Three variants of CAT paper are to be given to 12 students. In how any ways can the students be placed in 2 rows of 6 each so that there should be no identical variants side by side and that the student sitting behind should get the same variant. Find the number of ways it can be done.:neutral:
a) 6!^2 b) 6 x 6! x 6! c) 6!^3 d) 30 x (12 C 6) x 6! x 6!
can ne1 post the aproach for this qn?
Please help me solving the cubes question...Any foormula ,, any best approach...
The question goes like this :
There is a cube in which one pair of opposite faces is painted red , the second opposite faces is blue and the third pair of opposite faces is green .the cube is cut into 216 smaller but identical cubes
1. How many small cubes are there with no red paint at all
2. How many small cubes are there without any face painted
Please give me the detailed solution which should be self explainatory..
Thanks
Rahul Gupta 
Ganu02 SaysIs it none of these..'m getting 495...
at burger king- a famous fast food center on main street in Pune,burgers r made only on an automatic burger making machine.d machine conntinuously makes different sorts of burger by adding different sorts of filling. d machine makes burger at d rate of 1 burgers per half minute.the various fillings are added in d following manner. the 1st,5th,9th.... burgers r filled with chicken patty; d 2nd,9th,16th.... burgers with vegetable patty ; d 1st,5th,9th.... burgers with mashroom patty and the rest with plain cheese and tomato fillings.
d machine makes exactly 660 burgers per day
1) how many burgers per day are made with cheee n tomato fillings
a) 424
b) 236
c) 237
d) none of these
Please post answer for this one. I am getting 424. Is it right?
for 1,5,9,...660 which is in A.P. (ignoring the last term), there are 165 terms. For 2,9,16..660 which is A.P. there are exactly 95 terms. But 9,37,58...are repeating,which we need to subtract as they are added twice, which are 24 terms. =>165+95-24=236.
Therefore, total burgers with tomato filling is 660-236= 424.
Please help me solving the cubes question...Any foormula ,, any best approach...
The question goes like this :
There is a cube in which one pair of opposite faces is painted red , the second opposite faces is blue and the third pair of opposite faces is green .the cube is cut into 216 smaller but identical cubes
1. How many small cubes are there with no red paint at all
2. How many small cubes are there without any face painted
Please give me the detailed solution which should be self explainatory..
Thanks
Rahul Gupta
its
1.96
2.64
the highest power of 360 which divides 520! is
is it 128...
i hv askd d same question few days back dat what can b the highest power of 360 which divides 520! ... I dont hv d answer of dis question..dere is a hint given dat in dis case we need to check for the numbers 2^3(power) ,3^2 and 5....actually i hv a confusion in these type of questions coz dere is another question in which we have to find the highest power of 42 which divides 342!...in d solution hint of dis ques., it is written dat we need to check with 7 only nd ignore 3 and 2 coz their no. will b more than 7...i m just confuse y we dont ignore any digit in the first case?
the remainder of 51^203(power) when divided by 7 is 4..plz xplain?
dstubbornkanav Saysi hv askd d same question few days back dat what can b the highest power of 360 which divides 520! ... I dont hv d answer of dis question..dere is a hint given dat in dis case we need to check for the numbers 2^3(power) ,3^2 and 5....actually i hv a confusion in these type of questions coz dere is another question in which we have to find the highest power of 42 which divides 342!...in d solution hint of dis ques., it is written dat we need to check with 7 only nd ignore 3 and 2 coz their no. will b more than 7...i m just confuse y we dont ignore any digit in the first case?
buddy dont confuse urself too much, just understand the concept and not the solution... In these types of problem u shd be looking to find the prime factors which has least power...
Understand that highest prime factor is not necessarily the deciding factor...
dstubbornkanav Saysthe remainder of 51^203(power) when divided by 7 is 4..plz xplain?
51^203/7
=>2^203
=>2^2 x (2^3)^67/7
=>4x1
=>4
Please help me solving the cubes question...Any foormula ,, any best approach...
The question goes like this :
There is a cube in which one pair of opposite faces is painted red , the second opposite faces is blue and the third pair of opposite faces is green .the cube is cut into 216 smaller but identical cubes
1. How many small cubes are there with no red paint at all
2. How many small cubes are there without any face painted
Please give me the detailed solution which should be self explainatory..
Thanks
Rahul Gupta
1)cubes with red=>36+36(opposite side)=>72
=>216-72
=>144
2)no face painted => 4x4x4=>64
For concepts regarding cubes refer to this thread
http://www.pagalguy.com/forum/quantitative-questions-and-answers/55747-cat-2010-concepts-fundas-tips.html#post2192733Three variants of CAT paper are to be given to 12 students. In how any ways can the students be placed in 2 rows of 6 each so that there should be no identical variants side by side and that the student sitting behind should get the same variant. Find the number of ways it can be done.:neutral:
a) 6!^2 b) 6 x 6! x 6! c) 6!^3 d) 30 x (12 C 6) x 6! x 6!
can ne1 post the aproach for this qn?
First arrange the 6 in first row 12c6
six can arrange themselves in 6! and people in second row in 6! ways..so 12c6x6!x6!,and distribution in 30 ways so its 30 x (12 C 6) x 6! x 6!
1)cubes with red=>36+36(opposite side)=>72
=>216-72
=>144
2)no face painted => 4x4x4=>64
for the first one is it not 96...The question to find out cube with red color..So the cubes in the edges of blue and green will also have red color in them...
144-48===>96....Is it wrong????
for the first one is it not 96...The question to find out cube with red color..So the cubes in the edges of blue and green will also have red color in them...
144-48===>96....Is it wrong????
buddy the question is cube with no red color!
Please help me solving the cubes question...Any foormula ,, any best approach...
The question goes like this :
There is a cube in which one pair of opposite faces is painted red , the second opposite faces is blue and the third pair of opposite faces is green .the cube is cut into 216 smaller but identical cubes
1. How many small cubes are there with no red paint at all
2. How many small cubes are there without any face painted
Please give me the detailed solution which should be self explainatory..
Thanks
Rahul Gupta
EagleMenace Saysbuddy the question is cube with no red color!
ya bro the edges will be of red color na...
Ganu02 Saysya bro the edges will be of red color na...
buddy dont try to count the red cubes individually ... U know that 2 faces are painted red.. Just eliminate the faces with cube painted red u will get 36+36=72..
hi can some1 plz explain numbersystem LOD 3 where we need to find remainder of a number which has power of power...Ex- 50^(51^52) divided by 11
yes the ans is 424
hi this que can be solved as
first take 51^52 mod 11 =1 (1^2 divided by 11 leaves remainder 1)
now we come to 50^1
50 -44 =6
the number of positive integers not greater than 100 , which are not divisible by 2 or 3 or 5 is
a)24 b)25 C)31 D)28 e)26
hey how did u calculate the intersection between 2 aps plss tell me
hey can u plz explain in detail.. i din get it? how did we get 51^52mod11 = 1
2^2+22^2+222^2+....22...49two.s^2, whn divided by 9..what is remainder...2,8,7,6.,.plz suggest a good approach
priyamvada_89 Saysyes the ans is 424
hi this que can be solved as
first take 51^52 mod 11 =1 (1^2 divided by 11 leaves remainder 1)
now we come to 50^1
50 -44 =6
the number of positive integers not greater than 100 , which are not divisible by 2 or 3 or 5 is
a)24 b)25 C)31 D)28 e)26
priyamvada_89 Sayshey how did u calculate the intersection between 2 aps plss tell me
Buddy calm down u need not make so many posts.. Just put altogether in a single post...
no divisible by 2 = 50
no`s divisible by 3 => 99-3/3=>33+1=>34
no`s divisible by 5=>100-5/5=>19+1=>20
similarly find for 6,15, 10 and 30
u would get 16, 6, 10, 3
All ur doing is
(2U3u5)=n(2)+n(3)+n(5)-n(6)-n(15)-n(10)+n(30)
=>100-50-34-20+16+6+10-3
=>25
And I believe the question shd be nos divisible by 2,3 and 5 if its not divisible then answer shd be 100-25=>75
Rohit draw a rectangular grid of 529 cells arranged in 23 rows nd 23 columns and filled each cell with a number.the nos with which he filled each cell were such that nos of each row taken from left to right formed an arithmetic series and nos of each column taken from top to bottom also formed arithmetic series . 7 and 17 th nos of 5th row were 47 nd 63 respectively.while 7 nd 17 nos of 15 th row were 53 and 77 respectively.what is sum of all nos in grid?
a.32798 b.65596c.52900d.none of these
ans=a