Apologies for the repost but i require some help with this one as well
What is the smallest positive integer k such that C(2k, k) is divisible by 200?
a 23
b 61
b 13
d 11
Apologies for the repost but i require some help with this one as well
What is the smallest positive integer k such that C(2k, k) is divisible by 200?
a 23
b 61
b 13
d 11
C(2k,k)=2k!/k!k!=2k(2k-1)(2k-2)......(k+1)/k!
This will always be divisible by 2....so you basically have to find k such that the power of 5 in numerator is 2 more than that in denominator.....
In other words, there has to be a multiple of 5^2 in between k and 2k....
Smallest possible multiple is 25....smallest possible value of k will therefore be 25.....but k has to be an integer so 2k=26 or k =13....
can any one help me with these questions.....
1)find the GCD of 2n+13 and n+7
load 3 q 38
2)n is a number such that 2n has 28 factors and 3n has 30 factors 6n has?????
thanks in advance
The sole purpose of thisThread is to bring together the CAT aspirants who are solving the Quant book by Arun Sharma. This will be a common place to discuss any doubts while solving the questions. As there are many questions in the book where either the Hint/Solution is missing or the answer itself is wrong. It will be very nice of you all to help people clear their doubts and also they could learn various methods of problem solving.
:grab:
Thread is to bring together the CAT aspirants who are solving the Quant book by Arun Sharma. This will be a common place to discuss any doubts while solving the questions. As there are many questions in the book where either the Hint/Solution is missing or the answer itself is wrong. It will be very nice of you all to help people clear their doubts and also they could learn various methods of problem solving.Hi guys...
Please let me know if there is an equation between the length of interior tangent and exterior tangent when the radius of circles are given..?
Thanks
Sumesh M
Hi guys...
Please let me know if there is an equation between the length of interior tangent and exterior tangent when the radius of circles are given..?
Thanks
Sumesh M
TBH i'm not able to visualize the notion of an interior tangent. The only way i can think of is there would be two circles one completely inside the other, and from an external point P two tangents one to the smaller ("interior tangent") the other to the larger (exterior tangent). If this is the case you can get the length relation by the Tangent-Secant theorem
Some1 else can surely improvise and throw more light on this
the largest 4 digit no. which can be added to 7249 in order to make the derived no divisible by 12,14,21,33 and 54?
puys if u r getting 9383 as the answer pls explain the solution
A five digit number is taken. Sum of first four digits (excluding the unit digit) is equal to sum of all the five digits. Which of the following will not divide the number necessarily?
a)10
b)2
c)4
d)5
e)none
Answer given in the book is c) 4.
But I think that is wrong. Answer should be e) none. Because we are given that sum of first 4 digits is equal to sum of five digits. so number can be 12300.here sum of first four digit = 6. Sum of first five digit = 6. And this number is obviously divisible by four.
Please tell me if I am right or not?
A number 15B is divisible by 6. Which of these will be true about the positive integer B?
a)B will be even
b)B will be odd
c)B will be divisible by 6
d)both a and c
e)none.
Please help.
A five digit number is taken. Sum of first four digits (excluding the unit digit) is equal to sum of all the five digits. Which of the following will not divide the number necessarily?
a)10
b)2
c)4
d)5
e)none
Answer given in the book is c) 4.
But I think that is wrong. Answer should be e) none. Because we are given that sum of first 4 digits is equal to sum of five digits. so number can be 12300.here sum of first four digit = 6. Sum of first five digit = 6. And this number is obviously divisible by four.
Please tell me if I am right or not?
It's saying necessarily.
As it is saying 1-4 ka sum is equal to 1-5 ka sum. That means the fifth digit(unit digit) is 0. Matlab the number would necessarily be divisible by only 2, 5 and 10.
For example: 11210. not divisible by 4 according to my calcy.
Hope I ne ki madad.
AT
A five digit number is taken. Sum of first four digits (excluding the unit digit) is equal to sum of all the five digits. Which of the following will not divide the number necessarily?
a)10
b)2
c)4
d)5
e)none
Answer given in the book is c) 4.
But I think that is wrong. Answer should be e) none. Because we are given that sum of first 4 digits is equal to sum of five digits. so number can be 12300.here sum of first four digit = 6. Sum of first five digit = 6. And this number is obviously divisible by four.
Please tell me if I am right or not?
What if you take 12310 instead of 12300?? it won't be divisible be 4.....
So its not necessarily divisible by 4......it may or may not be depending on the number.....
A number 15B is divisible by 6. Which of these will be true about the positive integer B?
a)B will be even
b)B will be odd
c)B will be divisible by 6
d)both a and c
e)none.
Please help.
B can only be 0 or 6
so answer wud be:
d) both a & c
B can only be 0 or 6
so answer wud be:
d) both a & c
B can only be 6....0 is not a positive integer......
Answer would be d) though....
A five digit number is taken. Sum of first four digits (excluding the unit digit) is equal to sum of all the five digits. Which of the following will not divide the number necessarily?
a)10
b)2
c)4
d)5
e)none
Answer given in the book is c) 4.
But I think that is wrong. Answer should be e) none. Because we are given that sum of first 4 digits is equal to sum of five digits. so number can be 12300.here sum of first four digit = 6. Sum of first five digit = 6. And this number is obviously divisible by four.
Please tell me if I am right or not?
now divisibility for 4 is that last 2 characters should be divisible by 4
consider the number 12310,since 10 is not divisible by 4
so divisibility by 4 not necessary
Is this the book you guys are referring as 'RS AGGARWAL QUANT for CAT'?
I bought this one. Is it the right one?
Is this the book you guys are referring as 'RS AGGARWAL QUANT for CAT'?
I bought this one. Is it the right one?
R.S Aggarwal is not meant for CAT/XAT level exams.It doesn't have the questions that are of CAT/XAT standard.I think you confused R.S Aggarwal's QUANT BOOK(which is not for CAT) with SARVESH VERMA'S QUANTUM CAT(which is for CAT and other MBA exams).
the largest 4 digit no. which can be added to 7249 in order to make the derived no divisible by 12,14,21,33 and 54?
puys if u r getting 9383 as the answer pls explain the solution
LCM of 12,14,21,33,54 is 8316
8316 is the least number which is divisible by all these numbers.
Therefore 8316*2-7249= 9383 is the largest 4 digit number
Need the working steps of these questions?
1)There were 42 students in a hostel.Due to the admission of 13 students, the expenses of the mess increase by Rs.31 per day while the average expenditure per head diminished by Rs.3.What was the original expenditure of the mess?(ans-633.23)
2)The average price of 3 diamonds is Rs.97610498312, if their prices are in the ratio 4:7:9.The price of the cheapest is:
3)A man covers 1/3rd of his journey by cycle at 50 km/h, the next 1/3rd by car at 30 km/h and the rest by walking at 7 km/h.Find his average speed during the whole journey(ans-15.3 km/h)
4)With an average speed of 40 km/h, a train reaches its destination in time.If it goes with an average speed of 35 km/h, it is late by 15 minutes. The length of the total journey is(ans-70 km)
Need the working steps of these questions?
1)There were 42 students in a hostel.Due to the admission of 13 students, the expenses of the mess increase by Rs.31 per day while the average expenditure per head diminished by Rs.3.What was the original expenditure of the mess?(ans-633.23)
2)The average price of 3 diamonds is Rs.97610498312, if their prices are in the ratio 4:7:9.The price of the cheapest is:
3)A man covers 1/3rd of his journey by cycle at 50 km/h, the next 1/3rd by car at 30 km/h and the rest by walking at 7 km/h.Find his average speed during the whole journey(ans-15.3 km/h)
4)With an average speed of 40 km/h, a train reaches its destination in time.If it goes with an average speed of 35 km/h, it is late by 15 minutes. The length of the total journey is(ans-70 km)
1) let per head price be x
so, 42x+31 = 42+13(x-3)
=> x=15.
=>total expenditure =42*x
=15.33
i.e the answer choice
2) let the distance be 1050 (LCM of 5,3 7)
since we need to split the distance by 3 better we take distance as 105*3 = 315
now calculate time taken by each,
105/ 50 =2.1
105/30=3.5
105/7=15
total time= 20.6
Av speed = total Distance(315)/ total time(20.6)
=3150/206
=10+(1090/206)
=10+ ~5
can approximate from answer choice hereafter
4) S1 = 40km/hr
S2=35km/hr
S2= 7/8 S1
hence, T2= 8/7 T1
or T2= T1+ T1
now this increased time is given as 15 mins or T1 =15
hence T1 (actual time, without delay)= 105 mins
With speed 40km/hr, Distance travelled in 105 mins(1 hr 45 mins)
= 40+ (40/60 *45)
=40+30= 70km
what is latest version of arun sharma books of quant , verbal and LR Di ?
- How To Prepare For Data Interpretation & Logical Resoning For The Cat, 6/e
- How To Prepare For Verbal Ability And Reading Comprehensive For The Cat, 4/e
- How To Prepare For Quantitative Aptitute For The Cat, 4/e
are thse latest ones?
lcm of 12,14,21,33,54 is 8316
8316 is the least number which is divisible by all these numbers.
Therefore 8316*2-7249= 9383 is the largest 4 digit number
how please?????