1. 1
  2. 100
  3. 0
  4. 99
  5. None of these

Q17 . Find the last 2 digit of 2^134
  1. 04
  2. 84
  3. 24
  4. 64
  5. None of these



hey
how r u posting the qstns? as in mere paas to hardcopy hai 😞 pura qstn type krna padega.. how u doing it.. teme too please !!

cheers 😃 !!

i'm typing all the question.....I too have hardcopy only. Advantage here is I can copy and paste solution for these question and can keep it for future reference. I know it bit annoying or you can do one thing scan it and import as pdf then put it over here

Q) Find the GCD of the numbers 2n + 13 and n+7.
Ans : 1

Now by substituting values of n, i have deduced that the GCD will be 1. Can any1 provide a more rational explanation ??


To solve this Question, Euclid's Algorithm can be used as well.
Approach :
2n+13 = 1(n+7)+(n+6);
(n+7) = 1(n+6)+1;
(n+6) = (n+6)1+0:
The greatest common divisor equals to the last remainder in the Euclidean
algorithm, so it equals to 1.

====================================\

P.S. : Those who don't know about the algorithm, here are a few links
Euclidean Algo. : Euclidean algorithm
Video Link : Finding the GCF using the Euclidean Algorithm - YouTube
one more question puys.
find the three digit number if it is known that the sum of its digits is 17 and the sum of the squares of its digits is 109. If we subtract 495 from this number, we obtain a number consisting of the same digits written in reverse order.
thanks in advance ....


Let the number be abc.

Now, a+b+c = 17
a^2 + b^2 + c^2 = 109

100a + 10b + c - 495 = 100c + 10b + a
=> 99a - 99c = 495
=> a - c = 5

We have 3 equations in three variables.
Solving simultaneously we get,
a = 8, b = 6 and c = 3.

Number = 863...!!
Block 1 Test Review
Review -1
Q11 . 139 person have signed up for an eliminating tournament. All player are to be prepared up for the first round but because 139 is an odd no. one player will get bye, which promotes him to the second round , without actually playing in the first round. The pairing continues, with a bye to any player left over. If the scheduled is planned so that minimize no. of matches required to determine the champion, the no. of matches which must be played is ?
  1. 136
  2. 137
  3. 138
  4. 139

Q13 . There are ten 50 paise coins placed on a table. Six of these show tail, 4 shows head. A coin chosen at random and flipped over(not tossed). This operation performed 7 times. One of the coin then covered . Of the remaining 9 coin five show tails 4 shows head. The covered coin shows
  1. Head
  2. Tail
  3. More likely head

  1. More likely tail

Q18 . It takes the pendulum of a clock 7 sec to strike 4 o'clock. How much time will it take to strike 11 o'clock?
  1. 18 sec
  2. 20 sec
  3. 19.25 sec
  4. 23.33 sec

Review - 2
Q11 . Abc is a 3 digit no. in which A>0. the value of Abc is equal to the sum of factorial of its 3 digits. What is the value of B?
  1. 9
  2. 7
  3. 4
  4. 2

Q20 . The infinite sum of 1 + (4/7) + (9/72) + (16/73) +
  1. 27/14

  1. 29/13

  1. 49/27
  2. 256/147

Q24 . A +ve whole no. M less than 100 is represented in base 2, 3 and 5. it is found that in all 3 cases the last digit is 1, while in exactly 2 out of 3 case the leading digit in 1. Then M equals:
  1. 31

  1. 63
  2. 75
  3. 91

Review 3
Q3 . Find the digit at ten's place of the no. N = 7281 * 3264
  1. 0
  2. 1
  3. 6

  1. 5

  1. None of these

Q10 . A one digit no. , which is the ten's digit of a 2 digit no . X is subtracted from X to give Y which is the quotient of the division of 999 by the cube of a no. find the sum of digits of x.
  1. 5

  1. 6

  1. 7

  1. 8

  1. 9

Q14 . The no. of +ve integer value pair (x, y). Satisfying 4x-17y= 1 and x
  1. 59

  1. 57

  1. 55
  2. 58
  3. None of these

Review 4
Q1. Find the no. of 6 digit no that can be formed using the digits 1,2,3,4,5,6 once such that 6-digit no. is divisible by it s unit digit:
  1. 648
  2. 528
  3. 728
  4. 128
  5. None of these

Review 5
Q3 . Find the highest power of 2 in 1! + 2! + 3!+.+600!
  1. 1
  2. 494
  3. 3.0
  4. 256
  5. None of these

Q7 . What is the remainder when 789456123 is divided by 999?
  1. 123
  2. 369
  3. 963
  4. 189

  1. 998

Q8 . What is the total no. of factor of 16! ?
  1. 2016

  1. 1024

  1. 3780

  1. 4032

My answer was coming 5376
Factors of 2 is 15, 3 is 6, 5 is 3 , 7 is 2, 11 is 1 and 13 is 1
So (15 +1) * (6+1)*(3+1)*(2+1)*(1+1)*(1+1) = 5376
Q9 . Find the sum of first 125 term of the sequence1,2,3,2,1,4,3,2,1,5,4,3,2,1
  1. 616

  1. 460

  1. 750
  2. 720
  3. 680

Q10 . Umesh purchased a tata nano recently , but the faulty car odometer of car proceeds from digit 4 to digit 6 always skipping digit 5, regardless of position. If the meter shows 003008(starting with 000000) how many km has nano actually travelled?
  1. 2100

  1. 1999

  1. 2194
  2. 2195
  3. None of these

Q11 . What is the remainder when 123412341234.. upto 100 digit is divided by 909?
  1. 623
  2. 650
  3. 685
  4. 675
  5. None of these

Q12 . Mr. Ramlal lived his entire life during his 1800s. In the last year of his life, ramlal stated: once I was x year old in the x^2. he was born in the year?
  1. 1822
  2. 1851
  3. 1853
  4. 1806
  5. 1830

Q16 . What is the remainder when 2^100 is divided by 101?
  1. 1
  2. 100
  3. 0
  4. 99
  5. None of these

Q17 . Find the last 2 digit of 2^134
  1. 04
  2. 84
  3. 24
  4. 64
  5. None of these


This could be a clear case of COPYRIGHT VIOLATION :nono: , unless u have publisher's permission . Mods better look in this regard. People can ask questions without giving the exact question rather they can ask the concept involed

Even i had doubts in many chapters of Arun Sharma but i discussed the cocepts on this forum

block 1 test review



review -1
q11 . 139 person have signed up for an eliminating tournament. All player are to be prepared up for the first round but because 139 is an odd no. One player will get bye, which promotes him to the second round , without actually playing in the first round. The pairing continues, with a bye to any player left over. If the scheduled is planned so that minimize no. Of matches required to determine the champion, the no. Of matches which must be played is ?
  1. 136
  2. 137
  3. 138
  4. 139


sol:
At first round -69 matched to be played (with 138 palyers)


at second round -35 matches to be played(with 69 players from 1st round and 1 player who got bye at 1st round)


at third round - 17 matches to be played and one will get bye (with 35 players)


at 4th round - 9 matches to b played


at 5 th round - 4 matches to be played and one will get bye


at 6 th round - 2 matches to be played and one will get bye


at 7th round - 1 match to played and one will get bye


at 8th round - 1 matched to be played with 2 bowlers


now adding all matches = 69 + 35 + 17 + 9 + 4 + 2 + 1 + 1 = 138 matches
q13 . There are ten 50 paise coins placed on a table. Six of these show tail, 4 shows head. A coin chosen at random and flipped over(not tossed). This operation performed 7 times. One of the coin then covered . Of the remaining 9 coin five show tails 4 shows head. The covered coin shows
  1. head
  2. tail
  3. more likely head

  1. more likely tail


is it head??????////


review - 2
q11 . Abc is a 3 digit no. In which a>0. The value of abc is equal to the sum of factorial of its 3 digits. What is the value of b?
  1. 9
  2. 7
  3. 4
  4. 2.


is it 4 ??//////////

Block 1 Test Review

Review 3
Q3 . Find the digit at ten's place of the no. N = 7281 * 3264
  1. 0
  2. 1
  3. 6

  1. 5

  1. None of these

SOL:

FOR THESE TYPE OF QUESTIONS(MY WAY)

MULTIPLY LAST TWO TERMS OF BOTH NOS.

SO 81 * 64 = YX84

SO DIGIT AT TEN'S PLACE =8
SO NONE OF THESE


Q14 . The no. of +ve integer value pair (x, y). Satisfying 4x-17y= 1 and x
  1. 59

  1. 57

  1. 55
  2. 58
  3. None of these


AFTER SIMPLIFYING THE EQUATION;
4X- 17Y = 1
4X = 1+ 17Y

VALUES OF X AND Y SATISFYING THE EQUATION

X = COMMON DIFFERENCE=17

Y = COMMON DIFFERENCE=4

{NOTE:TO GET LAST VALUE OF X AS 999

DIVIDE 1000/17 = 58.82 (58*17=986)

BUT X IS STARTING FROM 13 (13 IS 4 LESS THAN 17)
AND SERIES OF X IS GOING IN THE SIMILAR FASHION.

SO THE 58 THE NO. =982
AND THE 59TH NO.= 999

REQUIRED ANSWER = 59

Review 4
Q9 . Find the sum of first 125 term of the sequence1,2,3,2,1,4,3,2,1,5,4,3,2,1
  1. 616

  1. 460

  1. 750
  2. 720
  3. 680

AM GETTING 760 AS ANSWER .

Q12 . Mr. Ramlal lived his entire life during his 1800s. In the last year of his life, ramlal stated: once I was x year old in the x^2. he was born in the year?
  1. 1822
  2. 1851

  1. 1806
  2. 1830

DIDN'T GET THE QUESTION
Q16 . What is the remainder when 2^100 is divided by 101?
  1. 1
  2. 100
  3. 0
  4. 99
  5. None of these

THERE IS FORMULA FOR THIS :

P^N-1/N =R(1)
Q17 . Find the last 2 digit of 2^134
  1. 04
  2. 84
  3. 24
  4. 64
  5. None of these


[(2)^10}^13 * 2^4

(24)^13 * 16

24 * 16

so last two digits = 84

SOL:

FOR THESE TYPE OF QUESTIONS(MY WAY)

MULTIPLY LAST TWO TERMS OF BOTH NOS.

SO 81 * 64 = YX84

SO DIGIT AT TEN'S PLACE =8
SO NONE OF THESE





AFTER SIMPLIFYING THE EQUATION;
4X- 17Y = 1
4X = 1+ 17Y

VALUES OF X AND Y SATISFYING THE EQUATION

X = COMMON DIFFERENCE=17

Y = COMMON DIFFERENCE=4

{NOTE:TO GET LAST VALUE OF X AS 999

DIVIDE 1000/17 = 58.82 (58*17=986)

BUT X IS STARTING FROM 13 (13 IS 4 LESS THAN 17)
AND SERIES OF X IS GOING IN THE SIMILAR FASHION.

SO THE 58 THE NO. =982
AND THE 59TH NO.= 999

REQUIRED ANSWER = 59

Review 4






AM GETTING 760 AS ANSWER .



DIDN'T GET THE QUESTION


THERE IS FORMULA FOR THIS :

P^N-1/N =R(1)

IS IT NONE OF THESE??????????/


@rakesh the last two digits of 2^134
(2^10)^13*16
24^13*16
24*16=84
so ans should be 84
plz correct me 😃