Quant by Arun Sharma

MBA CAT 2024
4583
Puys i got stuck on these problems...any suggestions

1.P(x) is a degree 2 polynomial in x. It leaves remainder 5 on division by (x - 1) and remainder 2 on
division by (x + 2). When P(x) is divided by (x - 1) (x + 2) then find the remainder.

2.If zeroes of the polynomial f(x) = x3 - 3px2 + qx - r are in A.P., then find the value of 2p3.

how come i hv nt a single attempt at this problem...common puys give it a shot..im getting nowhere on this problem
4584
pallavi70 Says
puys can somebody solve this question??


Rs .94435 was the gain man got by adding some water in milk....
So the amount of water he added in milk amounts to Rs.94435 .
Therefore, amount of milk that can be bought from Rs.94435 is->
(.94435/8.5) results in .1111L. :)

P.S. Correct if m wrong somewhere puys....
4585
ayush2011 Says
waiting fr the solution as i feel by my approach it should be 6


jst focus on the Unit Digits.... (5)^725 ....Acc. to 5 's, it wil always result in a number ending with 5..
For (3)^5810 .. Acc. to 3's cyclicity,5810%4 =2 .. From its cyclicity,on 2nd position its.. 9 .
For(2)^853..Acc. to 2's cyclicity,853%4 =1 .. From its cyclicity,on 1st position its.. 2 .
Adding them will result 5+9+2=16..Therfore.. 6 will be the unit Digit.. 😃
4586

At an election, the candidate who got 56% of the votes cast won by 144 votes. Find the total number of voters on the voting list if 80% people cast their vote and their were no invalid votes.
360
720
1800
1500
1600

4587

Let no of votes be x
80 % of (56 % - 44 %) = 144
So 80/100 * ( 56/100 -44/100 ) =144
So x should be 1500

4588
Puys i got stuck on these problems...any suggestions

1.P(x) is a degree 2 polynomial in x. It leaves remainder 5 on division by (x - 1) and remainder 2 on
division by (x + 2). When P(x) is divided by (x - 1) (x + 2) then find the remainder.

2.If zeroes of the polynomial f(x) = x3 - 3px2 + qx - r are in A.P., then find the value of 2p3.


1.) If the polynomial P(x) is divided by (x a), then the remainder
is P(a)

Let P(x) = (x-1)*(x+2)*f(x) + (ax+b)

Given: P(1) = 5 and P(-2) = 2
=> a+b = 5 and -2a+b = 2
=> a = 1 and b = 4

Therefore:
P(x) = (x-1)*(x+2)*f(x) + (x+4)
Remainder when P(x) is divided by (x-1)*(x+2) = (x+4)

2.) f(x) = x^3 - 3px^2 + qx - r
Given: The root of this equation are in A.P. Let the roots be a,b,c and
2b = (a+c)

=> a+b+c = 3p
=> 3b = 3p
=> b = p ----1

Also, abc = r
=> ac = r/p -----2

And ab+bc+ca = q
=> b(a+c) + ac = q
=> 2p^2 + r/p = q
=> 2p^3 = pq - r
4589
At an election, the candidate who got 56% of the votes cast won by 144 votes. Find the total number of voters on the voting list if 80% people cast their vote and their were no invalid votes.
360
720
1800
1500
1600


My take is 1500. Calculated assuming total vote as 100.
4590

In an exam 48% failed in hindi and 32% failed in history, 20% failed in both the subjects.If number os students passed the exam is 880. How many students appear in the examination?

option: a. 2000 b.2200 c.2500 d.none of these

4591
In an exam 48% failed in hindi and 32% failed in history, 20% failed in both the subjects.If number os students passed the exam is 880. How many students appear in the examination?

option: a. 2000 b.2200 c.2500 d.none of these


n(AUB) = n(A) + n(B) - n(A intersection B) = 48+32 - 20 = 60
=> 60% failed
=> 40% passed
=> 0.4 x = 880
=> x = 2200
4592
n(AUB) = n(A) + n(B) - n(A intersection B) = 48+32 - 20 = 60
=> 60% failed
=> 40% passed
=> 0.4 x = 880
=> x = 2200


Liked your approach...it took almost 2minutes for me to do the same prob..
but your approach is really good...thanks for sharing...:thumbsup:
4593

Arushi's project consist of 25 pages each of 60 lines with 75 characters on each line. In case of number of lines reduced to 55 but the number of characters is increased to 90 per lines, What is the percentage change in number of pages.
a. 10% b.5% c.-8% d.-10%

Guys please mention your approach also..

4594
Arushi's project consist of 25 pages each of 60 lines with 75 characters on each line. In case of number of lines reduced to 55 but the number of characters is increased to 90 per lines, What is the percentage change in number of pages.
a. 10% b.5% c.-8% d.-10%

Guys please mention your approach also..

Total characters = 25*60*75
New total = Old total = x*55*90
=> x = (25*60*75)/(55*90) = 22.7
=> x ~ 23
=> % drop = (25-23)/25 = 8%
4595

Ravi's monthly salary is A rupees. Of this, he spends X rupees. The next month he has an increase of C% in his salary and D% in his expenditure. The new amount saved is :
A(1+c/100)-X (1+D/100)
(A/100)(C-(D)X(1+D/100)
X(C-(D)/100
X(C+D)/100

4596
Ravi's monthly salary is A rupees. Of this, he spends X rupees. The next month he has an increase of C% in his salary and D% in his expenditure. The new amount saved is :
A(1+c/100)-X (1+D/100)
(A/100)(C-(D)X(1+D/100)
X(C-(D)/100
X(C+D)/100


..........Salary......................Expenditure......................Savings
............A.................................X...............................(A-X).....
.......A*(1 + C/100)..............X*(1 + D/100)....................S......

=> S = A*(1 + C/100) - X*(1 + D/100)
4597
Ravi's monthly salary is A rupees. Of this, he spends X rupees. The next month he has an increase of C% in his salary and D% in his expenditure. The new amount saved is :
A(1+c/100)-X (1+D/100)
(A/100)(C-(D)X(1+D/100)
X(C-(D)/100
X(C+D)/100


(A+AC/100)-(X+DX/100)
=A(1+c/100)-X (1+D/100)
4598
guyz tell me one thngh is ....arun sharma sufficient...or we shud refer ne othr materials....
4599

After 3 equal percentage rise in the salary the sum of 100 rupees turned into140 rupees and 49 paisa.
Find the Percentage rise in the salary?
a. 12% b.22% c.66% d.82%

4600
After 3 equal percentage rise in the salary the sum of 100 rupees turned into140 rupees and 49 paisa.
Find the Percentage rise in the salary?
a. 12% b.22% c.66% d.82%


My take is 12%

Yar this question actually needs no calc.
100 in first 12% increase becomes 112.
in the next lets take 10% instead of 12, this wld make the sum arnd 123+ say 125.xx
in the next also 125.xx ka 10% will yield something aroung 150. which is very close to our result. hence 12%.

Waise even this is not required. when we look at the options the second least is 22%, in the first term the sum becomes 122. toh 3 times mein it wld go way over 150. Hence sidha 12% mark kardo.

Ps - Dont apply this method in very close options.

And if u want to go with a method then;
((100+x)/100)^3=140.49.
this can be solved with the help of options...12% satisfies the condition.
4601
sassy23 Says
guyz tell me one thngh is ....arun sharma sufficient...or we shud refer ne othr materials....



Yes LOD I and LOD II are sufficient assuming that you would appear in a test series from TIME/CL/IMS and analyze your mocks properly and religiously.
4602

In a village consisting of p persons,x% can read and write. Of the males alone y%, of the females alone z% can read and write. Find the number males in village in terms of p,x,y,z if z