MY PROBLEM IN CHAPTER PROGRESSION..
LOD-2 QUESTION14 AFTER STRIKING THE FLOOR REBOUNDS TO4/5 OF ITS HIEGHT FROM WHICH IT HAS FALLEN.FIND THE TOTAL NUMBER OF DISTANCE THAT IT TRAVELS BEFORE COMING TO REST IF IT HAS BEEN GENTLY DROPPED FROM THE HIEGHT OF 120m. options a)540 b)960 c)1080 d)1020 e)1120.. ans.(c).............. LOD-2 QUESTION41 how many three digit numbers have property that thier digit taken from left to write form an arithmetic or geometric progression? a)15 b)18 c)20 d) none of these.....ans(b). LOD-3 QUESTION16find the sum of of the series 1.2+2.2^2+3.2^3+.....100.2^100? option a)100.2^101+2 b)99.2^100+2 c)99.2^101+2 d)100.2^100+2 e)none of these .............. LOD-3 QUESTION26 one side of the staircase is to be clsed by rectangular plancks from the floor to each step.the width of each planck is 9inches and their ht are successively 6inches,12 inches,18 inches and so on.there are 24 planks in total.find the area in square feet. a)112.5 b)107 c)118.5 d)105 e)none of these.....ans(a)LOD-3QUESTION32 in a certain colony of cancerous cell,each cell reproduce by giving birth to new cells each hour.if ther is single productive cell at the start and this process continues for 9 hours,how many cell will the colony have at the end of 9 hrs?if it is known that life of an individual cell is 20hrand only 50% of cells are capable enough of producing next generation cells? a)2^9-1 b)2^10 c)2^9 d)2^10-1 e)2^11-1...ans(c) puys pls check out problem in CHAPTER AVERAGE PAGE110 QUESTION36-39 AND PROBLEM 40-49 ON PAGE 112 these are long statement question pls give the solution..... now my problems in chapter percentages LOD-3 PAGE-159 QUESTION6 in an election of 3 candidates A,b Aand C,A GETS 50% more votes than B.A also beats c by 18000 votes.if it is known that b gets 5 perentage point more votes than c,find the number of voters on the voting list(90% of the voters on the voting list voted and no votes were illegal) a)72000 b)81000 c)90000 d)100000 e)110000 ans(d) problems in chapter INTEREST LOD-1PAGE 212 QUESTION40.a sum of money placed at compound interest doubles itself in the 3 yrs.in how many yrs will it amount to 8 times? a)9yrs b)8yrs c)27yrs d)7yrs .ans(a)
hello,I have got a problem from Profit Loss
Mr X goes to buy fruits and after a lot of bargaining he is able to get the price of a dozen apples reduced by Re 1 from the initial price,thereby enabling him to get 1 apple extra, for every rupee saved.(getting no discount on the extra apple).What is the initial price of a dozen apples?
a)10 b)13 c)12 d)15
somebody help plz!!!
my doubts:
lod1-
Q72. a test has 80 questions. there is 1 mark for correct answer, while there is -ve penalty of -0.5 for a wrong answer and -0.25 for an unattempted question. what is the nos. of questions answered correctly if the student has a score of 34.5 marks.
a)45 b)48 c)54 d)cannot b determined
lod 2-
Q61. define a nos K such dat sum of the squares of first M natural nos. where MQ64. find the 28383rd term of series 123456789101112...
a)3 b)4 c)9 d)7
Q65. if you form a subset of integers chosen from between 1 to 3000 such that no integers add upto a multiple of nine, wat can b d max. nos. of elements in the subset?
a)1668 b)1332 c)1333 d)1334
Q67. K is a 3 digit nos. such that the ratio of the number to the sum of its digits is least . what is the difference between hundreds and tens digits of K?
a)9 b)8 c)7 d)none
Q88. Arun, Bikash n Chetakar have a total of 80 coins among them. arun triples the number of coins with the others by giving them some coins from his own collection. next, bikash repeats the same process. after this bikash has 20 coins. find nos of coins he had at the beginning.
a)11 b)10 c)9 d)12
Q85. find the last two digits of (201*202*203*204*246*247*248*249)^2
a)36 b)56 c)76 d)16
MY HUMBLE REQUEST IS THAT PLZZZ SHOW THE PROCEDURE AS ANSWERS ARE ALSO KNOWN TO ME.... THANX A LOT IN ADVANCE..
find the 28383rd term of series 123456789101112...
a)3 b)4 c)9 d)7...
1-9 ==> 9
10-99 ==> 180
100-999 ==> 2700
1000-6999=>24000
7000-7299=> 1200
7300-7369=> 280
total ==>28369
so another 14 digits...
7370,7371,7372=12 digits
So 3 is the 28383rd digit...
a)3 b)4 c)9 d)7...
1-9 ==> 9
10-99 ==> 180
100-999 ==> 2700
1000-6999=>24000
7000-7299=> 1200
7300-7369=> 280
total ==>28369
so another 14 digits...
7370,7371,7372=12 digits
So 3 is the 28383rd digit...
my doubts:
lod1-
Q72. a test has 80 questions. there is 1 mark for correct answer, while there is -ve penalty of -0.5 for a wrong answer and -0.25 for an unattempted question. what is the nos. of questions answered correctly if the student has a score of 34.5 marks.
a)45 b)48 c)54 d)cannot b determined
lod 2-
Q61. define a nos K such dat sum of the squares of first M natural nos. where MQ64. find the 28383rd term of series 123456789101112...
a)3 b)4 c)9 d)7
Q65. if you form a subset of integers chosen from between 1 to 3000 such that no integers add upto a multiple of nine, wat can b d max. nos. of elements in the subset?
a)1668 b)1332 c)1333 d)1334
Q67. K is a 3 digit nos. such that the ratio of the number to the sum of its digits is least . what is the difference between hundreds and tens digits of K?
a)9 b)8 c)7 d)none
Q88. Arun, Bikash n Chetakar have a total of 80 coins among them. arun triples the number of coins with the others by giving them some coins from his own collection. next, bikash repeats the same process. after this bikash has 20 coins. find nos of coins he had at the beginning.
a)11 b)10 c)9 d)12
Q85. find the last two digits of (201*202*203*204*246*247*248*249)^2
a)36 b)56 c)76 d)16
MY HUMBLE REQUEST IS THAT PLZZZ SHOW THE PROCEDURE AS ANSWERS ARE ALSO KNOWN TO ME.... THANX A LOT IN ADVANCE..
Hey...
q1. U can do it using options.48 is the answer.
48 correct, 10 unattempted.22 wrong.
Also, u can cancel a few options 54 is not possible.
q64) 28383rd number is 3. brute force method buddy....
keep adding 9+180+2700+.... 6374 is the number , 3 comes in 28383rd position.
q67) Answer should be 8. 199/19 keeps the ratio minimum.
q85) answer is 76. This problem does not require any special method.
use normal remainder theorem. u wil get the answer in less than 3 mins.
find the 28383rd term of series 123456789101112...
a)3 b)4 c)9 d)7...
1-9 ==> 9
10-99 ==> 180
100-999 ==> 2700
1000-6999=>24000
7000-7299=> 1200
7300-7369=> 280
total ==>28369
so another 14 digits...
7370,7371,7372=12 digits
So 3 is the 28383rd digit...
A test has 80 questions. there is 1 mark for correct answer, while there is -ve penalty of -0.5 for a wrong answer and -0.25 for an unattempted question. what is the nos. of questions answered correctly if the student has a score of 34.5 marks.
a)45 b)48 c)54 d)cannot b determined
take it in equation as x-0.75y=34.5
another equation is x+y=80
solve these two equations...answer is 54....
I dont think we can use it like this.
For example if all questions except 54 were right then, 26 wrong u wil get -13 marks. not 0.75*26=18.5 marks.
Arun sharma time speed distance lod 2 question number 14...
Thanks in advance
Please help with this question of LOD2 Number system:
M is a two digit number which has the property that:
The product of factorial of its digits > sum of factorialsof it's digits.
How many values of M exists?
a. 56
b. 64
c. 63
d. None of these
Please help me how to solve this.
Thanks in advance
Arun sharma time speed distance lod 2 question number 14...
Thanks in advance
Do post the question....Many over here who doesn't have books can also solve it...
For the Q.92 on Page 47 of Arun Sharma (Quant)
How come I have a deviation here... :(
14(7!) + 14(13!)
---------------------
2(8!) - 21(6!)
which gives
7!(14+13x)
---------------
7!(16-3)
which in turn gives
(13+1)+13x
----------------
13
whose remainder would be 1.
Please correct me...
hello,I have got a problem from Profit Loss
Mr X goes to buy fruits and after a lot of bargaining he is able to get the price of a dozen apples reduced by Re 1 from the initial price,thereby enabling him to get 1 apple extra, for every rupee saved.(getting no discount on the extra apple).What is the initial price of a dozen apples?
a)10 b)13 c)12 d)15
the answer is 12,since now he gets 1 dozen of apple for 11 rs,n initial price was rs12,he have 1 more ruppee to buy one more apple,since there is no discount given
Arun sharma time speed distance lod 2 question number 14...
Thanks in advance
answer is 6km/hr,u can get answer by using the fact that the time is inversely proportional to speed, so the time equation we get according to question is T/9=8/T+6,where Tis the time taken by rider A to reach meeting point,by solving this equation we get T=6.now using the statement that B traveled 12km more than A,so we have equation 12B-6A+12,A and B are speed of riders.now speed of A is 3/2 times of B,SO BY PUTTING IN ABOVE EQUATION YOU WILL GET THE ANSWER A=6KM/HR N B+4KM/HR
I dont think we can use it like this.
For example if all questions except 54 were right then, 26 wrong u wil get -13 marks. not 0.75*26=18.5 marks.
i think the answer will be 48
check out,the 2digits numbers that doesnt show this property are-- 10-20,30,40,50,60,70,80,90,21,31,41,51,61,71,81,91 and 22,so total number of digit are 27.now the number of digits shows property given in question will be 90-27=63.so answer is option c
hey m also using this book... but m not able to solve some of them.. and also keys for all questions are not given.. wat to do !!!
-nilesh
Please help with this question of LOD2 Number system:
M is a two digit number which has the property that:
The product of factorial of its digits > sum of factorialsof it's digits.
How many values of M exists?
a. 56
b. 64
c. 63
d. None of these
Please help me how to solve this.
Thanks in advance
the two digits number that doesnt show the property given in the question are-10,11,12,13,14,15,16,17,18,19,20,30,40,50,60,70,80,90,,21,31,41,51,61,71,81,91,and 22(i think most of you are missin this number) total number of above digits=27,so the answer is 90-27=63
LOD2 QUESTION 62:
M is a two digit number which has the property that:the product of factorial of its digit>sum of factorial of its digits.how many values of M exists? option A)56 B)64 C)63 D)none of these.........ans-(c)
Let the two digit number be ab. Therefore a!*b! > a!+b!
=> a!*b!-b! > a! => b!*(a!-1) > a! => b! > a!/(a!-1)
a & b are integers where a can have value in the range of 1 to 9 (tens place of two digit number so cannot have a value 0) and b in the range of 0 to 9
now look at R.H.S.:-
1) Denominator cannot be equal to zero hence a!-1 > 0 i.e. a!>1 i.e a >= 2
hence a can have any of the 8 values from 2 to 9
2) It represents a fraction whose numerator and denominator are successive numbers. So the values of fraction will always be less than 2 i.e. a!/(a!-1) So except for b = 0 or 1 all values of B satisfy the equation i.e. b can have any of the 8 values form 2 to 9
Hence the no of such 2 digit numbers = 8*8 = 64.
I cant think of any other combination thats possible. So no idea why the given answer is 63?
LOD2 QUESTION 66:
The series of numbers(1,1/2,1/3.....1/1972)is taken.now two number taken from this series(the first two)say x,y.then the operation x+y+xy is performed to get consolidated number.the process is repeated.what will be the value of set after all the numbers are consolidated into one number. OPTIONS A)1970 B)1971 C)1972 D)none of these............................ans(c)
given formula id x+y+xy. Let us select the first two numbers from the series: x =1 & y=1/2
hence x+y+xy = 1+1/2+1/2 = 2
Thus 2 will replace 1, 1/2 in the series. Noe let x = 2 and y = 1/3 (next number in series)
hence x+y+xy = 2+1/3+2/3 = 3
If we continue we see that each time the eq. x+y+xy yields a vale equal to the Denominator of the fraction replaced. Thus the answer is (c) 1972
LOD-2 NUMBER SYSTEM PROBLEM 92:
what is remainder when 2(8!)-21(6!) divides 14(7!)+14(13!)? options a)1 b)7! c)8! d)9!.....ans(b).................
/
=> 14*7!*(1+13*12*11*10*9*8 )/
=> 14*7*(14+13*12*11*10*9*8 )/
=> 14*(14 + 13*12*11*10*9*8 )/
=> 14*(14 + 13*12*11*10*9*8 )/13
=> 1*(1+0)/13 ......using reminder theorem
=> reminder = option (a) 1
LOD2 NUMBER SYSTEM PROBLEM 93
how many integer values of x and y are such that 4x+7y=3,when modulus of x
x and y are integers such that x |x x x > -500)
thus -500 similarly -500 If we look at the equation 4x+7y = 3 we can easily come up with the values x = 6 and y = -3 that satisfies the equation.
Here is a very important property if we have one set of value (x1,y1) that satisfies equation ax+by = c then we can find other values as follows
x2 = x1+b ---------------- y2 = y1-a
x3 = x2+b ---------------- y3 = y2-a....
xn = xn-1 + b ---------------- yn = yn-1 - a
Similarly following values will also satisfy the equation:
x2 = x1-b ---------------- y2 = y1+a
x3 = x2-b ---------------- y3 = y2+a....
In short increase the values of x by the coefficient of y in the eq. (i.e. b) and decrease the value of y by coefficient of x ( i.e. a)
OR
decrease the values of x by the coefficient of y in the eq. (i.e. b) and increase the value of y by coefficient of x ( i.e. a)
thus using this we can say that values of x that will satisfy the eq. will be
( .....-8,-1,6,13.... ) and corresponding values of y satisfying the eq. will be (.....5,1,-3,-7,-11...)
The end values will be -500 to 500
Both of them form an AP series so. thus using number of terms equation for AP the answer can be found which comes out as d) 142
Let the two digit number be ab. Therefore a!*b! > a!+b!
=> a!*b!-b! > a! => b!*(a!-1) > a! => b! > a!/(a!-1)
a & b are integers where a can have value in the range of 1 to 9 (tens place of two digit number so cannot have a value 0) and b in the range of 0 to 9
now look at R.H.S.:-
1) Denominator cannot be equal to zero hence a!-1 > 0 i.e. a!>1 i.e a >= 2
hence a can have any of the 8 values from 2 to 9
2) It represents a fraction whose numerator and denominator are successive numbers. So the values of fraction will always be less than 2 i.e. a!/(a!-1) So except for b = 0 or 1 all values of B satisfy the equation i.e. b can have any of the 8 values form 2 to 9
Hence the no of such 2 digit numbers = 8*8 = 64.
I cant think of any other combination thats possible. So no idea why the given answer is 63?
given formula id x+y+xy. Let us select the first two numbers from the series: x =1 & y=1/2
hence x+y+xy = 1+1/2+1/2 = 2
Thus 2 will replace 1, 1/2 in the series. Noe let x = 2 and y = 1/3 (next number in series)
hence x+y+xy = 2+1/3+2/3 = 3
If we continue we see that each time the eq. x+y+xy yields a vale equal to the Denominator of the fraction replaced. Thus the answer is (c) 1972
/
=> 14*7!*(1+13*12*11*10*9*8 )/
=> 14*7*(14+13*12*11*10*9*8 )/
=> 14*(14 + 13*12*11*10*9*8 )/
=> 14*(14 + 13*12*11*10*9*8 )/13
=> 1*(1+0)/13 ......using reminder theorem
=> reminder = option (a) 1
x and y are integers such that x |x x x > -500)
thus -500 similarly -500 If we look at the equation 4x+7y = 3 we can easily come up with the values x = 6 and y = -3 that satisfies the equation.
Here is a very important property if we have one set of value (x1,y1) that satisfies equation ax+by = c then we can find other values as follows
x2 = x1+b ---------------- y2 = y1-a
x3 = x2+b ---------------- y3 = y2-a....
xn = xn-1 + b ---------------- yn = yn-1 - a
Similarly following values will also satisfy the equation:
x2 = x1-b ---------------- y2 = y1+a
x3 = x2-b ---------------- y3 = y2+a....
In short increase the values of x by the coefficient of y in the eq. (i.e. b) and decrease the value of y by coefficient of x ( i.e. a)
OR
decrease the values of x by the coefficient of y in the eq. (i.e. b) and increase the value of y by coefficient of x ( i.e. a)
thus using this we can say that values of x that will satisfy the eq. will be
( .....-8,-1,6,13.... ) and corresponding values of y satisfying the eq. will be (.....5,1,-3,-7,-11...)
The end values will be -500 to 500
Both of them form an AP series so. thus using number of terms equation for AP the answer can be found which comes out as d) 142
your procedure is correct but answer is 143,n thanks for yours very useful post
Thank you Dark Knight
pooh23 SaysThank you Dark Knight
Please avoid spamming. It just makes the thread bigger and unreadable. Use the thanks button given at the bottom right of the post to thank someone.
Regards,
Abhishek