hey I know this approach but here we have zero starting from 5! and it will include all from 6 to 50 so the answer here is 262 I wanted to know how Thanks
solution is simple we just have to look for the number of 42 we can form by these digits...42=2*3*7now by looking at number you can see that there are good amount of 2 and 3 are present....so just for the number of 7 present in this multiplication....that is there are three 7 are present...hence n=3i hope this help..
solution is simple we just have to look for the number of 42 we can form by these digits... 42=2*3*7 now by looking at number you can see that there are good amount of 2 and 3 are present.... so just for the number of 7 present in this multiplication....that is there are three 7 are present... hence n=3
i hope this help..
look yaar for making 42 we need 2*3*7....but we can see there are a lot of 2 and 3...so case will lie totally on 7....reason for this is the fact that for making 42 we need all the 3 numbers in equal quantity now split every number once by yourself you will get your answer... if not then pm i will solve this again...
dude answer in book is correct from my point of view.... you need to check power of 3...which will be there..which will come to 75.... @thinkace bhai correct me if i am wrong......
find the maximum value of n such that 157! is perfectly divisible by 18^n????
can u plz explain how ?18 =3^2 *2 ,so if i proceed like 157/3+157/9+157/27+157/81 idont get the anser??
dude your approach is cent percent correct.... by this you will get there are 75...3 present in 157!.... but you need 3^2(or 9) to make 18...hence there can only be 37...9 can be made.. 37*2=74...in he end only one 3 will be left and there is no possible way to form 18 by that...
i hope his will help...pm me if you have any problem...
Puys i got stuck on these problems...any suggestions
1.P(x) is a degree 2 polynomial in x. It leaves remainder 5 on division by (x - 1) and remainder 2 on division by (x + 2). When P(x) is divided by (x - 1) (x + 2) then find the remainder.
2.If zeroes of the polynomial f(x) = x3 - 3px2 + qx - r are in A.P., then find the value of 2p3.
please help me out with below problems from avg and alligation 1. A train travels 8km in teh first quarter of an hour, 6km in the 2nd quarter and 40km in the 3rd quarter. Find the average speed of teh train per hour over the entire journey. a.72km/h b. 18km/h c.77.33km/h d. 78.5km/h e. 79km/h
2.A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 25%. Find the % of adulterated fat in the mixture assuming that adulterated fat is freely available. a. 20% b. 25% c.33.33% d.40% e. 35%
3. A man buys milk at rs. 8.5 per litr and dilutes it with water. He sells the mixture at the same rate and thus gains 11.11% .Find the quantity of water mixed by himin every litre of milk a. 0.111 litres b.0.909 litr c. 0.1 litre d. 0.125 litre
please help me out with below problems from avg and alligation 1. A train travels 8km in teh first quarter of an hour, 6km in the 2nd quarter and 40km in the 3rd quarter. Find the average speed of teh train per hour over the entire journey. a.72km/h b. 18km/h c.77.33km/h d. 78.5km/h e. 79km/h
2.A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 25%. Find the % of adulterated fat in the mixture assuming that adulterated fat is freely available. a. 20% b. 25% c.33.33% d.40% e. 35%
my take on 1st ques-option (B) 2nd ques-option (A) let me know are they correct then i will post my approach.
Q: Find the unit digit of the expression 55^725+73^5810+22^853 options: a.4 b.0 c.6 d.5
can anyone please explain what is the shortest way to solve this kind of problems?
Is the answer 6?? y approach to these problems would be as follow: 1. instead of concentrating on the entire no. jst concentrate on the last digit of the base(becaz the unit digit of the answer will purely depend on that) 2. Find the period in which the divisor is repeating Soln: the question can be rearranged as to find the unit digit of 5^725+3^5810+2^853(1st step) 2. Find the periodicity for 5 its simple tht 5 raised to odd powers will end in 5 for 3 the last digit repeats as 3,9,7,1,3,9(so here the period is 4) for 2 the digit repeats as: 2,4,8,6,2,4(here also period is 4) so 3^5810= 3^(4*1452+2)= 3^2=9(we r only interested in last digit) 22^853= 2^853=2^(4*413+2^1)=2^1=2 thus the last digit of the expression is the last digit of 5^5+3^2+2^1=5+9+2=6 (ans)
Puys i got stuck on these problems...any suggestions
1.P(x) is a degree 2 polynomial in x. It leaves remainder 5 on division by (x - 1) and remainder 2 on division by (x + 2). When P(x) is divided by (x - 1) (x + 2) then find the remainder.
2.If zeroes of the polynomial f(x) = x3 - 3px2 + qx - r are in A.P., then find the value of 2p3.
