divyaakanksha Sayshow did u get 5/2 * (25 % 10x)?
I meant (5/2x) is 25% of 10x
As the profit = 25%
I meant (5/2x) is 25% of 10x
As the profit = 25%
divyaakanksha Sayshow did u get 5/2 * (25 % 10x)?
try this since the milkman sold it at 25% profit then the actual cost of the mixture would be
5X/4=10 =>x=8
now according to the allegation rule we have
10(CP of milk) 0(cost of water)
8(actual selling prise of the mixture)
8(8-0) 2(10-8 )
hence the ratio is M:W=8:2=4:1
already given water is 5 L
so the milk will be 4*5=20
so the total mixture =20+5=25
1. a dishonest milkman purchased milk at rs 10 /litre and mixed 5 litre of water in it. By selling the mixture at the rate of Rs 10/l he earns a profit of 25%. The quantity of amount of mixture that he had was?
a. 15l
b 20 l
c. 25 l
d. 30 l
e. none
I want to know how to solve this by using equations as I am able to solve it through options
When 25% amount is 5 litres..Then 100% will be 20 litres...So totally 25 litres..
divyaakanksha Sayshow did u get 5/2 * (25 % 10x)?
He makes profit of 25% on 10x
so 25/100*10x = 5x/2
the rest part is solved by akshay.
answer is 25L..! 😃
Time & Work, lod2:
Mini and vinay are quiz masters preparing for a quiz. in x minutes, Mini makes y questions more than vinay. If it were possible to reduce the time needed by each to make a question by two minutes, then in x minutes Mini would make 2y questions more than vinay. How many questions does Mini make in x minutes?
a) 1/4
b) 1/4
c) either a or b
d)1/4
e) none of these
thanks in advance.
Find the remainder 28!/62 and give detailed explanation or logic involed.
kumarmayank SaysFind the remainder 28!/62 and give detailed explanation or logic involed.
62=31x2
so find the remainder first with 31.
=>28!/31
wkt (p-2)!/p=1
=>(31-2)/31=1
=>29!/31=1
=>28!x29/31=1
=>29
28!/2=0
=> number which gives remainder 0 with 2 and 29 with 31.. So remainder shd be 60...
62=31x2
so find the remainder first with 31.
=>28!/31
wkt (p-2)!/p=1
=>(31-2)/31=1
=>29!/31=1
=>28!x29/31=1
=>29
28!/2=0
=> number which gives remainder 0 with 2 and 29 with 31.. So remainder shd be 60...
can you please explain the bold part..i think it's multiply,so 29 should come,it's not necessary....and please pardon my ignorance if i am wrong
62=31x2
so find the remainder first with 31.
=>28!/31
wkt (p-2)!/p=1
=>(31-2)/31=1
=>29!/31=1
=>28!x29/31=1
=>29
28!/2=0
=> number which gives remainder 0 with 2 and 29 with 31.. So remainder shd be 60...
boss 28! 15 remainder dega 31 ke saath.... plz recheck!!!
=>28!x29/31=1... yeh step galt hai!!!
rahicecream Sayscan you please explain the bold part..i think it's multiply,so 29 should come,it's not necessary....and please pardon my ignorance if i am wrong
Pasting same thing
62 = 31*2
28! = 0 mod2 (1)
Using Wilson' theorem,
29! = 1 mod31 I hope this part is Oakey with you.
=> 29*28! = 1 mod31
=> -2*28! = -30 mod31 = -2*15 mod31
=> 28! = 15 mod31.
(2)Combining (1) and (2) using Chinese Remainder Theorem, we have
28! = 46 mod62.
boss 28! 15 remainder dega 31 ke saath.... plz recheck!!!
=>28!x29/31=1... yeh step galt hai!!!
Pasting same thing
62 = 31*2
28! = 0 mod2 (1)
Using Wilson' theorem,
29! = 1 mod31 I hope this part is Oakey with you.
=> 29*28! = 1 mod31
=> -2*28! = -30 mod31 = -2*15 mod31
=> 28! = 15 mod31.:) (2)
Combining (1) and (2) using Chinese Remainder Theorem, we have
28! = 46 mod62.
Obsolutely my bad
Pasting same thing
62 = 31*2
28! = 0 mod2 (1)
Using Wilson' theorem,
29! = 1 mod31 I hope this part is Oakey with you.
=> 29*28! = 1 mod31
=> -2*28! = -30 mod31 = -2*15 mod31
=> 28! = 15 mod31.:) (2)
Combining (1) and (2) using Chinese Remainder Theorem, we have
28! = 46 mod62.
Boss what's this Chinese theoram all about ????
Ques. no. 6 ( I AM NOT ABLE TO DRAW FIGURE PROPERLY PLZ HELP. ANSWER IS BELOW)
Shyam's house, his office and his gym are equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting hos office and his house and stops when he reaches a point directly east of his office. He then reverses his direction and walks till he reaches a point directly south of his office. The total distance walked by Shyam is
(a) 6 Km
(b) 9 Km
(c) 16 Km
(d) 12 Km
(e) 8 Km
Ok here it is
Help me out with this question
Circles are drawn with four vertices as the centers and radius equal to the side of a square . If the square is formed by joining the mid points of another square of side 2*root(6) , find the area common to all four circles .
GOt this from arun sharma Mensuration LOD -II
which one is greater in terms of percentage ?
150/412, 137/406, 160/449, 68/436, 180/457
any shortcut method????????????????
These are some of my difficulties from chapter No. System.They may have been discussed earlier but I could not find them. All ques are from LOD II.
20. gives remainder and {.} denotes fractional part of that. The fractional part is of the form (0.bx). The value of x could be
OP: a. 2 b. 4 c. 6 d. 8 e. None of these
25. The expression (333^555) + (555^333) is divisible by
Op: a. 2 b. 3 c. 37 d. 11 e. All of these
(I am getting all of these bt ans given is 11)
39. Find the smallest no. n such that n! is divisible by 990.
OP: a. 3 b. 5 c. 11 d. 12 e. None of these
(My ans. 11 ; Given ans. None of these)
64. Find the 28383rd term of series 123456789101112........
OP: a. 3 b. 4 c. 9 d. 7
(Gettin 7 bt not correct)
77. (12^33) * (34^23) * (2^47) Find the sum of odd factors.
Please explain the approach for this....I waste quite
a time to solve these type of ques. Ans: ((3^34-1)/2) * ((17^24-1)/16)
Find last two digits of follwing nos.
1. 101*102*103*197*198*199 : Getting 64 (even tried calci.); given ans 54
2. 65*29*37*63*71*87*62 : Any shortcuts for solving que
Find the remainder when
1. 7^99 divides 2400 (getting no clue whatsoever)
2. (10^3 + 9^3)^752 is divided by 12^3
Will post LOD III difficulties once these are addressed and if still I could not solve them.
If these ques are earlier discussed I am really sorry guys but I am new in PG world.....Thank you
plz solve
it takes six days for three women and two men working together to complete a work. Three men would do the same work five days sooner than nine women. How many times does the output of a man exceeds that of a women?
a. 3 times
b. 4 times
c. 5 times
d. 6 times
e. 7 times
plz solve
it takes six days for three women and two men working together to complete a work. Three men would do the same work five days sooner than nine women. How many times does the output of a man exceeds that of a women?
a. 3 times
b. 4 times
c. 5 times
d. 6 times
e. 7 times
let x be work done by men and y be work done by women
6(2x+3y)=100---1
if 5(3x)=100 =>3x=20
=>10(9y)=100=>9y=10
3x+9y=30---------2
solve them
u get 6 times...
let x be work done by men and y be work done by women
6(2x+3y)=100---1
if 5(3x)=100 =>3x=20
=>10(9y)=100=>9y=10
3x+9y=30---------2
solve them
u get 6 times...
how did u get 5(3x) and 10(9y) . I didnt get the logic of taking 5 and 10. plz explain
divyaakanksha Sayshow did u get 5(3x) and 10(9y) . I didnt get the logic of taking 5 and 10. plz explain
I took 5(3x) and 10(9y) because if 3x complete the work in 5 days, then 9y would complete the work 10 days... U can take any value but staisfying that condition..