A number xy is multiplied by another number ab and the result comes as pqr ,where r=2y, q=2(x+y) and p=2r where p=2x where x,y pls give detailed solution
xy*ab = pqr
ab(10x + y) = 200x + 20x + 20y + 2y = 220x + 22y = 22(10x + y)
=> ab = 22
xy*ab = pqr
ab(10x + y) = 200x + 20x + 20y + 2y = 220x + 22y = 22(10x + y)
=> ab = 22
x and y are two positive integers.then what will be the sum of the co-officients of the expansion of the expression (x+y)^44
Plz xplain
x and y are two positive integers.then what will be the sum of the co-officients of the expansion of the expression (x+y)^44
Plz xplain
is it 2^44
putting x=1 and y=1
x and y are two positive integers.then what will be the sum of the co-officients of the expansion of the expression (x+y)^44
Plz xplain
2^44.....
very convincing solution. thank u very much
1)What is the total number of divisors of 12^33*34^23*2^47
2)for the above question which of the following will represent the sumof factors (such that only odd factors are counted)
(3^34-1)/2 * (17^24 -1)/16
(3^34-1)*(917^24-1)
(3^34-1)/2
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Thanks,
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Originally Posted by royy View Post
A number xy is multiplied by another number ab and the result comes as pqr ,where r=2y, q=2(x+y) and p=2r where p=2x where x,y pls give detailed solution
xy*ab=2x*2(x+y)*2y
because x,y
then
11.ab=242
Hence ab=22
Originally Posted by royy View Post
A number xy is multiplied by another number ab and the result comes as pqr ,where r=2y, q=2(x+y) and p=2r where p=2x where x,y pls give detailed solution
xy*ab=2x*2(x+y)*2y
because x,y
then
11.ab=242
Hence ab=22
if you assume x and y to be 2 then value of ab comes to be 24.... so
assumption might not be the right way.......
Originally Posted by royy View Post
A number xy is multiplied by another number ab and the result comes as pqr ,where r=2y, q=2(x+y) and p=2r where p=2x where x,y pls give detailed solution
xy*ab=2x*2(x+y)*2y
because x,y
then
11.ab=242
Hence ab=22
if you assume x and y to be 2 then value of ab comes to be 24.... so
assumption might not be the right way.......
x and y are two positive integers.then what will be the sum of the co-officients of the expansion of the expression (x+y)^44
Plz xplain
just considering simple case for power 1,2,3....
(x+y)^1sum=1=2^1
(x+y)^2sum=1=2^2
(x+y)^3sum=1=2^3
ans is 2^44.
I think i suck in QA. Help me with this question.
Arun sharma, page 69, chapter-2, q 23
If a man saves rs 4 more each year than he did the year before and if he saves rs 20 in the first year, after how many years will his savings be more than rs 1000 altogether.
I thot this is a simple AP question but am nt able to solve it and the answer is 19 year.
Can somebody please explain how to solve this one??????
I think i suck in QA. Help me with this question.
Arun sharma, page 69, chapter-2, q 23
If a man saves rs 4 more each year than he did the year before and if he saves rs 20 in the first year, after how many years will his savings be more than rs 1000 altogether.
I thot this is a simple AP question but am nt able to solve it and the answer is 19 year.
Can somebody please explain how to solve this one??????
well here a=20,d=4
so taking n=19 we get the total sum of 19 years as 1064 and taking n as 18 we get the total sum hence ans is 19
well here a=20,d=4
so taking n=19 we get the total sum of 19 years as 1064 and taking n as 18 we get the total sum hence ans is 19
this is a bottom-up approach but i was trying to solve it using top-down approach. Though i figured out how to do it bt m nt confident enuf
I think i suck in QA. Help me with this question.
Arun sharma, page 69, chapter-2, q 23
If a man saves rs 4 more each year than he did the year before and if he saves rs 20 in the first year, after how many years will his savings be more than rs 1000 altogether.
I thot this is a simple AP question but am nt able to solve it and the answer is 19 year.
Can somebody please explain how to solve this one??????
This problem can only be solved by hit and trial method in a quadratic equation.
we shall be using the series summation formula which goes like
S=n(2*a+(n-1)d)/2
1000=n(2*20+(n-1)*4)/2
upon simplifying this eqn we get
=>n^2+9n-500=0
Roots of this equation are not integers.
So think of two nos which have a sum of 9 and multiplication of >500 by hit and trial.
Two such nos are 28 and 19 whose multiplication is 532.
Fit these value in the eqn as follows:
=>n^2+28n-19n-532=0
=>n(n+28 )-19(n+28 )=0
=>n=-28 and 19
Therefore n=19 yrs is the correct answer
To check this furthur, put the value in summation formula
=>S=19(2*20+(19-1)*4)/2
=>S=19*(112/2)
=>S=19*56 =532
Hence #.
can any one explain me the solution for this??
its from progressions chapter:
one side of a staircase is to be closed in by a rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6,12,18 inches and so on.. there are 24 planks required in total. find the area in square feet.
pls expalin me the solution.
I think i suck in QA. Help me with this question.
Arun sharma, page 69, chapter-2, q 23
If a man saves rs 4 more each year than he did the year before and if he saves rs 20 in the first year, after how many years will his savings be more than rs 1000 altogether.
I thot this is a simple AP question but am nt able to solve it and the answer is 19 year.
Can somebody please explain how to solve this one??????
can any one explain me the solution for this??
its from progressions chapter:
one side of a staircase is to be closed in by a rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6,12,18 inches and so on.. there are 24 planks required in total. find the area in square feet.
pls expalin me the solution.
Can somebody please explain how to solve this one??????
can any one explain me the solution for this??
its from progressions chapter:
one side of a staircase is to be closed in by a rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6,12,18 inches and so on.. there are 24 planks required in total. find the area in square feet.
pls expalin me the solution.
karthick vs SaysCan somebody please explain how to solve this one??????
can any one explain me the solution for this??
its from progressions chapter:
one side of a staircase is to be closed in by a rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6,12,18 inches and so on.. there are 24 planks required in total. find the area in square feet.
pls expalin me the solution.
We have to find the answer in square feet. So first convert all the given dimensions into feets.
1 foot=12 inches => 1 inch= 1/12 feet
so
width of the planks=9/12 feet
heightof the planks= 1/2,1,3/2,.....
the heights is an increasing A.P with a=1/2 and d=1/2
Now the sum of heights of the wooden plank will be given by
=>24/2
=24*25/4
area of rectangle= height * width
here it will be => sum of heights of all planks * width
=>(24*25/4)* (9/12)
=112.5
can any one explain me the solution for this??
its from progressions chapter:
one side of a staircase is to be closed in by a rectangular planks from the floor to each step. the width of each plank is 9 inches and their height are successively 6,12,18 inches and so on.. there are 24 planks required in total. find the area in square feet.
pls expalin me the solution.
there are 24 rectangles overall on one side of staircase with dimensions of 9 inches width(of each rectangle) and length would 6,12,18...upto 24th terms.
so the area would --> 9*6 +12*6 +18*6+....+area of 24th rectangle
so applying A.P sum
6*24/2( 2*6+(24-1)6) ....{ n/2 * [2a + (n-1)d }
which comes out to be 16200 sq inches
in feets , we know 1 ft=12 inches
so ans in feets =16200/144=112.5 sq feets