no ...it is 66(2/3) % .....not 50%
pkaman SaysIs the answer 50 % ?
no it is 100 %....
hi there,
how did you find the no 32 here? what is the significance ..?
Posting a question from Geometry LOD 2
in attachments
21961
and also ataching download link
Image Upload !
will upload OA soon 
Posting a question from Geometry LOD 2
in attachments
21961
and also ataching download link
Image Upload !
will upload OA soon
Not clear the lengths of which segments are given....
Since all are composite numbers and all are co-prime to each other, we can say that all the numbers are product of prime numbers.
Also, 32 is greater than 1000, both the prime numbers in the product can not be greater than 31.
So, basically we just have to count number of prime numbers less than or equal to 31, i.e., 11 in numbers.
Also, we can have 1, as its neither prime nor composite.
=> We can have 12 number of elements
hi there,
how did you get 32..? what's the significance????????
Hi there,
Can anyone pleazee tell me the solution to Arun sharma page 73, LOD II, question 42-43.. (The Burger King one!!)
nishant_88 SaysNot clear the lengths of which segments are given....
reuploading 2nd image with clarity
21962
hope its clear now
Hi there,
Can anyone pleazee tell me the solution to Arun sharma page 73, LOD II, question 42-43.. (The Burger King one!!)
pls post full question,
everyone has different edition of Arun Sharma
@ myalterego
pls post full question,
everyone has different edition of Arun Sharma
Yes provide full Info abt the question...m hvng the 4rth Edition...
reuploading 2nd image with clarity
21962
hope its clear now
Triangle AOD is similar to Triangle COB.
AO/CO = OD/OB
3/(x-3) = (x-5)/(3x-19)
9x-57 = x^2 - 8x + 15
x^2-17x+72 = 0
(x-8 )(x-9)=0
x=8,9
x=8,9
Yes answer is (a) x =8,9
Uploading another question
Mensuration LOD 2
21963
will post OA when someone provides the right solution
Uploading another question
Mensuration LOD 2
21963
will post OA when someone provides the right solution
Well u kno, u could solve using some trigonometry, but knowing that 6 circles area = 6PiR^2 = 19R^2 (Roughly), we know that our triangle's area would be more than that.
Computing the options to rough estimates
a) 15R
b) 9R^2
c) 24R^2
d) 8R^2
Only option C) matches up
ELSE
In the attached image,
Side of triangle = 4R +2Sqrt(3)R
Area of triangle = Sqrt(3)/4 * (Side)^2
Area comes out to be = R^2(12+7Sqrt(3))
Well u kno, u could solve using some trigonometry, but knowing that 6 circles area = 6PiR^2 = 19R^2 (Roughly), we know that our triangle's area would be more than that.
Computing the options to rough estimates
a) 15R
b) 9R^2
c) 24R^2
d) 8R^2
Only option C) matches up
ELSE
In the attached image,
Side of triangle = 4R +2Sqrt(3)R
Area of triangle = Sqrt(3)/4 * (Side)^2
Area comes out to be = R^2(12+7Sqrt(3))
thats correct. Just the shortcut I needed in such questions
OA R^2(12+7Sqrt(3))
Here is the the question:
Q. 13 LOD-2 Geometry
If ABC is a quarter and a cirlce is inscribed in it and if AB = 1cm , find the radius of the smaller circle.
I m not sure how to provide you fig. here...i hope u guys can draw the pic by yourself...
Please help
Hi there,
you can get the sol from the ans choices itself.
Inner circle will have a radius less than 0.5
the only ans choice satisfying this is (a).
pls post full question,
everyone has different edition of Arun Sharma
hi there
please find the Q below.
A machine makes different sort of burgers by adding different fillings on a common bread.
the machine makes burger at the rate of 1 burger per half a minute.various fillings are added to the burger in the following manner:
1 5 9 .. . .... .are filled with chicken
2 9 16 ....... . .are filled with veg.
1 5 9 .. . .... .are filled with mushroom
and the rest with cheese and tomato.
machine makes exactly 660 burgers per day.
a) how many burgers per day are made with cheese and tomato fillings:
236
424
237
none of these
b) how many burgers with all three fillings -chicken,veg,mushroom
23
25
24
26
hi there
please find the Q below.
A machine makes different sort of burgers by adding different fillings on a common bread.
the machine makes burger at the rate of 1 burger per half a minute.various fillings are added to the burger in the following manner:
1 5 9 .. . .... .are filled with chicken
2 9 16 ....... . .are filled with veg.
1 5 9 .. . .... .are filled with mushroom
and the rest with cheese and tomato.
machine makes exactly 660 burgers per day.
a) how many burgers per day are made with cheese and tomato fillings:
236
424
237
none of these
b) how many burgers with all three fillings -chicken,veg,mushroom
23
25
24
26
my take in bold
Soln
there are 2 series to be considered here
1,5,9..
2,9,16
first find total number of terms in both series
Now comes the tough part removing the numbers repeated twice like 9,37 etc
In order to get those you need to take the lcm of 4 and 7(D1 and D2)=28
so the repeating series become 9,37,65....
Hope the concept is clear now......
a-424
b-24
- Trick is to find the last term in each of these series and hence evaluate the no of terms in each of them .
Plus a the no of burgers having all three fillings can be found by a simple look at the series which reveals a series with an initial term 9 and a comman difference of 28 .
Hope this helps
1)Computer takes an input of a number N and X where X is a factor of the number N.N is 83p796161q and X is equal to 11 where o