The average speed of a train is 20% less on the return journey than on the onward journey.The train halts for half an hour at the destination station before starting on the return journey.If the total time taken for the to and fro journey is 23 hours,covering a distance of 1000 km ,the speed of the train is
a)60 km/hr b)40 km/hr c)50 km/hr
pls expain with full approach.
Ratio of speed = 1 : 1.2 = 5 : 6 Time taken during journey = 23 - 1 = 22 Ratio of time taken(onward : return journey) = > 5x + 6x = 22 => x = 2 => time taken is 10hr and 12hr so speed = 500/10 = 50 * it's better to solve these kind of questions using ratio method. This way you won't even need a pen.
Two trains move from station A and station B towards each other at the speed of 50 km/hr and 60 km/hr.At the meeting point,the driver of the second train felt that the train has covered 120 km more.What is the distance between A and B?
a)1320km b)1100km c)1200km d)960km
pls do show the whole process.
Ratio of speed = 50:60 = 5:6 *ratio of distance covered will be same as ratio of speed(as time is same) ratio of distance covered by each train = 5 : 6 6x - 5x = 120 x = 120 Total Distance = 5x + 6x = 11*120 =1320
I am thinking of solving this book for CAT2012..?? but somebody has told me that this book doesn't have detailed solution . Is this true ..??
yes you are correct that this book doesn't have detailed solution...but still i would say go for it..because it is the best book for quant...and i think you won't be needing solution and for any problem you have this thread....
yes you are correct that this book doesn't have detailed solution...but still i would say go for it..because it is the best book for quant...and i think you won't be needing solution and for any problem you have this thread....
what about Arun sharma's DI-LR does that book also have the same issue??
If you subtract Re1 from the money bholu has ,take its reciprocal,then add it to the square of the money and subtract the money bholu has,you get two rupees more than the reciprocal of money after subtracting 1 from it.Find the money bholu has?
If you subtract Re1 from the money bholu has ,take its reciprocal,then add it to the square of the money and subtract the money bholu has,you get two rupees more than the reciprocal of money after subtracting 1 from it.Find the money bholu has?
If you subtract Re1 from the money bholu has ,take its reciprocal,then add it to the square of the money and subtract the money bholu has,you get two rupees more than the reciprocal of money after subtracting 1 from it.Find the money bholu has?
pls show the detailed sol.
bholu has x rs x-1 x^2 + 1/(x-1) - x = 2+ 1/(x-1) x2 -x -2 = = x = 2
Q: Find the unit digit of the expression 55^725+73^5810+22^853 options: a.4 b.0 c.6 d.5
can anyone please explain what is the shortest way to solve this kind of problems?
divid the powr by 4 ..nd find the re:ainder..like 73^5810 .;we find the reamander 2 .so unit digit of 73 is 3 ..so sqre the unit digit nd hnce get the unit digit as 9..isi tarah baki sbaka nikal lo...
1) In a chess tornament 16 members played in tournament x and 20 played in tournament y and. 12 in both the tournaments,if each player played atleast one of these tournaments,what is the total number of players?? a)24 b)36 c)32 d)48
2)the number of bacteria in a test tube doubles every 3 mins.if at the end of 1 hour there are N bacteria in the test tube,at the end of how many minutes were there exactly N/4 bacteria? a) 51 b) 54 c) 56 d) 58
3) In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is : (a) 20 m (b) 22 m (c) 24 m (d) 26 m pls explain with step in detail
2)the number of bacteria in a test tube doubles every 3 mins.if at the end of 1 hour there are N bacteria in the test tube,at the end of how many minutes were there exactly N/4 bacteria? a) 51 b) 54 c) 56 d) 58
answer for this question is option (B) easy one.... look at 60 min there are N bacteria this means at 57 there will b N/2 bacteria because they doubles every 3 minutes hence at 54 there will be N/4..other wise N bacteria are not possible at 60 mins p.s.-will solve remaining later.... p.p.s.-kittu ji elitmus ka exam kaisa hua????????
1) In a chess tornament 16 members played in tournament x and 20 played in tournament y and. 12 in both the tournaments,if each player played atleast one of these tournaments,what is the total number of players?? a)24 b)36 c)32 d)48
2)the number of bacteria in a test tube doubles every 3 mins.if at the end of 1 hour there are N bacteria in the test tube,at the end of how many minutes were there exactly N/4 bacteria? a) 51 b) 54 c) 56 d) 58
3) In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is : (a) 20 m (b) 22 m (c) 24 m (d) 26 m pls explain with step in detail
1) My take is 24. P(x y) = P(x) + P(y) - P(x y) => P(x y) = 16 + 20 - 12. = 24.
2) My take is 54. The test tube will be full (N) at the 60th minute. 57th (60 - 3) minute pe N/2. 54th(57 - 3) minute pe N/4.
3) My take is 24m. 1m+1m from the boundary. 2m*11 between trees. Total = 2m + 22m = 24m.
Hi puys, Started with P&C; and stuck with 1 ques in LOD 1. I think the ans key is wrong. Pls reply:
LOD-1 ------
29) How many ways are there to choose 4 cards of different suits and different values from a deck of 52 cards? Ans given: 13.12.11.10 I got: 52.36.22.10
Hi puys, Started with P&C; and stuck with 1 ques in LOD 1. I think the ans key is wrong. Pls reply:
LOD-1 ------
29) How many ways are there to choose 4 cards of different suits and different values from a deck of 52 cards? Ans given: 13.12.11.10 I got: 52.36.22.10
Well actually the answer given is absolutely correct. Lets see, there are 4 suits in a regular deck of cards -> Hearts, Diamonds, Spades & Clubs. Each suit has 13 cards each,ie, 13*4 = 52 total cards. Now the question says that the card should be from a different deck and of a different value. Choose from Hearts -> 13C1 (suppose the card that came out was an Ace). Now we cannot choose ace so from the next suit the options would be 12C1. Similarly, 11C1 and 10C1. Hence our answer becomes = 13*12*11*10.
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Why was your answer incorrect was because; U did 52C1 -> this is correct as this would give one card of any suit and some value. now when u subtract 16 (to eliminate the same suit and that value of that card), then from a deck of 52 cards it doesnt ensure that ur subtracting the correct suit. you cannot be sure. Hence the answer given is correct.
1)What is the product of the irrational roots of the equation (2x-1)(2x-3)(2x-5)(2x-7)=9? (a)3/2 (b)4 (c)3 (d)3/4 Ans. (a)
2)In an examination, 35% candidates failed in one subject and 42% failed in another subject while 15% failed in both the subjects. If 2500 candidates appeared in the examination, how many passed in either subject but not in both? a) 325 b) 1075 c) 1175 d) 2125 e) 2250
